#14 Exponentials and Logs

0.0(0)
studied byStudied by 0 people
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
Card Sorting

1/17

encourage image

There's no tags or description

Looks like no tags are added yet.

Study Analytics
Name
Mastery
Learn
Test
Matching
Spaced

No study sessions yet.

18 Terms

1
New cards

What is an exponential function?

A function in the form f(x) = ax

2
New cards

Where does an exponential cross the y-axis?

y = 1

3
New cards

If a>1, which way does the graph tend?

Upwards

4
New cards

If 0<a<1, which way does the graph tend?

Downwards

5
New cards

If f(x) = ekx, what is f ‘(x) ?

kekx

6
New cards

What is the constant e used for?

To model population growth where the rate of increase is proportional to the size of the population

7
New cards

What is a logarithm?

The inverse of an exponential function

8
New cards

State the expression logan = x as an exponential?

ax = n

9
New cards

State the multiplication law of logarithms.

logax + logay = logaxy

10
New cards

State the division law of logarithms.

logax - logay = logax/y

11
New cards

State the power law of logarithms.

loga(xk) = klogax

12
New cards

State the special cases of log laws.

loga(1/x) = -logax

logaa = 1

loga1 = 0

13
New cards

Describe how to use logs to solve equations in the form ax = b.

Re-arrange into log form and solve using a calculator

14
New cards

Describe how to solve an equation involving hidden quadratics.

Use the substitution method to make a quadratic and solve, subbing the answers into the substitution equation

15
New cards

State how to solve more complex equations using logs.

Take logs of both sides

16
New cards

What is the natural log?

The reverse function of ex

17
New cards

How can a linear relationship be modelled from data with the equation y=axn?

logy = loga + nlogx

compare the y = mx + c

18
New cards

How can a linear relationship be modelled from data with the equation y=abx?

logy = loga + xlogb

compare to y = mx + c