Week 10- Invertible Matrices and Determinants

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15 Terms

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When is the matrix product defined?

If the inner dimensions agree:

(n x k)((k x m)

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When is a matrix invertible?

If it is square (n x n)

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How do you test for invertibility?

Using the following conditions:

A has n columns.

  • To be invertible, L must be one-to-one and onto.

  • This means that the kernel of A is just 0, or ker(A) = just {0}, or dim(ker(A)) = 0

  • So the rank of A must be n

  • So the columns of A must be linearly independent

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Algorithm for computing the inverse matrix

If A is an invertible n × n matrix, write the following double-width augmented matrix:

[ A | In ].

Use row operations to put this combined matrix into RREF. The resulting matrix will be: [ In | A−1 ]

where A−1 is the inverse of A

<p>If A is an invertible n × n matrix, write the following double-width augmented matrix: </p><p>[ A | I<sub>n</sub> ]. </p><p>Use row operations to put this combined matrix into RREF. The resulting matrix will be: [ I<sub>n</sub> | A−1 ] </p><p>where A−1 is the inverse of A </p>
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Determinant

A single scalar value associated with linear transformation L (and its associated standard matrix A)

  • The magnitude of D represents the overall scaling done by the transformation.

  • The sign of D is related the directional or orientation flips done by the transformation

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Computing determinant for 2 × 2 matrices

<p></p>
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Computing determinant for 2 × 2 matrices

Copy the 1st two columns beside the matrix, then

  • Multiply down the diagonals, and up the diagonals as shown, then

  • Add the down-right diagonal products, and subtract the up-right diagonals.

<p>Copy the 1st two columns beside the matrix, then </p><ul><li><p>Multiply down the diagonals, and up the diagonals as shown, then </p></li><li><p>Add the down-right diagonal products, and subtract the up-right diagonals.</p></li></ul><p></p>
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How could you find a perpendicular vector to two 3D vectors?

cross-multiplying two 3D vectors (computing determinant) will produce a vector perpendicular to both

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Computing the determinant for n x n matrices

Laplace Expansion Formula:

  1. The “checkerboard” pattern of signs. This always starts as a + in the top-left corner, and then alternates for every vertical or horizontal step taken

  2. The (n−1)×(n−1) sub-matrix associated with any entry. For any entry aij in an n×n matrix, we make a smaller sub-matrix by crossing out the row i and column j that entry is in.

Formally:

  1. Pick any row or column.

  2. For every entry aij in that row or column: compute (checkerboard sign) ×(aij)× (det of sub-matrix for aij)

  3. Take the sum of all the values from step 2

<p>Laplace Expansion Formula:</p><ol><li><p>The “checkerboard” pattern of signs. This always starts as a + in the top-left corner, and then alternates for every vertical or horizontal step taken</p></li><li><p>The (n−1)×(n−1) sub-matrix associated with any entry. For any entry aij in an n×n matrix, we make a smaller sub-matrix by crossing out the row i and column j that entry is in.</p></li></ol><p>Formally:</p><ol><li><p>Pick any row or column. </p></li><li><p>For every entry aij in that row or column: compute (checkerboard sign) ×(aij)× (det of sub-matrix for aij) </p></li><li><p>Take the sum of all the values from step 2</p></li></ol><p></p>
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Determinant in terms of scaling

det(A) represents the scaling effect of A as a transform on areas in R2, volumes in R3

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Determinant in terms of invertibility of matrices

det(A)=0 —> A is not invertible

  • transform A collapses at least 1 dimension

  • ker(A)=/ just {0}

  • A is not injective

det(A)=/ 0 —> A is invertible

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Determinants when multiplying matrices

B x A matrix product

det(BA) = det(B) x det(A)

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Determinants of inverse matrices

det(A) det(A-1) = det(In) —> det(A-1) = 1/det(A)

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Inverse matrices using adjoint matrices

A−1 = 1/det(A)Adj(A) where Adj(A) is a new matrix, based on determinants.

Adj(A) = CT, where:

  • The T indicates a transpose, or a reflection of values across the diagonal.

  • The C matrix is the cofactor matrix of A, which is defined element-by-element as Cij = (−1)i+j det(Mij), and

  • Mij is the sub-matrix of A with row i and column j removed

<p>A<sup>−1</sup> = 1/det(A)Adj(A) where Adj(A) is a new matrix, based on determinants. </p><p>Adj(A) = CT, where: </p><ul><li><p>The T indicates a transpose, or a reflection of values across the diagonal. </p></li><li><p>The C matrix is the cofactor matrix of A, which is defined element-by-element as Cij = (−1)i+j det(Mij), and </p></li><li><p>Mij is the sub-matrix of A with row i and column j removed</p></li></ul><p></p>
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