Energy Balance and Concentration Dynamics

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Vocabulary flashcards reviewing key concepts, mathematical definitions, and mass balance principles covered in the lecture transcript.

Last updated 4:43 PM on 9/8/26
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10 Terms

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Well-Mixed Assumption

A classical modeling assumption that the salt concentration throughout the liquid inside a tank is completely uniform at any given moment.

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Initial Tank Salt Concentration

The salt concentration in the tank at time t=0t = 0, calculated as 2kg2\,\text{kg} of salt divided by 40L40\,\text{L} of liquid, which equals 0.05kgL10.05\,\text{kg\,L}^{-1}.

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Inlet Salt Concentration

The constant salt concentration of the incoming fluid stream, specified as 0.3kgL10.3\,\text{kg\,L}^{-1}.

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Concentration Gap

The numerical difference between the inlet salt concentration and the tank salt concentration, which drives the exponential rate of concentration change over time.

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Mass Balance Case 1

A system state where mass input (1kgs11\,\text{kg\,s}^{-1}) equals mass output (1kgs11\,\text{kg\,s}^{-1}), resulting in zero net change of mass within the system boundary.

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Mass Balance Case 2

A system state where mass input (2kgs12\,\text{kg\,s}^{-1}) exceeds mass output (1kgs11\,\text{kg\,s}^{-1}), resulting in a net mass accumulation of 1kgs11\,\text{kg\,s}^{-1} inside the system boundary.

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Mass Balance Case 3

A system state where mass output (5kgs15\,\text{kg\,s}^{-1}) exceeds mass input (2kgs12\,\text{kg\,s}^{-1}), resulting in a net mass reduction of 3kgs13\,\text{kg\,s}^{-1} inside the system boundary.

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Governing Differential Equation

An ordinary differential equation (ODE) formulated from mass balance principles to describe the continuous time-dependent rate of change of salt mass inside the tank.

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Tank Filling Duration

The time required to fill an empty 40L40\,\text{L} tank at a volume flow rate of 0.15Ls10.15\,\text{L\,s}^{-1}, calculated as approximately 266.67s266.67\,\text{s}.

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Steady-State Salt Mass

The maximum upper bound of salt mass in the 40L40\,\text{L} tank as time approaches infinity, calculated as 0.3kgL1×40L=12kg0.3\,\text{kg\,L}^{-1} \times 40\,\text{L} = 12\,\text{kg}.