1.3, 1.4 Quadratic Equations & Complex Numbers

0.0(0)
studied byStudied by 0 people
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
Card Sorting

1/16

encourage image

There's no tags or description

Looks like no tags are added yet.

Study Analytics
Name
Mastery
Learn
Test
Matching
Spaced

No study sessions yet.

17 Terms

1
New cards

quadratic equation

an equation of the standard form ax² + bx + c = 0, where a ≠ 0

<p>an equation of the standard form ax² + bx + c = 0, where a ≠ 0</p>
2
New cards

quadratic formula

[-b ± √(b² - 4ac)] / (2a)

is used as a form of solving quadratic equations

<p>[-b ± √(b² - 4ac)] / (2a)</p><p>is used as a form of solving quadratic equations</p>
3
New cards

4 ways to solve quadratic equations

4 ways: factoring, square root property, completing the square, quadratic formula

<p>4 ways: factoring, square root property, completing the square, quadratic formula</p>
4
New cards

factoring is based on

the zero product property. review P4.2, P4.3

to factor, put polynomial in standard form, factor and get linear factors, set each linear factor to 0 and solve

5
New cards

completing the square

using a trinomial in standard form:

1. subtract c

2. divide by a on both sides

3. add the square of 1/2 the coefficient of x

4. write the left hand side as a perfect square

5. solve using the square root property

<p>using a trinomial in standard form:</p><p>1. subtract c</p><p>2. divide by a on both sides</p><p>3. add the square of 1/2 the coefficient of x</p><p>4. write the left hand side as a perfect square</p><p>5. solve using the square root property</p>
6
New cards

square root property

for any number n ≥ 0, if x² = n, then x = ±√n.

To solve a quadratic equation in the form x^2=n, take the square root of each side.

can be generalized to cube roots and higher powers

<p>for any number n ≥ 0, if x² = n, then x = ±√n.</p><p>To solve a quadratic equation in the form x^2=n, take the square root of each side.</p><p>can be generalized to cube roots and higher powers</p>
7
New cards

using the quadratic formula

1. make sure the trinomial is in standard form

2. plug a,b,c into the formula and solve

<p>1. make sure the trinomial is in standard form</p><p>2. plug a,b,c into the formula and solve</p>
8
New cards

what is the discriminant

The discriminant of the quadratic equation ax^2+bx+c=0 is

D=b^2-4ac

If D>0, then the equation has two distinct real solutions

if D=0, then the equation has exactly one real solution

if D<0, then the equation has no real solution

<p>The discriminant of the quadratic equation ax^2+bx+c=0 is </p><p>D=b^2-4ac</p><p>If D&gt;0, then the equation has two distinct real solutions </p><p>if D=0, then the equation has exactly one real solution </p><p>if D&lt;0, then the equation has no real solution</p>
9
New cards

imaginary numbers

Square roots of negative numbers. Have no points on the number line

uses most of the rules of radicals: refer to P.6

<p>Square roots of negative numbers. Have no points on the number line</p><p>uses most of the rules of radicals: refer to P.6</p>
10
New cards

i =

√-1

11
New cards

i²=

-1

<p>-1</p>
12
New cards

complex numbers

has a standard form: z=a+bi, a is a real number

<p>has a standard form: z=a+bi, a is a real number</p>
13
New cards

imaginary numbers and rational numbers

rational, irrational, and imaginary numbers do not overlap but can be added/subtracted/multiplied/divided together

<p>rational, irrational, and imaginary numbers do not overlap but can be added/subtracted/multiplied/divided together</p>
14
New cards

adding/substracting complex numbers

(a+bi)+(c+di) = (a+c) + (b+d)i

Add real parts, then add the imaginary parts on, expressing the sum as a complex number

<p>(a+bi)+(c+di) = (a+c) + (b+d)i</p><p>Add real parts, then add the imaginary parts on, expressing the sum as a complex number</p>
15
New cards

multiplying complex numbers

1. FOIL (refer to P4.1)

2. Simplify *WHENEVER IT IS i^2 REPLACE with -1*

3. Write answer in standard form (a+bi)

Ex: -2i(5+31)

-10i-6i^2

-10i-6(-1)

-10+6

6-10i

<p>1. FOIL (refer to P4.1)</p><p>2. Simplify *WHENEVER IT IS i^2 REPLACE with -1*</p><p>3. Write answer in standard form (a+bi)</p><p>Ex: -2i(5+31)</p><p>-10i-6i^2</p><p>-10i-6(-1)</p><p>-10+6</p><p>6-10i</p>
16
New cards

dividing complex numbers

1. multiply the numerator and denominator by the conjugate of the denominator

2. solve accordingly

<p>1. multiply the numerator and denominator by the conjugate of the denominator</p><p>2. solve accordingly</p>
17
New cards

conjugate of the denominator

The same to terms with the opposite sign between the two terms, the real term does not change signs.

Remember to replace i^2 with a = -1, combine like terms, and then continue simplifying the fraction.

(is similar to rationalizing the denomator; the number is always rational: refer to P3.1,P3.2)

<p>The same to terms with the opposite sign between the two terms, the real term does not change signs. </p><p>Remember to replace i^2 with a = -1, combine like terms, and then continue simplifying the fraction.</p><p>(is similar to rationalizing the denomator; the number is always rational: refer to P3.1,P3.2)</p>