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Different forms of Z^n=
r^n(cos(nx)+isin(nx))
(rcisx)^n= r^n cis(nx)
[r, x]^n=[r^n,nx]
Where nx= arg, r^n=mod
Smallest pos integer n for which z^n is imaginary
arg(nx)= pi/2 , 3pi/2
Smallest pos integer n for which z^n is real
arg(nx)= pi, 2pi
Eulers formula
re^ix = r(cos x + i sinx)
Cartesian form of eulers formula
x+iy
4^(3+2i) in eulers form
4³ (e^ln(4)^(2i))
= 4³(cos(ln16)+isin(ln16))
z+z*=
2rcosx
z-z*=
i2rsinx
z x z*=
r²
cosx=
cos(x+2pik)
sin x=
sin(x+2pik)
cosx +i sinx=
e^i(x+2pik)
Sn=
a(r^(n) -1)/(r-1)
Nth roots of unity are
1, e^(i2pi/n), e^(i4pi/n),…,e^(i2(n-1)pi/n)
W_k=W^k_1=
(e^(i2pi/n))^k
w_(n-1)=
w_(n-2)=
…
=W_1*
=W_2*
…
Multiplying by
r(cos x+ i sin x)
e^irx
Means to translate:
Rotate by x, enlarge by r
Dividing by
r(cos x+ i sin x)
e^irx
Means to translate:
Rotate -x, enlarge by 1/r
Cos nx=
(c+is)^n
e^inx+e^-inx=
2cos (nx)
e^inx-e-inx=
2isin(nx)
Z^n+1/z^n
2cos(nx)
z^n-1/z^n=
2isin(nx)
Conditions for a converging geometric sequence are
-1<r<1
S infinity=
a/(1-r)
Polar coordinate
(r, x)
r is distance from origin, x is angle with initial line
r=k As a polar coordinate
Is a circle
x=k as a polar coordinate is
a half-line
cartesian → polar
X=
Y=
X²+Y²=
rcosx
rsinx
r²
r= sin/cos(nx)
What is n
n is the number of loops
dont draw r<0
looped has
2 tangents
a<b
cardioid has
1 tangent
a=b
dimpled
r>0
b<a<2b
convex/egg
r>0
a=>2b
Regular sin graph
0, pi, 2pi
Regular cos graph
pi/2, 3/2pi
Calculus for polar curves
rmax=
dr/dtheta=0
Area enclosed by polar curve=
½/ r² dtheta
Normally measure between tangents, unless r>0 for any value, then between 2pi and 0
Parallel to initial line
dy/dtheta=0
Perp to the initial line
dx/dtheta=0
/secx tanx
[secx]
/sec²x
[tanx]
tan²x=
sec²x-1
cosec²x=
cot²x+1
Proving De Moivres theorem
Proof by induction for r(cosx+isinx)^n
Evaluate x+iy/a+bi
-convert to mod arg form
-subtract args
-subtract mod powers
-make theta between -pi and pi
X³+bx²+cx+d=0
Find b c and d
b is sum of the roots = -b/a
c is product pairs = c/a
d is product= -d/a
Find all roots of z^n= x+iy
Z^n= re^i(x+2pi k), kEZ
k=0,1,2,-1,-2… for -pi<x<pi
Show that cos_ + cos_ + cos_ = ½
Z^n= x+iy
Z^n-x-iy=0
Roots of z^n=0
Real: cos_ +cos_ +cos_= ½
Find the roots of 1+z+z²+z³=0
a=1
r=z
n= 4
z^n-1=0
z^n=e^i(x+2 pi k) k=0,1,-1,2,-2…
Roots of z^n=p
z=p^1/n
360/n= theta
So z= p^1/n+ p^1/n e^itheta…
z^n=p , find the exact value of cos_
Find roots of z^n=p
Rewrite as z^n-p=0
Analyse for sum/ product/ pairs of the equation to equal 0
i.e z³+1=0 has no z² so sum of roots=0
Find c
State 2 conjugate relationships between the roots of z^n=1
z= 1, e^ix, e^i2x, e^i3x, e^i4x
Look for angles that are equal when one is subtracted from 2pi
“Let w_1 be the conjugate of w_4”
w_1=w_4*
w_2=w_3*
Show that 1/(e^xi -1)= -1/2-i/2 cot (x/2)
(x/2) in final answer is the half angle of x
- 1/(e^xi -1) multiply top and bottom by e^-x/2i, a change in sign for the power as it is a half angle in the final answer
Simplify to get the final answer
Write z^n+p as a product of 2 real quadratic factors
z^n+p=0
Find roots, z= z1, z2, z3
z^n+p= (z-z1)(z-z2)(z-z3)
Multiply out to get 2 quad factors
z^n+p= (z²-az+b)(z²+az+b)
Describe the transformation that maps a onto b (complex numbers)
a=x+iy b=a+bi
a
Mod: 1
arg: pi
b
Mod:2
arg: 2pi
Mod 1→ mod 2 is enlargement 2 and arg pi→ arg 2 pi is rotation pi
so az=b
a(2e^ipi)=b
Find the roots of the regular polygon
-inner
z=p
z^number of points=n
(z^no of points - p)=0
-repeat for outer shape
Multiply the two results to find an equation whose roots will give the roots for the two shapes on the diagram
Use de moivres to derive a formula
Find cos(nx)
(Cos x + i sinx)^n
(c+is)^n
Pascals expansion
R//
Use de moivres to derive a formula
Find cos³x
Use either e^ix +e^-ix= 2cos x
e^ix-e^-ix= 2isinx
In this case (2cosx)³= (e^ix +e^-ix)³
Expand both sides, keeping right side in terms of e
Factorise terms of e to put back into trigonometric form
Integrate cos^6x
Use de moivres
Evaluate
Infinity
E cos(kx)
k=0
Starts writing terms by subbing in k=0,1,2,3…
Find the pattern and write in eulers form
Multiply denominator and rearrange to get answer
Show that (e^ix +1)^n= acos²(x/2)sin(x/2)
Expand to see list of results
Im [(e^ix +1)^n]
Since double angle in answer, take out a factor of e^(ix/2). A double angle only counts if it is the final angle on the list of expanded results, divided by 2.
Expand the e^ix
Write in modulus arg form to get answer
![<p>Expand to see list of results </p><p>Im [(e^ix +1)^n]</p><p>Since double angle in answer, take out a factor of e^(ix/2). A double angle only counts if it is the final angle on the list of expanded results, divided by 2. </p><p>Expand the e^ix</p><p>Write in modulus arg form to get answer</p>](https://knowt-user-attachments.s3.amazonaws.com/0ee6154f-a2e6-44f3-8f36-9d6d2da85b99.jpeg)
Draw the curve r= 5-2sin(3x)
Draw the sin graph
Find the values for 1 section
Mirror it
Check w graphical calc
Draw curve r= 2-2cos(2x)
Solve for r=0
Draw graph
Plot points
Check w calc, be wary of where r<0
Draw curve 3/2-sinx
sinx max = 1
sinx min = -1
So rmax 3/2-1= 3 when sinx= 1, x= pi/2
So r min 3/2+1= 1 when sinx=-1 x= 3pi/2
Plot points
Draw curve r= x(x-pi)(x-2pi) pretend this x is theta
Draw the cartesian graph with y axis equal to r and x axis equal to angle
y= x(x-pi)(x-2pi)
View the points and their locations
Plot
Find the max and min r for the polar curve
(Can sketch)
Write the curve in cartesian form
Find the max and min value of y in cartesian form
Sketch the polar graph to confirm their location being max/min
Find the max and min r for the polar curve
(Unable to sketch)
rmax= dr/dtheta=0
Show line of symmetry
(r, theta) → (r, -theta)