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27 Terms

1
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CAB

Determine the largest mass of cylinder F that can be supported.

A. 367.60

B. 376.60

C. 37.47

D. 73.74

Determine the tension on cable CD.

A. 342

B. 366

C. 355

D. 426

What is the sag Yc(ft)?

A. 3.03

B. 9.94

C. 4.03

D. 8.49

<p>Determine the largest mass of cylinder F that can be supported.</p><p>A. 367.60</p><p>B. 376.60</p><p>C. 37.47</p><p>D. 73.74</p><p>Determine the tension on cable CD.</p><p>A. 342</p><p>B. 366</p><p>C. 355</p><p>D. 426</p><p>What is the sag Yc(ft)?</p><p>A. 3.03</p><p>B. 9.94</p><p>C. 4.03</p><p>D. 8.49</p>
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BCA

Determine the shear strength provided (kN) by the concrete.

73

76

94

64

If Pu = 10 kN, determine the spacing due to shear alone.

168

600

263

210

Determine the maximum value of Pu so that the effect of torsion can be neglected.

1.70

0.80

1.50

1.20

<p>Determine the shear strength provided (kN) by the concrete.</p><p>73</p><p>76</p><p>94</p><p>64</p><p>If Pu = 10 kN, determine the spacing due to shear alone.</p><p>168</p><p>600</p><p>263</p><p>210</p><p>Determine the maximum value of Pu so that the effect of torsion can be neglected.</p><p>1.70</p><p>0.80</p><p>1.50</p><p>1.20</p>
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BDA

Situation. An 18 m long precast pile is to be lifted at two points from the casting bed. The weight of the pile is 4.86 kN/m.

At what equal distance (m) from the middle should the pile be lifted so that the maximum bending moment is theleast possible?

A. 2.95

B. 5.27

C. 2.25

D. 3.73

At what equal distance (m) from the ends should the pile be lifted so that the resulting shear stress is the smallest

A. 5.6

B. 3.4

C. 2.25

D. 3.73

As the pile is being moved, its left end is laid on the ground while being lifted through a hook attached 3 m. from the right end. What is the maximum positive moment (kN.m) due to its weight?

A. 126

B. 116

C. 108

D. 122

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CBA

SITUATION. A cantilever beam 3.5 long, carries a concentrated load, P, at mid length. Given the following:

P = 200 kN E = 200 GPa I = 60.8 x 106 mm4

How much is the beam deflection (mm) at mid length?

A. 1.84

B. 23.50

C. 29.40

D. 14.70

What force (kN) should be applied at the free end to prevent deflection?

A. 7.8

B. 62.5

C. 41.7

D. 100

To limit the deflection at mid-length to 9.5 mm, how much force (kN) should be applied at the free end?

A. 54.1

B. 129

C. 76.6

D. 64.7

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ABD

For the computation of design force, apply the moving concentrated load at the truss joint only. Find the maximum vertical reaction at A.

A. 190.8

B. 140.25

C. 160.5

D. 130.6

What is the maximum ordinate of the influence line for the force developed in member JK?

A. -1.0

B. -0.50

C. 1

D. 0.5

What is the maximum force developed in member JK.

A. 88

B. 140

C. 160

D. 94

<p>For the computation of design force, apply the moving concentrated load at the truss joint only. Find the maximum vertical reaction at A.</p><p>A. 190.8</p><p>B. 140.25</p><p>C. 160.5</p><p>D. 130.6</p><p>What is the maximum ordinate of the influence line for the force developed in member JK?</p><p>A. -1.0</p><p>B. -0.50</p><p>C. 1</p><p>D. 0.5</p><p>What is the maximum force developed in member JK.</p><p>A. 88</p><p>B. 140</p><p>C. 160</p><p>D. 94</p>
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ACA

Determine the diameter (mm) of the bracket based on the allowable bending stress of 30 MPa.

A. 20

B. 30

C. 25

D. 35

Compute the max. shear stress for this diamter as required by bending.

A. 0.9

B. 0.85

C. 0.80

D. 0.95

If the diamter d = 15 mm, at what distance x from C should the force P = 224 N be applied so that it will not exceed the allowable bending stress of 30 MPa.

A. 130.62

B. 120.24

C. 138.24

D. 125.29

<p>Determine the diameter (mm) of the bracket based on the allowable bending stress of 30 MPa.</p><p>A. 20</p><p>B. 30</p><p>C. 25</p><p>D. 35</p><p>Compute the max. shear stress for this diamter as required by bending.</p><p>A. 0.9</p><p>B. 0.85</p><p>C. 0.80</p><p>D. 0.95</p><p>If the diamter d = 15 mm, at what distance x from C should the force P = 224 N be applied so that it will not exceed the allowable bending stress of 30 MPa.</p><p>A. 130.62</p><p>B. 120.24</p><p>C. 138.24</p><p>D. 125.29</p>
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CDA

Find the maximum compressive stress (kPa) at the base of the wall if the water reaches the top of the wall.

A. 1426

B. 1638

C. 1128

D. 1536

If the maximum compressive stress at the base of the wall is not exceed 380 kPa, what is the allowable depth (m)

of the water?

A. 1.20

B. 1.50

C. 1.00

D. 2.00

If the allowable tensile stress at the base if the wall is zero, what is the maximum height of the water which the wall can retain?

A. 1.20

B. 1.50

C. 1.00

D. 2.00

<p>Find the maximum compressive stress (kPa) at the base of the wall if the water reaches the top of the wall.</p><p>A. 1426</p><p>B. 1638</p><p>C. 1128</p><p>D. 1536</p><p>If the maximum compressive stress at the base of the wall is not exceed 380 kPa, what is the allowable depth (m)</p><p>of the water?</p><p>A. 1.20</p><p>B. 1.50</p><p>C. 1.00</p><p>D. 2.00</p><p>If the allowable tensile stress at the base if the wall is zero, what is the maximum height of the water which the wall can retain?</p><p>A. 1.20</p><p>B. 1.50</p><p>C. 1.00</p><p>D. 2.00</p>
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DDD

Situation – Roof trusses 6 m apart support purlins spaced at 1 m on centers. The purlins are simply

supported.

Given:

Roof slope = 15 degrees

Gravity loads acting at the top flange of the purlins (Total) = 900 Pa

Wind loads:

288 Pa pressure at the windward side

864 Pa suction at the leeway side

Properties of the Purlins

Section : 200 mm x 7 mm

Sx :6.19 x 104 mm3

Sy :1.60 x 104 mm3

Weight :79 N/m

Load Combination = D + W

Which of the following gives the bending stress about the x-axis, fbx (Mpa)?

A. 93

B. 96

C. 99

D. 90

Which of the following gives the bending stress about the y-axis, fby (Mpa)?

A. 92

B. 144

C. 167

D. 136

What should be the maximum purlin spacing (m) to prevent overstressing? Fbx = Fby = 207MPa

A. 0.50

B. 0.75

C. 0.30

D. 0.90

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BBC

Based on bolt capacity in shear.

A. 75

B. 82

C. 41

D. 150

Based on bolt bearing capacity.

A. 184

B. 123

C. 61

D. 207

Based on block shear strength of the double angle.

A. 173

B. 74

C. 272

D. 136

<p>Based on bolt capacity in shear.</p><p>A. 75</p><p>B. 82</p><p>C. 41</p><p>D. 150</p><p>Based on bolt bearing capacity.</p><p>A. 184</p><p>B. 123</p><p>C. 61</p><p>D. 207</p><p>Based on block shear strength of the double angle.</p><p>A. 173</p><p>B. 74</p><p>C. 272</p><p>D. 136</p>
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DBA

SITUATION. A 12 mm thick steel tire has a width of 110 mm and has an internal diameter of 800 mm. The tire is heated and shrunk to a steel wheel 800.5 mm diameter. Take the modulus of Elasticity, E = 200 GPa.

Determine the compressive pressure (MPa) between the tire and the wheel.

A. 7.50

B. 5.25

C. 10.50

D. 3.75

Determine the tensile stress (MPa) in the tire.

A. 175

B. 125

C. 250

D. 350

Determine the thickness (mm) of the tire to resist pressure of 1.5 MPa if it has an allowable stress of 124 MPa.

A. 4.84

B. 8.44

C. 2.12

D. 6.32

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BCA

SITUATION. A parabolic cable carries a horizontally distributed load of 20 kN/m. The horizontal span between the supports A and C is 60 m. The lowest point B has a vertical distance of 6 m below the support at A and 12 m below the support at C.

Determine the horizontal distance (m) between the lowest point and the support at A.

A. 21.67

B. 24.85

C. 25.35

D. 26.45

Determine the tension (kN) at cable A?

A. 1029

B. 703

C. 1143

D. 1247

Determine the tension (kN) at cable C.

A. 1247

B. 1143

C. 1029

D. 703

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BDB

What is the critical effective slenderness ratio of the column?

A. 38

B. 83

C. 54

D. 58

Calculate the critical load Pc in kN?

A. 11210

B. 4733

C. 5493

D. 2319

Determine the minimum length of the column for which the Euler’s formula is valid if the proportional limit of the steel used is 320 MPa.

A. 11.70

B. 7.60

C. 3.80

D. 10.80

<p>What is the critical effective slenderness ratio of the column?</p><p>A. 38</p><p>B. 83</p><p>C. 54</p><p>D. 58</p><p>Calculate the critical load Pc in kN?</p><p>A. 11210</p><p>B. 4733</p><p>C. 5493</p><p>D. 2319</p><p>Determine the minimum length of the column for which the Euler’s formula is valid if the proportional limit of the steel used is 320 MPa.</p><p>A. 11.70</p><p>B. 7.60</p><p>C. 3.80</p><p>D. 10.80</p>
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DBB

Calculate the maximum bending stress (MPa) in the beam due to dead load.

A. 123

B. 92

C. 107

D. 98

Determine the maximum moment due to live load plus impact.

A. 524.47

B. 651.35

C. 681.81

D. NOTA

Calculate the maximum bending stress (MPa) in the beam due to live load plus impact.

A. 79

B. 68

C. 62

D. 56

<p></p><p>Calculate the maximum bending stress (MPa) in the beam due to dead load.</p><p>A. 123</p><p>B. 92</p><p>C. 107</p><p>D. 98</p><p>Determine the maximum moment due to live load plus impact.</p><p>A. 524.47</p><p>B. 651.35</p><p>C. 681.81</p><p>D. NOTA</p><p>Calculate the maximum bending stress (MPa) in the beam due to live load plus impact.</p><p>A. 79</p><p>B. 68</p><p>C. 62</p><p>D. 56</p>
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DCC

Determine the tensile force (kN) in the cable if W = 36 kN.

A. 66

B. 80

C. 40

D. 33

Determine the vertical reaction (kN) at B if W = 36kN.

A. 56

B. 48

C. 64

D. 39

If the allowable tensile force in the cable AC is 45kN, what is the maximum load W (kN) that can be lifted.

A. 56

B. 48

C. 50

D. 39

<p>Determine the tensile force (kN) in the cable if W = 36 kN.</p><p>A. 66</p><p>B. 80</p><p>C. 40</p><p>D. 33</p><p>Determine the vertical reaction (kN) at B if W = 36kN.</p><p>A. 56</p><p>B. 48</p><p>C. 64</p><p>D. 39</p><p>If the allowable tensile force in the cable AC is 45kN, what is the maximum load W (kN) that can be lifted.</p><p>A. 56</p><p>B. 48</p><p>C. 50</p><p>D. 39</p>
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CBC

SITUATION. The rigid bar AB has a hinged at A and supported by steel plate hanger, designated at D. The

hanger is fixed at D with two plates.

L1 = 2.0m

L2 = 1.2m

H = 3.0m

Thickness of plate hanger = 10mm

Width of plate hanger = 40mm

Bolt diameter = 20mm

Allowable bolt bearing stress = 240 MPa

Allowable bolt shear stress = 68 MPa

What is the allowable stress (MPa) in the hanger based on bolt capacity in double shear at D.

A. 53.4

B. 86.6

C. 106.8

D. 43.3

If the maximum tensile stress in the hanger is 138 MPa, find the allowable load W (kN).

A. 55.2

B. 34.5

C. 69.0

D. 138.5

If the load W = 60kN, what is the vertical displacement (mm) at B?

A. 3.6

B. 9.22

C. 5.76

D. 6.0

<p>SITUATION. The rigid bar AB has a hinged at A and supported by steel plate hanger, designated at D. The</p><p>hanger is fixed at D with two plates.</p><p>L1 = 2.0m</p><p>L2 = 1.2m</p><p>H = 3.0m</p><p>Thickness of plate hanger = 10mm</p><p>Width of plate hanger = 40mm</p><p>Bolt diameter = 20mm</p><p>Allowable bolt bearing stress = 240 MPa</p><p>Allowable bolt shear stress = 68 MPa</p><p></p><p>What is the allowable stress (MPa) in the hanger based on bolt capacity in double shear at D.</p><p>A. 53.4</p><p>B. 86.6</p><p>C. 106.8</p><p>D. 43.3</p><p>If the maximum tensile stress in the hanger is 138 MPa, find the allowable load W (kN).</p><p>A. 55.2</p><p>B. 34.5</p><p>C. 69.0</p><p>D. 138.5</p><p>If the load W = 60kN, what is the vertical displacement (mm) at B?</p><p>A. 3.6</p><p>B. 9.22</p><p>C. 5.76</p><p>D. 6.0</p><p></p>
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CAD

SITUATION.

Given:

b= 350 mm h1= 100 mm h2= 500 mm

Tension steel, As = 6 of 28 mm diameter bars

Compression steel, As’ = 4 of 28 mm diameter bars

Lateral ties = 12 mm

Clear concrete cover = 40 mm

Concrete: fc’ = 28MPa

Steel: fyt = 415MPa (main bars)

fyv = 275MPa (ties)

Allowable concrete shear stress at factored load, 0.88 MPa

Which of the following gives the minimum spacing, a (mm)?

A. 56

B. 28

C. 53

D. 38

Which of the following gives the nominal shear strength (kN) provided by the concrete?

A. 159

B. 285

C. 158.7

D. 362

Which of the following gives the nominal shear strength (kN) of the section if the lateral ties are spaced at 125 mm on center?

A. 257

B. 415.7

C. 256.5

D. 416

<p>SITUATION.</p><p>Given:</p><p>b= 350 mm h1= 100 mm h2= 500 mm</p><p>Tension steel, As = 6 of 28 mm diameter bars</p><p>Compression steel, As’ = 4 of 28 mm diameter bars</p><p>Lateral ties = 12 mm</p><p>Clear concrete cover = 40 mm</p><p>Concrete: fc’ = 28MPa</p><p>Steel: fyt = 415MPa (main bars)</p><p>fyv = 275MPa (ties)</p><p>Allowable concrete shear stress at factored load, 0.88 MPa</p><p></p><p>Which of the following gives the minimum spacing, a (mm)?</p><p>A. 56</p><p>B. 28</p><p>C. 53</p><p>D. 38</p><p>Which of the following gives the nominal shear strength (kN) provided by the concrete?</p><p>A. 159</p><p>B. 285</p><p>C. 158.7</p><p>D. 362</p><p>Which of the following gives the nominal shear strength (kN) of the section if the lateral ties are spaced at 125 mm on center?</p><p>A. 257</p><p>B. 415.7</p><p>C. 256.5</p><p>D. 416</p>
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BCC

SITUATION. A 12m simply supported beam is provided by an additional support at midspan. The beam has a width of b = 300mm and a total depth h = 450mm. It is reinforced with 4-25mmφ at the tension side and 2-25mmφ at the compression side with 70mm cover to centroid of reinforcements. fc’ = 30 MPa, fy = 415 MPa.

Determine the depth of compression block (mm).

A. 142.24

B. 106.52

C. 159.77

D. 53.26

Determine the nominal bending moment. (kN-m)

A. 336.1

B. 244.92

C. 266.2

D. 119.5

Determine the total factored uniform load (kN/m) including the beam’s weight.

A. 84.025

B. 65.07

C. 53.24

D. 71.84

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A

The material has the same composition at every point but the elastic properties may not be the same in all directions.

A. Isotropic

B. Orthotropic

C. Prismatic

D. Homogeneous

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A

The composite material exhibits elastic properties in one direction different from that in the perpendicular

direction.

A. Orthotropic

B. Isotropic

C. Homogeneous

D. Prismatic

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C

The material with the same elastic properties at all points.

A. Prismatic

B. Isotropic

C. Homogeneous

D. Orthotropic

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CAD

SITUATION. A combined footing as shown carries ultimate column loads:

Pu1 = 928 kN

Pu2 = 1484 kN

Dimension = 6m x 4m

Distance between columns = 3.9m

Effective depth of footing = 500mm

Reduction factor for shear, Ø = 0.75

Reduction factor for moment, Ø = 0.90

fc’= 27.7 MPa

fy = 413 MPa

Determine the maximum punching shear stress (MPa).

A. 1.96

B. 0.77

C. 0.98

D. 1.74

Determine the wide beam shear stress (MPa).

A. 0.39

B. 1.73

C. 0.41

D. 0.87

Determine the number of 20mm Ø bars parallel to the longer side at the right overhang.

A. 12

B. 10

C. 20

D. 22

<p>SITUATION. A combined footing as shown carries ultimate column loads:</p><p>Pu1 = 928 kN</p><p>Pu2 = 1484 kN</p><p>Dimension = 6m x 4m</p><p>Distance between columns = 3.9m</p><p>Effective depth of footing = 500mm</p><p>Reduction factor for shear, Ø = 0.75</p><p>Reduction factor for moment, Ø = 0.90</p><p>fc’= 27.7 MPa</p><p>fy = 413 MPa</p><p></p><p>Determine the maximum punching shear stress (MPa).</p><p>A. 1.96</p><p>B. 0.77</p><p>C. 0.98</p><p>D. 1.74</p><p>Determine the wide beam shear stress (MPa).</p><p>A. 0.39</p><p>B. 1.73</p><p>C. 0.41</p><p>D. 0.87</p><p>Determine the number of 20mm Ø bars parallel to the longer side at the right overhang.</p><p>A. 12</p><p>B. 10</p><p>C. 20</p><p>D. 22</p>
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BAD

SITUATION. The weight of the cylindrical tank is negligible in comparison with the weight of water it contains (water weighs 9.81kN/m3). The coefficient of friction between the tank and the horizontal surface is u (sub) s.

Assuming a full tank, find the smallest force P (kN)required to tip the tank.

A. 11.81

B. 14.35

C. 5.91

D. 7.18

Find the smallest coefficient of static friction u (sub) s

A. 0.17

B. 0.13

C. 0.23

D. 0.31

If force P = 6.5 kN initiates tipping determine the depth (m) of water in the tank.

A. 1.67

B. 0.85

C. 1.32

D. 1.45

<p>SITUATION. The weight of the cylindrical tank is negligible in comparison with the weight of water it contains (water weighs 9.81kN/m3). The coefficient of friction between the tank and the horizontal surface is u (sub) s.</p><p></p><p>Assuming a full tank, find the smallest force P (kN)required to tip the tank.</p><p>A. 11.81</p><p>B. 14.35</p><p>C. 5.91</p><p>D. 7.18</p><p>Find the smallest coefficient of static friction u (sub) s</p><p>A. 0.17</p><p>B. 0.13</p><p>C. 0.23</p><p>D. 0.31</p><p>If force P = 6.5 kN initiates tipping determine the depth (m) of water in the tank.</p><p>A. 1.67</p><p>B. 0.85</p><p>C. 1.32</p><p>D. 1.45</p>
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BDB

SITUATION. A spiral column 600 mm in diameter has an unsupported height of 3m. The column is bent in single curvature and is braced against sidesway.

Given:

Concrete compressive strength, fc’=20.7 MPa

Steel yield strength, fy=413 MPa

Effective length factor, K=1.0

If the required steel ratio is 2%, find the number of 28 mm diameter bars.

A. 8

B. 10

C. 12

D. 14

If Pu=6400 kN, determine the number of 32 mm bars.

A. 24

B. 20

C. 22

D. 16

What is the slenderness ratio of the column?

A. 40

B. 20

C. 22

D. 46

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BAB

Determine the reaction at G.

A. 17.9

B. 11.2

C. 12.45

D. 4.15

Determine the stress (kN) in member AB.

A. 3.1(tension)

B. 3.1(compression)

C. 3.6(tension)

D. 3.6(compression)

Determine the stress (kN) in member BE.

A. 3.25(tension)

B. 0

C. 3.75 (tension)

D. 4.15(tension)

<p>Determine the reaction at G.</p><p>A. 17.9</p><p>B. 11.2</p><p>C. 12.45</p><p>D. 4.15</p><p>Determine the stress (kN) in member AB.</p><p>A. 3.1(tension)</p><p>B. 3.1(compression)</p><p>C. 3.6(tension)</p><p>D. 3.6(compression)</p><p>Determine the stress (kN) in member BE.</p><p>A. 3.25(tension)</p><p>B. 0</p><p>C. 3.75 (tension)</p><p>D. 4.15(tension)</p>
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CAD

SITUATION. A rectangular section 300 x 650 is simply supported on a span of 12m. It carries a dead load equal to self-weight and a live load of 6kN/m. An initial prestress force P = 1500kN is applied at an eccentricity of 100mm. Using 24kN/m3 as unit weight of concrete. Assume 20% loss at service loads.

Determine the stress at the bottom fiber at midspan due to final prestressing force alone.

A. -0.59

B. -0.47

C. -11.83

D. -14.79

Determine the stress at the top fiber at midspan due to self-weight and initial prestress force.

A. -4.58

B. -4.46

C. -10.81

D. -7.85

Determine the stress at the bottom fiber at midspan due to service loads and final prestress force.

A. -5.70

B. -9.57

C. -9.69

D. -2.73

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BCB

SITUATION. The bolt shown in the figure is subjected to a total tensile force of 100 kN.

Determine the tensile stress in the body of the bolt in MPa.

A. 141.47

B. 93.06

C. 132.49

D. 79.36

Determine the tensile stress at the root of the bolt in MPa.

A. 141.47

B. 93.06

C. 132.49

D. 79.36

Determine the compressive stress at the head as the bolt bears on the surface to resist the tensile load.

A. 32.08

B. 48.96

C. 57.07

D. 35.37

<p>SITUATION. The bolt shown in the figure is subjected to a total tensile force of 100 kN.</p><p></p><p>Determine the tensile stress in the body of the bolt in MPa.</p><p>A. 141.47</p><p>B. 93.06</p><p>C. 132.49</p><p>D. 79.36</p><p>Determine the tensile stress at the root of the bolt in MPa.</p><p>A. 141.47</p><p>B. 93.06</p><p>C. 132.49</p><p>D. 79.36</p><p>Determine the compressive stress at the head as the bolt bears on the surface to resist the tensile load.</p><p>A. 32.08</p><p>B. 48.96</p><p>C. 57.07</p><p>D. 35.37</p>
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ABA

SITUATION. A solid steel post that is free from one end and fixed from the other end is subjected to pure torsion

Given: Post diameter = 80 mm

Length = 3 m

Shear Modulus = 70 GPa

What is the torsional rigidity of the post (kN-m2)

A. 281.49 kN-m2

B. 235.15 kN-m2

C. 266.91 kN-m2

D. 224.67 kN-m2

Determine the torsional stiffness of the post.

A. 99.6 kN-m

B. 93.83 kN-m

C. 69.9 kN-m

D. 96.9 kN-m

Determine the maximum shear stress (MPa) in the post if it is subjected to a torque of 540 N.m.

A. 5.37 MPa

B. 6.15 MPa

C. 6.25 MPa

D. 5.61 MPa