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What are the 2 categories of carbonyl compounds?
aldehydes & ketones
carboxylic acids & derivatives
What kinds of reactions do Aldehydes & ketones undergo?
nucleophilic addition, H/R isn’t a good leaving group
What kinds of reactions do carboxylic acids & derivatives undergo?
nucleophilic substitution, R can be a good leaving group
What is the nature of a carbonyl?
O is electrophile, 2 lone pairs of electrons, partial negative
C is nucleophile, 3 sigma bonds & 1 pi = sp2, partial positive
shape = trigonal planar
bond angle around C = 120
polarized w/ partial charges
Reactions Seen by Carbonyls
nucleophilic addition
nucleophilic acyl substitutions
alpha substitutions
carbonyl condensations
Aldehyde Nomenclature
aldehydes = replace terminal -e of alkane name with -al
parent chain must have CHO, CHO =C1
CHO on ring = carbaldehyde
CHO is substituent on chain = formyl
Ketone Nomenclature
replace terminal -e of alkane with one
parent chain is longest one containing ketone
numbering starts at end closes to carbonyl C
substituent = prefix oxo
Unsystematic Names for Ketones/Aldehydes
R-C=O as a substituent = acyl group, used w/ suffix -yl from root of carboxylic acid
Preparing Aldehydes
Oxidize 1o alcohols w/ pyridinium chlorochromate/PCC (CH2OH → CHO)
oxidative cleave w/ ozone for alkenes w/ vinylic H
reduce ester w/ DIBAH (C-COOCH3 → CHO)
Preparing Ketones
oxidize 2o alcohol, many reagents possible
ozonolysis of alkenes (only if 1/both of unsaturated C atoms is disubstituted)
friedel-crafts acylation of aromatic ring w/ acid chloride, presence of AlCl3 catalyst
hydration of terminal alkynes in presence of Hg, makes methyl ketone
Oxidation of Aldehydes
1 H can be oxidized ONCE to a carboxylic acid
Oxidation of Ketones
0 H so can’t oxidize, can still get a -COOH group, no H directly attached
Aldehydes
CrO3 in aq acid (Jones’ Reagent) oxidizes aldehydes to carboxylic acids
Silver oxide/Ag2O in aq ammonia (Tollens’ reagent) oxidizes aldehydes (no acid)
Hydrates & Aldehydes
aldehyde oxidations occur through 1,1-diols/hydrates
aldehyde hydrate oxidized to carboxylic acid by usual reagents for alcohols
In Aldehyde oxidations, is adding water to the carbonyl group possible? Can it be reversed
Addition is possible, and reversible
Ketones making COOH
slow cleavage with/ hot alkaline KMnO4
C-C bond next to C=O broken to give carboxylic acids
only good for symmetrical ketones, unsymmetrical gives mixture of products
Nucleophile
electron rich species reacting w/ electron poor species (C=O)
(-) → OH-, H-, R3C-, RO-, N///C-
neutral → H2O, ROH, H3N, H2NR, H will be elim
Addition
implies 2 systems combine to give a single entity
How do nucleophilic addition reactions work?
nuc approaches 75o to the plane of C=O & adds to C
tetrahedral alkoxide ion intermediate produced
2 possible products!
protonation = make alcohol
carbonyl O elim as OH/H2O to give C=nuc
Aldehyde NAS
base catalyzed, strong nucleophile, anionic
nuc adds directly to C=O to make intermediate alkoxide, alkoxide is protonate on workup w/ dilute acid
nucs = RMgX, LiAlH4, NaBH4, Wittig Rxn [(Ph)3P+:CRH-]
Ketone NAS
acid catalyzed, weak nucleophile, neutral
C=O needs to be activated before nuc attack
nucs = H2O, ROH, RNH2
protonating carbonyl = structure redrawn in another resonance form, reveals electrophilic character of C since it’s a carbocation
Which is more reactive, aldehydes or ketones?
aldehydes, electronic & steric
steric = transition state for addition is less crowded, lower in energy for A, only H on it & 1 R group, ketone has 2 R groups, more things in the way, aldehydes have 1 large substituent on C=O, ketones have 2
electronic = less stabilization of partial positive, more reactive, ketone is more stabilized/less reactive through more alkyl groups stabilizing C=O’s C inductively
more alkyl groups stabilize + character
aldehyde C=O is more polarized than ketone C=O
aromatic aldehydes < aliphatic aldehydes (more reactive), e- donating resonance effect of ring makes C=O less reactive electrophile than carbonyl group of aliphatic aldehyde
Oxygen Nucleophiles
addition of water/hydration
addition of alcohols: acetal formation
addition of HCN: cyanohydrin formation
Hydration
makes 1,1 diols or germinal diols/hydrates, 2 OH groups on 1 C
hydrates not stable enough to be isolated, equilibrium shifts back to starting materials except for a few simple aldehydes
hydrates are the reactive species in the [O] of aldehydes to acids
reversible process, slow in pure water, catalyzed by A/B
B → nuc is OH-, stronger nuc than water
reaction of C=O w/ H-Y (Y= EN-) gives addition product/adduct, reversible formation
Acetal Formation
nuc add then nuc sub
reversible
add 1 eq of alcohol = hemiacetal/hemiketal (ac=aldehyde, ket=ketone)
add 2 eq of alcohol = acetal/ketal
1,1-germinal diethers
catalyzed only by acidic conditions
acetals → used in carbs, also protecting groups
equilibrium shifted to acetal → excess use of alcohol or removing water as it forms
can use 1,2 or 1,3 diols to make cyclic acetals
stable to strong bases & nucleophiles
acetals can be converted to aldehyde/ketone by heating w/ aqueous acid
Cyanohydrin Formation
H-C///N (H cyanide) is toxic, reacts slowly
small amount of base added → N///C- nuc made, base catalyzed addition (also use KC///N, NaC///N)
react to make cyanohydrins RCH(OH)C///N
add CN to C=O makes tetrahedral intermediate, which is protonated
equilibrium favors adduct
reactivity: formaldehyde > other aldehydes > ketones
ketones hindered by large alkyl groups react slowly, give poor % yields
useful as precursors
reduced by LiAlH4 to give 1o amines (RCH2NH2)
hydrolyzed by hot aqu
Nuc Addition of Grignard & Hydride Reagents
treat aldehyde/ketone w/ grig reagent = alcohol
nuc add of eq of carbanion, C-Mg is polarized, so reacts practically (R-, MgX+)
irreversible, carbanion is a poor leaving group
What happens when a grignard reagent is added to aldehydes/ketones?
alcohols are made
Formaldehyde (H2C=O) → 1o alcohol
Aldehydes (RCHO) → 2o alcohol
Ketones (RR’CO) → 3o alcohol
Hydride Addition/Reduction
2 H atoms added across C=O to give H-C-O-H
LiAlH4 & NaBH4 = donors of hydride ion
rxn usually in Et2O or THF followed by H3O+ workups
protonation after addition yields alcohol
aldehyde = 1o alcohol
ketone = 2o alcohol
Forming Imines & Enamines: Primary Amines
reaction type → nuc addition then elim
primary amines, R-NH2, or ArNH2 give carbinolamines
dehydrate to give substituted imines
rxn done in acidic buffer (pH 4.4) to activate C=O, help dehydration w/o inhibiting nucelophile
VERY acidic/basic = VERY slow rxn
Forming Imines & Enamines: Secondary Amines
reaction type → nuc addition then elim
R2NH gives carbinolamines, dehydrate to give enamines
enamines = alkene amines
carbinolamine can only elim to give C=C since no N-H in carbinolamine
Why do carbinolamines only give C=C with eliminating?
no N-H in carbinolamine
need slightly acidic so carbinolamine o can be protonated to become a good leaving group (H2O)
too acidic =amine becomes protonated, rxn can’t occur
Mechanism of Forming Imines
primary amine adds to C=O
proton lost from N, adds to O → carbinolamine
protonate OH → convert to water as leaving group
result = iminium ion, loses proton
acid required for loss of OH, too much acid blocks RNH2, why the acidic buffer is there, reaction goes but it’s not too much
Carbinolamine
neutral amino alcohol
Imine Derivatives
adding amines w/ atom containing LP on adjacent atom, occurs readily, gives stable imines
hydroxylamine (NH2OH) → makes oximes
2,4-dinitrophenylhydrazine → 2,4-dinitrophenylhydrazones
semicarbazide (NH2NH CONHS)
Mechanism of Formation of Enamine
starts off same as imine formation
after adding R2NH, proton is lost from adjacent C
Wittig Reaction
nucleophilic addition of phosphorous ylides
nuc add then elim
C=O → C=C
phosphorous ylide adds to aldehyde/ketone → betaine
betaine decomposes through ring → alkene & triphenylphosphine oxide [(Ph)3P=O]
= made at location of og aldehyde/ketone
NO ALKENE ISOMERS MADE (only E/Z)
Betaine
dipolar intermediate in Wittig Reaction, formed when a phosphonium ylide reacts with a carbonyl compound.
For which alkenes can the Wittig Reaction be used for?
monosub, disub, & trisubstituted alkenes, makes pure alkene
NO TETRA = too sterically hindered
Planning a Wittig
divide target mol at C=C bond
½ becomes ketone/aldehyde, other is ylide
ylide need to be unhindered, so is 1o