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Geometric series
a/(1-r)
Convergence if |r| < 1
Diveregence if |r| >= 1
nth Term Test
a_n
Divergence: if limit as n approaches infinity is NOT equal to 0
Inconclusive: if limit as n aproaches infinity is equal to 0
Cannot prove convergence
Integral test
Do integral of inner function from N value to infinity
If received a real number then CONVERGENCE
Otherwise divergence
P-Series Test
Sumation of n=N to infinity is 1/(n^P)
Converges if P > 1
Diverges if 0 < P <= 1
Opposite of Geometric test basically
Alternating Series Test
Sumation of something of (-1)^n * f(x)
Convergence: sequence must decrease and lim as n aproaches 0 of f(x) = 0
Cannot prove divergence, do another test
Absolute/conditional convergence:
Use direct/limit comparison and if that converges as well as the orignal absolute convergence
If just orignal converges then conditional convergence
If neither then divergence
Direct Comparison
Pick a function thats the more simplisitc version of the given sumation
Limit Comparsion
Find simpler function and divide it by the original function, take the lim of that
Convergence: 0<x<infinity (positive and finite value)
if (a_n)/(b_n) = 0 sumation of a_n converge if b_n converge
if (a_n)/(b_n) = infinity sumation of a_n diverges if b_n diverge
Ratio Test
take absolute value lim of increase the nth term by one and divide by original function
Converges if that whole thing is <1
Diverges if >1 or =infinity
Same as geometric test basically
Root Test
Take the nth root of the absolute value of a_n
Converges if that is <1
Diverges for anything else
Inconclusive if that is = 1, try smthn else