2.2 motion of charged particles in electric fields

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4 Terms

1

draw and describe the electric field produced by two oppositely charged parallel conducting plates

  • uniform between the plates and away from the edges is uniform

  • represented by evenly spaced electric field lines

  • means a positive test charge experiences the same force no matter where it is placed

  • near and beyond the edges of the plates the electric field is non-uniform

<ul><li><p>uniform between the plates and away from the edges is uniform</p></li><li><p>represented by evenly spaced electric field lines</p></li><li><p>means a positive test charge experiences the same force no matter where it is placed</p></li><li><p>near and beyond the edges of the plates the electric field is non-uniform </p></li></ul>
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2

derive the formula for the accelleration of a charge q of mass m in an electric field

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3

how do cyclotrons utilise electric fields

  • cyclotron is composed of two hollow D-shaped copper conductors called Dees

  • the potential difference in the gap between the dees produces a uniform electric field

  • when the charges enter the electric field they are accellerated as the electric field exerts a force on the charges, due to f=ma, the charges gain speed

  • the magnetic field created by electromagnets above and below the dees cause the charged particles to move in a semi circular path through the dees so that they return to the electric field

  • the electric field is reversed when the charges return to the gap so that they once again accellerate accross the electric field

  • the process repeats many times and the charges eventually exit the cyclotron having accumulated a large amount of kinetic energy and thus speed

  • the charges do not gain energy while inside the dees as there is no electric field within a hollow conductor

<ul><li><p>cyclotron is composed of two hollow D-shaped copper conductors called Dees</p></li><li><p>the potential difference in the gap between the dees produces a uniform electric field</p></li><li><p>when the  charges enter the electric field they are accellerated as the electric field exerts a force on the charges, due to f=ma, the charges gain speed</p></li><li><p>the magnetic field created by electromagnets above and below the dees cause the charged particles to move in a semi circular path through the dees so that they return to the electric field</p></li><li><p>the electric field is reversed when the charges return to the gap so that they once again accellerate accross the electric field</p></li><li><p>the process repeats many times and the charges eventually exit the cyclotron having accumulated a large amount of kinetic energy and thus speed </p></li><li><p>the charges do not gain energy while inside the dees as there is no electric field within a hollow conductor</p></li></ul>
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4

describe the morion of charged particles at an angle to a uniform electric field

  • consider a negative charge entering a uniform electric charge between two parallel conducting plates

  • the charge enters in a direction which is perpendicular to the electric field

  • the electric field exerts a constant force towards the lower plate

  • the electric field does not exert a force on the charge in the horizontal direction

  • therefore the component of velocity perpendicular to the electric field remains constant

  • results in a parabolic path towards lower plate

  • the magnitude of vertical accelleration of a charge can be calculated using a=(qE)/m

  • the direction depends on the particle’s charge and the charge of the plates of the conductors

<ul><li><p>consider a negative charge entering a uniform electric charge between two parallel conducting plates</p></li><li><p>the charge enters in a direction which is perpendicular to the electric field</p></li><li><p>the electric field exerts a constant force towards the lower plate</p></li><li><p>the electric field does not exert a force on the charge in the horizontal direction</p></li><li><p>therefore the component of velocity perpendicular to the electric field remains constant</p></li><li><p>results in a parabolic path towards lower plate</p></li><li><p>the magnitude of vertical accelleration of a charge can be calculated using a=(qE)/m</p></li><li><p>the direction depends on the particle’s charge and the charge of the plates of the conductors</p></li></ul>
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