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The distance |P1P2| between the points P1(x1, y1, z1) and P2(x2, y2, z2) is
|P1P2| =
sqrt((x2-x1)² + (y2-y1)² + (z2-z1)²)
The equation of a sphere with the center (a, b, c) and radius r:
r² =
(x-a)² + (y-b)² + (z-c)²
Given the points A(x1, y1, z1) and B(x2, y2, z2), the vector a with representation AB→ is
a = <x2-x1, y2-y1, z2-z1>
Let a = <a1, a2, a3> and b=<b1, b2, b3> be vectors.
The length of a, |a|=
sqrt(a1² + a2² + a3²)
Let a = <a1, a2, a3> and b = <b1, b2, b3>
A unit vector in the same direction as a is u =
a/|a|
Let a = <a1, a2, a3> and b = <b1, b2, b3>
The dot product a⋅b =
a1b1 + a2b2+ a3b3
Let a = <a1, a2, a3> and b = <b1, b2, b3>
If the angle between a and b is θ(0 < θ < π), then we can write a⋅b=
|a||b|cos(theta)
Let a = <a1, a2, a3> and b = <b1, b2, b3>
The vectors a and b are orthogonal if
a⋅b = 0
Let a = <a1, a2, a3> and b = <b1, b2, b3>
The scalar projection of b onto a is given by:
compa(b) = (a⋅b)/|a|
Let a = <a1, a2, a3> and b = <b1, b2, b3>
The vector projection of b onto a is given by:
proja(b)=((a⋅b) / |a|)(a / |a|)
Let a = <a1, a2, a3> and b = <b1, b2, b3>
The cross product of a and b is the vector
a x b = | i j k|=<a2b3-a3b2, a3b1-a1b3, a1b2-a2b1>
|a1 a2 a3|
|b1 b2 b3|
A vector orthogonal to a and b is
a x b
If θ is the angle between a and b (0 < θ < π), then (cross product)
|a x b| = |a||b|sin(theta)
An equation of the line through the point P(x0, y0, z0) parallel to the vector v=<a, b, c>:
L(t)=<x0+ta, y0+tb, z0+tc>
An equation of the plane through the point P(x0, y0, z0) with normal vector n=<a, b, c>:
a(x-x0)+b(y-y0)+c(z-z0)=0