AP Calc BC Part 2 Notes

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Last updated 8:59 PM on 8/19/26
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34 Terms

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Arithmetic Sequence Term

tn=a+(n1)dt_n = a + (n-1)d (where aa is the first term and dd is the common difference)

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Sum of an Arithmetic Series

Sn=n2(2a+(n1)d)S_n = \frac{n}{2}(2a + (n-1)d)

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Geometric Sequence Term

tn=arn1t_n = a r^{n-1} (where aa is the first term and rr is the common ratio)

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Sum of a Finite Geometric Series

Sn=a1rn1rS_n = a\frac{1 - r^n}{1 - r}

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Sum of an Infinite Geometric Series

S=a1rS = \frac{a}{1-r}, provided that r<1\|r\| < 1

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Absolute Convergence

Both the original series an\sum a_n and the absolute value series an\sum \|a_n\| converge.

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Conditional Convergence

The original series an\sum a_n converges, but the absolute value series an\sum \|a_n\| diverges.

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Integral Test Conditions

If f(x)f(x) is positive, continuous, and decreasing for x1x \ge 1 where f(k)=akf(k) = a_k, then 1f(x)dx\int_{1}^{\infty} f(x) \, dx and k=1ak\sum_{k=1}^{\infty} a_k either both converge or both diverge.

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P-Series Test

k=11kp\sum_{k=1}^{\infty} \frac{1}{k^p} converges if p>1p > 1; diverges if 0<p10 < p \le 1.

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Direct Comparison Test

If 0anbn0 \le a_n \le b_n, then if bk\sum b_k converges, so does ak\sum a_k. If ak\sum a_k diverges, then bk\sum b_k diverges as well.

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Ratio Test

Evaluate L=limkak+1akL = \lim_{k \to \infty} \left\| \frac{a_{k+1}}{a_k} \right\|. If L<1L < 1, the series converges absolutely; if L>1L > 1, it diverges; if L=1L = 1, the test is inconclusive.

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n-th Term Test for Divergence

If limkak0\lim_{k \to \infty} a_k \neq 0, then the series ak\sum a_k diverges.

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Alternating Series Test Conditions

  1. ak>0a_k > 0 for all kk; 2. limkak=0\lim_{k \to \infty} a_k = 0; 3. ak+1aka_{k+1} \le a_k (the terms are non-increasing).
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Geometric Series Test

arn\sum a r^n converges if r<1\|r\| < 1; diverges if r1\|r\| \ge 1.

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Limit Comparison Test

Evaluate c=limkakbkc = \lim_{k \to \infty} \frac{a_k}{b_k}. If 0<c<0 < c < \infty, then both series either both converge or diverge.

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General Maclaurin Series

n=0f(n)(0)n!xn\sum_{n=0}^{\infty} \frac{f^{(n)}(0)}{n!} x^n

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Maclaurin Series for sin(x)

sin(x)=k=0(1)k(2k+1)!x2k+1\sin(x) = \sum_{k=0}^{\infty} \frac{(-1)^k}{(2k+1)!} x^{2k+1}

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Maclaurin Series for cos(x)

cos(x)=k=0(1)k(2k)!x2k\cos(x) = \sum_{k=0}^{\infty} \frac{(-1)^k}{(2k)!} x^{2k}

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Maclaurin Series for e^x

ex=n=0xnn!e^x = \sum_{n=0}^{\infty} \frac{x^n}{n!}

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Maclaurin Series for \frac{1}{1-x}

11x=n=0xn\frac{1}{1-x} = \sum_{n=0}^{\infty} x^n valid for x<1\|x\| < 1.

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General Taylor Series

n=0f(n)(a)n!(xa)n\sum_{n=0}^{\infty} \frac{f^{(n)}(a)}{n!} (x-a)^n

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Alternating Series Error Bound

SSkak+1\|S - S_k\| \le a_{k+1}.

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Lagrange Error Bound

En(x)M(n+1)!xan+1\|E_n(x)\| \le \frac{M}{(n+1)!} \|x-a\|^{n+1}.

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Interval of Convergence Three Possibilities

  1. Converges only at x=ax = a (R=0R = 0); 2. Converges absolutely for all xx (R=R = \infty); 3. Converges for xa<R\|x-a\| < R and diverges for xa>R\|x-a\| > R, yielding interval (aR,a+R)(a-R, a+R).
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Steps to Find Interval of Convergence

  1. Apply the Ratio Test to solve for xa<R\|x-a\| < R; 2. Test each endpoint x=aRx = a-R and x=a+Rx = a+R for convergence.
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First Derivative for Parametric Equations

dydx=dy/dtdx/dt\frac{dy}{dx} = \frac{dy/dt}{dx/dt}.

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Second Derivative for Parametric Equations

d2ydx2=ddt(dydx)dxdt\frac{d^2y}{dx^2} = \frac{\frac{d}{dt}\left(\frac{dy}{dx}\right)}{\frac{dx}{dt}}.

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Rectangular Coordinate Equations for Polar Coordinates

x=rcos(θ)x = r \cos(\theta), y=rsin(θ)y = r \sin(\theta), and x2+y2=r2x^2 + y^2 = r^2.

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Polar Curve Derivative

dydx=dydθdxdθ=drdθsin(θ)+rcos(θ)drdθcos(θ)rsin(θ)\frac{dy}{dx} = \frac{\frac{dy}{d\theta}}{\frac{dx}{d\theta}} = \frac{\frac{dr}{d\theta}\sin(\theta) + r\cos(\theta)}{\frac{dr}{d\theta}\cos(\theta) - r\sin(\theta)}.

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Area Bounded by a Polar Curve

A=12abr2dθA = \frac{1}{2} \int_{a}^{b} r^2 \, d\theta.

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Area Between Two Polar Curves

A=12ab((r2)2(r1)2)dθA = \frac{1}{2} \int_{a}^{b} \left((r_2)^2 - (r_1)^2\right) d\theta.

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Cartesian Arc Length

L=ab1+[f(x)]2dxL = \int_{a}^{b} \sqrt{1 + [f'(x)]^2} \, dx (for y=f(x)y = f(x)).

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Cartesian Arc Length for x = g(y)

L=cd1+[g(y)]2dyL = \int_{c}^{d} \sqrt{1 + [g'(y)]^2} \, dy.

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Parametric Arc Length

L=ab(dxdt)2+(dydt)2dtL = \int_{a}^{b} \sqrt{\left(\frac{dx}{dt}\right)^2 + \left(\frac{dy}{dt}\right)^2} \, dt.