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CCD interval [a,b] pt. c exists where f’(c) = (f(b)-f(a))/(b-a)
√3
3x²
1/2√x
-x^-1
Concave Up
Decreasing
Underestimate
-e-x
f(b)-f(a)/b-a
-1
a(b)’ - b(a)’ / (a)²
cot(x)
|P’(x)| or |v(x)|
f’(g(x)) * g’(x)
1/4
y - 4 = 1/4(x-2)
-csc(x)cot(x)
y = sin(u)du + c
esin(x)cos(x)
∞
1/x(ln(a))
csc-1(x)
maximum
3π/4, 7π/4
Extreme Value Theorum
DNE
y = -5ln|x| + C
0
f” > 0
0
y = sec(x) + C
2hπrr’ = 16π
2x³yy’ + 3x²y²
0, 1/2
0