5.1.3 - acids, bases and buffers

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26 Terms

1
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what is a brønsted-lowry acid

a species that donates a proton

2
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what is a brønsted-lowry base

a species that accepts a proton

3
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what is a conjugate acid-base pair

two species which differ by H+

4
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what is a monobasic acid

release 1 H+ ion per molecule

5
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what is a dibasic acid

releases 2 H+ ions per molecule

6
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what is a tribasic acid

releases 3 H+ ions per molecule

7
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what did lavoisier discover

that oxygen was responsible for combustion

8
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what was lavoisier’s theory about acids

all acids contain oxygen

9
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what was arrhenius’ theory

-acids donate protons and bases release hydroxide ions

-when an acid and base reacts they form salt and water

10
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brønsted and lowry suggested that when we mix acids and water ____ ions are released

H+

11
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brønsted and lowry suggested that when we mix bases and water ____ ions are released

OH-

12
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what is the expression for Kw

Kw = [H+][OH-]

13
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what can we simplify Kw to when referring to pure water and why

Kw = [H+]²

-pure water has an equal concentration of H+ and OH- ions

14
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what is the value of Kw at 250

1\times10^{-14}

15
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what is the equation for working out pH

pH = -log[H+]

16
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what is the equation for working out [H+] if we are given pH

10^{-pH}

17
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for strong acids what do we assume

we assume that the concentration of the acid is equal to the concentration of H+ ions because it fully dissociates

18
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for strong bases what do we assume

we assume that the concentration of the base is equal to the concentration of H+ ions because it fully dissociates

19
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how do we work out [H+] when we have Kw and [OH-]

\left\lbrack H^{+}\right\rbrack=\frac{K_{w}}{\left\lbrack OH^{-}\right\rbrack}

20
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when do we use Ka

weak acids

21
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what does Ka tell us

the extent of dicssociation

22
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what do we assume when working with weak acids

-[HA(aq)]equilibrium = [HA(aq)]start

-[H+(aq)]=[A-(aq)]

23
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what is the formula for Ka

Ka = [H+][A-] / [HA] or Ka = [H+]²

24
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how do we calculate pka

-logKa

25
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how do we calculate Ka from pka

10^{-pKa}

26
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