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Pythagorean Identity
sin2x+cos2x=1
sin2x+cos2x=1 transformed for sin2x (sin2x=?)
sin2x=1−cos2x
sin2x+cos2x=1 transformed for cos2x (cos2x=?)
cos2x=1−sin2x
sin2x+cos2x=1 transformed for csc2x (csc2x=? )
csc2x=1+cot2x (divide original pythagorean identity by sin2x)
sin2x+cos2x=1transformed for cot2x (cot2x=?)
cot2x=csc2x−1(divide original pythagorean identity by sin2x )
sin2x+cos2x=1 transformed for tan2x (tan2x=?)
tan2x=sec2x−1 (divide original pythagorean identity by cos2x)
sin2x+cos2x=1 transformed for sec2x(sec2x=?)
sec2x=tan2x+1 (divide original pythagorean identity by cos2x)
double angle identity of sin(2x) (sin(2x)=? )
sin(2x)=2sinxcosx
double angle identity of cos(2x) (cos(2x)=? )
cos(2x)=cos2x−sin2x=2cos2x−1=1−sin2x
half angle identity of cos2x (cos2x=?)
cos2x=21+cos(2x)
half angle identity of sin2x (sin2x=?)
sin2x=21−cos(2x)
the degree of sine m is an odd integer in ∫sinmxcosnxdx, with n as an integer > 0
reserve a power of sine (e.g., ∫sin3xcos4xdx=∫sin2xcos4xsinxdx)
convert the remaining powers of sine to cosine using trigonometric identities
perform a u-substitution of cosine
solve
the degree of cosine n is an odd integer in ∫sinmxcosnxdx, with m as an integer > 0
reserve a power of cosine (e.g., ∫sin4xcos3xdx=∫sin4xcos2xcosxdx )
convert the remaining powers of cosine to sine using trigonometric identities
perform a u-substitution of sine
solve
the degree of both sine m and cosine n are odd in ∫sinmxcosnxdx
(pick either method)
reserve a power of either cosine or sine
convert the remaining powers of the chosen function to the other function using trigonometric identities
perform a u-substitution of the other function
solve
he degree of both sine m and cosine n are even in ∫sinmxcosnxdx
substitute both sine and cosine with their half-angle identities
distribute and solve
the degree of tangent m is an odd integer in ∫tanmxsecnxdx, with n as an integer > 0
reserve a secxtanx(e.g., ∫tan3xsecxdx=∫tan2xsecxtanxdx )
convert the remaining powers of tangent to secant using trigonometric identities
perform a u-substitution of secant
solve
the degree of secant n is an even integer in ∫tanmxsecnxdx, with m as an integer > 0
reserve a sec2x (e.g., ∫tan6xsec6xdx=∫tan6xsec4xsec2xdx )
convert the remaining powers of secant to tangent using trigonometric identities
perform a u-substitution of tangent
solve