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Find the area of the region that is bounded by the given curve, r = e^(-θ/10), π/2 ≤ θ ≤ π
Find the area that encloses r = 5 + 2 cos(𝜃)
Find the area of the region enclosed by one loop of the curve r = sin(4𝜃)
Find the area of the region that lies inside the first curve and outside the second curve. r = 14 cos(𝜃), r = 7
A. Find the area enclosed by one of the petals of the curve r = cos(2θ)
B. Set up the integral to find the area of the entire curve
B. You would right the same thing for part A where you only use one half of the petal, but instead of multiplying the integral by 2, you would multiply it by 8. If you wrote the integral in part A by doing the positive and negative bounds as opposed to just doing the positive bound and the other bound be 0, you would multiple the integral by 4
Find the area enclosed by one loop of the circle r = 2cosθ
Find the area of the region that lies inside the first curve r = 3sin𝜃 and outside the second curve r = 1 + sin𝜃
Find the arc length of the curve r = 2cosθ, 0 ≤ 𝜃 ≤ 𝜋
Find the slope of the tangent line to the polar curve r = 2cosθ, when θ =π/3
Find the slope of the tangent line to the polar curve r = 9/θ, when θ = π
Find the slope of the tangent line to the polar curve r = cos(θ/3), when θ = π
Find the exact length of the polar curve r = θ², 0 ≤ 𝜃 ≤ 3𝜋/2