Unit 5: Thermo (Packets 1 & 2)

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15 Terms

1
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Exo or Endo: Bond formation

Exothermic

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Exo or Endo: Bond breakage

Endothermic

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Bond Energy

Amount of energy required to break a covalent bond

<p>Amount of energy required to break a covalent bond</p>
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<p>To solve this equation:</p>

To solve this equation:

1: Balance stoichiometric equation.

2: Draw Lewis Dot Structure for all reactants and products.

3: Substitute correct bonds into equation and apply mole ratio, e.g.

  • ΔH = 4(C-H) + 2(O=O) - 2(C=O) - 4(O-H)

4: Substitute correct numerical values into equation.

  • ΔH = 4(393) + 2(433) - 2(433) - 4(464)

  • Bond energies found in DP data booklet

5: Solve the equation.

  • ΔH = -890 kJ

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Hess’ Law

The enthalpy change for a reaction is independent of the pathway between the initial and final states.

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Standard Enthalpy Change of Combustion

Amount of heat released from 1 mol of a substance in the presence of oxygen.

  • C3H8 + 5O2 —> 3CO2 + 4H2O

  • ΔH: Need to use ΔHformation to find ΔHcombustion

<p>Amount of heat released from 1 mol of a substance in the presence of oxygen.</p><ul><li><p>C<sub>3</sub>H<sub>8</sub> + 5O<sub>2</sub> —&gt; 3CO<sub>2</sub> + 4H<sub>2</sub>O</p></li><li><p>ΔH: Need to use ΔH<sub>formation</sub> to find ΔH<sub>combustion</sub></p></li></ul><p></p>
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Standard Enthalpy Change of Formation

Amount of heat needed to make (released) from the formation of 1 mol of a compound from its elements in standard state.

  • Does not apply to diatomic and metals (they aren’t compounds)

  • 0 for elements at standard state

  • Standard state = state the element exists as at 25 ºC (298.15 K) and 1 atm (101 kPa)

  • CANNOT USE COMBUSTION VALUES FOR FINDING ΔH OF A COMBUSTION REACTION

<p>Amount of heat needed to make (released) from the formation of 1 mol of a compound from its elements in standard state.</p><ul><li><p>Does not apply to diatomic and metals (they aren’t compounds)</p></li><li><p>0 for elements at standard state</p></li><li><p>Standard state = state the element exists as at 25 ºC (298.15 K) and 1 atm (101 kPa)</p></li><li><p>CANNOT USE COMBUSTION VALUES FOR FINDING ΔH OF A COMBUSTION REACTION</p></li></ul><p></p>
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ΔHformation vs ΔHBE

  • ΔHformation: Uses standard states and not gas volumes —> accurate

  • ΔHBE: Averages of bond energies in gaseous phase and are used as a guide —> approximate

  • ALWAYS A QUESTION ON IB EXAM

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Born-Haber Cycle

BHC is an application of Hess’ Law used to show energy changes in the formation of an ionic compound.

<p>BHC is an application of Hess’ Law used to show energy changes in the formation of an ionic compound.</p>
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Lattice Enthalpy

Energy required to make gaseous ions from 1 mol of solid ionic compound.

  • Endothermic

  • Experimental values at 298K are found in section 18 of data booklet

  • ΔHºlat > 0

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Enthalpy of atomization / sublimation

Standard enthalpy change that occurs on the formation of 1 mol of separate gaseous atoms of an element in its standard state.

  • M(s) —> M(g) ΔHºatom > 0 Sublimation

  • ½ X2 (g) —> X(g) ΔHºatom > 0 BE

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Ionization Energy (ΔHºIE)

Standard enthalpy change that occurs on the removal of 1 mol of e- from 1 mol of atoms or positively charged ions in the gaseous phase.

  • For metal ions with multiple ve- the 1st, 2nd and 3rd IEs are defined.

  • M(g) —> M+(g) + e- ΔHºIE > 0

  • M+(g) —> M2+(g) + e- ΔHºIE > 0

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Electron Affinity (ΔHºEA)

The standard enthalpy change on the addition of 1 mol of e- to 1 mol of atoms in the gaseous phase.

  • X(g) + e- —> X-(g) ΔHºEA < 0

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Lattice Enthalpy Steps

1: ΔHformation (-ΔH (heat released))

2: ΔHatomisation / sublimation (↑ +ΔH)

3: IE1 (↑ +ΔH)

4: ½ ΔHBE (↑ +ΔH)

5: EA (↓ -ΔH)

ΔHlattice = ΔHatom + IEcation + ½ ΔHBE + EAanion - ΔHf

<p>1: ΔH<sub>formation</sub>  (<span>↓ </span>-ΔH (heat released))</p><p>2: ΔH<sub>atomisation / sublimation </sub> (<span>↑ +</span>ΔH)</p><p>3: IE<sub>1 </sub> (↑ +ΔH)</p><p>4: ½ ΔH<sub>BE  </sub>(↑ +ΔH)</p><p>5: EA  (↓ -ΔH)</p><p></p><p>ΔH<sub>lattice</sub> = ΔH<sub>atom</sub> + IE<sub>cation</sub> + ½ ΔH<sub>BE</sub> + EA<sub>anion</sub> - ΔH<sub>f</sub></p>
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