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3 L of a 2 M sugar solution — how many moles of sugar?
6 moles
4 g sugar (M.W. 342 g/mol) dissolved in 350 mL water — molarity?
0.033 M
171 g sucrose (M.W. ≈ 342 g/mol) in 1.00 L solution — molarity?
0.5 M
0.75 mole dissolved in 2.50 L — molarity? →
0.3 M
25.0 g KBr (M.W. 119 g/mol) in 750.0 mL — molarity? →
0.28
58.44 g NaCl (M.W. 58.44 g/mol) in 2.00 L — molarity?
0.5 M
80.0 g glucose (M.W. 180 g/mol) in 1.00 L — molarity? →
0.444 M
15.0 g H₂SO₄ (M.W. 98 g/mol) to make a 0.200 M solution — how many mL? →
765.3 mL
30.0 g acetic acid (M.W. 60 g/mol) in 500.0 mL — molarity? →
1.0 M
Formula:
M = moles of solute ÷ liters of solution
moles = grams ÷ molecular weight)