proton (H+)
Hydronium (H30+) formed when a water molecule and proton coordinately bond
taste sour
pH < 7.0
litmus is red
phenolphthalein is colorless
methyl orange is red
taste bitter
ph > 7.0
litmus is blue
phenolphthalein is pink
methyl orange is yellow
metal hydroxides
metal oxides
ammonium hydroxide (Weak)
pH = 14 - (-log[OH-]) or
[H+] = (10^-14)/[OH-]
pH = -log[H+]
HCl (hydrochloric acid)
HNO3 (nitric acid)
H2SO4 (sulfuric acid)
CH3COOH (Ethanoic acid)
H2CO3 (Carbonic acid)
H3PO4 (phosphoric acid)
Group 1 metal Hydroxides
LiOH (Lithium Hydroxide)
NaOH (Sodium Hydroxide)
KOH (Potassium Hydroxide)
Ba(OH)2 (Barium Hydroxide
NH3 (Ammonia)
C2H5NH2 (Ethylamine) and other amines
deforestation
leaching of minerals from soils leading to elevated acid levels in lakes and rives
uptake of toxic minerals by plants
reduction of pH of lake and river systems
uptake of toxic metals by shellfish and other marine animals which can damage the fishing industry
Corrosion of marble, limestone, and metal buildings, bridges and vehicles
Natural: volcanic eruptions and the decomposition of vegetation
Unnatural: burning of fossil fuels
80-90% of all inorganic sulfur removed
mineral benefaction involves crushing coal, followed by floatation
electron rich with at least one lone pair of electrons
Lewis Base
an electron-deficient species that can accept a lone pair from a nucleophile
Lewis Acid
Find the moles of the HA and OH-
Find number of HA moles left and A- moles formed
Calculate [HA] leftover and [A-] formed
Use Ka to find [H+] using equation to the left
pH is the -log[H+]
Note with different molar ratios it has to be multiplied or divided
Find the moles of the AH and OH-
Find number of OH- moles left and A- moles formed
Calculate [OH-] left over
Calculate pOH is the -log[OH-]
pH = 14 - pOH
Note with different molar ratios it has to be multiplied or divided
Ka x Kb = Kw
Ka = Kw/Kb
Kb = Kw/Ka
the larger the Ka
the weaker the conjugate base
the smaller the Kb of the conjugate base
the larger the Kb
the weaker the conjugate acid
the smaller the Ka of the conjugate acid
change in the temperature of the system will result in a change in the position of equilibrium resulting in the forward reaction being favored, increasing the concentration of hydrogen and hydroxide ions.
represents an increase in the magnitude of Kw and decrease in pH
distinction between the neutrality and pH of the solution as the pH decreases with an increase in [H+] but [OH-] increases equally so the solution remains neutral