Chemistry Review: Atomic Structure, Isotopes, and Spectroscopy

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A set of fill-in-the-blank flashcards covering key topics from the notes: chemical laws, nuclear model, atomic notation, neutrons/electrons, percent composition, sig figs, atomic mass units vs. g/mol, isotope averaging, and basic spectroscopy equations.

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20 Terms

1
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In a given compound, the mass ratios of the elements are always __.

constant

2
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The law of multiple proportions states that when two elements form more than one compound, the masses of the second element that combine with a fixed mass of the first are in __-number ratios.

simple whole-number ratios

3
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Compounds are formed when atoms of different elements combine in -number ratios.

small whole-number

4
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In Rutherford's gold foil experiment, most alpha particles passed through with minimal deflection, but some were deflected due to the presence of a small, dense inside the atom.

nucleus

5
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In atomic symbols, the first letter is and the second letter (if present) is .

capital; lowercase

6
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Mass number is written as a to the upper left of the symbol.

superscript

7
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Atomic number is written as a to the lower left of the symbol.

subscript

8
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The number of neutrons N is calculated as .

A − Z

9
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For an ion with charge x+, there are electrons than protons.

one fewer

10
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To calculate percent composition, you sum the mass contributions and divide by .

100%

11
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In multiplication or division, the result should have as many significant figures as the factor with the sig figs.

fewest

12
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In addition or subtraction, the result should be rounded to the least precise place.

decimal

13
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AMU is the unit for the mass of a atom, while g/mol is the unit for the mass per of atoms.

single; mole

14
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The weighted average atomic mass is calculated using the formula Aavg = sum (fractioni × mass_i) for all isotopes.

sum of products of isotopic fractions and their masses

15
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Gallium has isotopes Ga-69 and Ga-71 with abundances 60.11% and 39.89%; the weighted average mass is approximately amu.

69.72

16
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Red fireworks emission is due to light with a wavelength around nm.

650

17
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The speed of light is c ≈ × 10^8 m/s.

2.998

18
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One nanometer equals meters.

1.0 × 10^-9

19
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The relationship between wavelength and frequency is given by the equation (i.e., λ = c / f).

λ = c / f

20
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For λ = 650 nm, the frequency f is approximately Hz.

4.61 × 10^14