Calculating gas volumes: 4.3.5 Use of amount of substance in relation to volumes of gases (chemistry only) (HT only): AQA Q&A: GCSE (9:1)

0.0(0)
studied byStudied by 0 people
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
Card Sorting

1/11

encourage image

There's no tags or description

Looks like no tags are added yet.

Study Analytics
Name
Mastery
Learn
Test
Matching
Spaced

No study sessions yet.

12 Terms

1
New cards

the pressure inside will be the same each container

Two separate containers contain equal volumes of argon and carbon dioxide gas. Both containers are at the same temperature. What will be true about the two containers?

2
New cards

480 dm³

What is the volume occupied by 20 moles of propane gas at RTP?

3
New cards

7.68 dm³

What is the volume occupied by 0.32 moles of hydrogen gas at RTP?

4
New cards

4.8 dm³

What is the volume occupied by 4 grams of neon (Ar = 20)?

5
New cards

600 cm³

What is the volume occupied by 1.1 grams of carbon dioxide (Mr = 44)?

6
New cards

16.8

What is the mass in grams of 14.4 dm³ of nitrogen gas (Mr = 28)?

7
New cards

0.8

What is the mass in grams of 1200 cm³ methane gas (Mr = 16)?

8
New cards

4.8 dm³

What volume of carbon dioxide can be made from the decomposition of 20 grams of calcium carbonate? (Mr CaCO₃ = 100)?

CaCO₃ → CO₂ + CaO

9
New cards

2.4 dm³ (rtp, previously answer was 4.4 but i think its wrong)

What volume of oxygen can be made from the decomposition of 6.8 grams of hydrogen peroxide (Mr H₂O₂ = 34)?

2H₂O₂ → 2H₂O + O₂

10
New cards

10 dm³

What volume of oxygen would be needed to completely react with 2 dm³ of propane gas?

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

11
New cards

36 dm³

What volume of hydrogen would be needed to completely react with 14 grams of nitrogen?

N₂ + 3H₂ → 2NH₃

12
New cards

100 dm³

2 dm³ of oxygen is required to completely combust 1 dm³ of methane gas. If we approximate air to contain 20% oxygen, what volume of air would be needed to react with 10 dm³ methane?