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lattice enthalpy
enthalpy change of formation of 1 mole of ionic lattice from its gaseous ions
K+ (g) + F- (g) → KF (s)
-is exothermic = more exothermic → more stronger ionic bonds
standard enthalpy change of formation
enthalpy change when 1 mole of a compound is formed from its elements under standard conditions
Na (s) + ½ Cl2 (g) → NaCl (s)
first ionisation energy
enthalpy change when 1 electron is removed from each atom in 1 mole of gaseous atoms to form 1 mole of gaseous 1+ ions
-always endothermic = energy supplied to remove negative electron from the attraction to positive nucleus
-second ionisation energy is more endothermic as electron is closer to nucleus so greater attraction
standard enthalpy change of atomisation
enthalpy change of formation of 1 mole of gaseous atoms from element in its standard state under standard conditions
½ Cl2 (g) → Cl (g)
-is always endothermic = energy needs to be supplied to break bonds between molecules into atoms or into a gas
first electron affinity
enthalpy change when 1 electron is added to each atom in 1 mole of gaseous atoms to form gaseous 1- ions
-is exothermic = electron being added is attracted in towards the nucleus
-BUT second electron affinity is endothermic = negative electron being added to negative ion so energy required to overcome repulsion
method for Born-Haber Cycle
lattice enthalpy:
g = a-b-c-d-e-f
-need to multiply values by 2 if there are 2 moles of a substance
factors that affect LATTICE ENTHALPY + HYDRATION
-greater ionic charge
-smaller ionic size/radius
-both lead to stronger attractions between the ions so leads to a more negative/exothermic value
standard enthalpy change of solution
enthalpy change when 1 mole of a solute completely dissolves in water under standard conditions
MgBr2 (aq) + aq → Mg2+ (aq) + 2Br- (aq)
-energy is taken in to break ionic bonds, new attractions formed between ions and water, cations and S- dipole of H2O, anions and S+ dipole of H2O
-overall endothermic = more energy being taken in to break bonds than released to make bonds
-overall exothermic = vice versa
standard enthalpy of hydration
enthalpy change when 1 mole of gaseous ions are dissolved in water to form 1 mole of aqueous ions under standard conditions
K+ (g) + aq → K+ (aq)
-always exothermic = energy is released when attractions to water molecules are made
calculation for enthalpy change of solution cycles + experiment
sum of lattice enthalpy + solution = sum of the enthalpy changes of hydration
Q = mcT