Find the x-intercepts of a parabola by factoring

0.0(0)
studied byStudied by 1 person
0.0(0)
full-widthCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/4

encourage image

There's no tags or description

Looks like no tags are added yet.

Study Analytics
Name
Mastery
Learn
Test
Matching
Spaced

No study sessions yet.

5 Terms

1
New cards

How to find the x-intercepts of a parabola if a = 1 (Example: y = x² - 6x +5)

  1. Find two numbers with a sum of b and a product of c. (-1,-5)

  2. Each number + x should equal 0, solve for x. [x + (-1)] = 0 (x = 1), [x + (-5)] = 0 (x = 5)

  3. Convert into corrdinates (1,0), (5,0)

2
New cards

Find the x-intercept of a parabola if a ≠ 0 (example: 2x² + 7x + 3)

  1. Multiply a • c (2 • 3)

  2. Find two number (p and q) that have a product of ac and a sum of b. (6,1)

  3. Re-write the middle term as px and qx (6x and 1x)

  4. Group the four terms into 2 pairs [(2x²+6x)+(1x+3)]

  5. Factor both groups individually by the GCF

2x(2x²+6x) = (x + 3)

1(1x + 3) = (x + 3)

New expression: 2x(x+3)+1(x+3)

  1. Factor the two terms (by (x + 3)

Fully factored: (2x+1)(x+3) = 0

  1. Solve each term for x individually

Case 1: 2x + 1 = 0 → 2x = -1 → x = -1/2

Case 2: x + 3 = 0 → x = -3

3
New cards

Find the x-intercept of a parabola if a ≠ 0 (example: 2x² + 7x + 3)

  1. Multiply a • c (2 • 3)

  2. Find two number (p and q) that have a product of ac and a sum of b. (6,1)

  3. Re-write the middle term as px and qx (6x and 1x)

  4. Group the four terms into 2 pairs [(2x²+6x)+(1x+3)]

  5. Factor both groups individually by the GCF

2x(2x²+6x) = (x + 3)

1(1x + 3) = (x + 3)

New expression: 2x(x+3)+1(x+3)

  1. Factor the two terms (by (x + 3)

Fully factored: (2x+1)(x+3) = 0

  1. Solve each term for x individually

Case 1: 2x + 1 = 0 → 2x = -1 → x = -1/2

Case 2: x + 3 = 0 → x = -3

4
New cards

How to find the x-intercepts of a parabola if a = 1 (Example: y = x² - 6x +5)

  1. Find two numbers with a sum of b and a product of c. (-1,-5)

  2. Each number + x should equal 0, solve for x. [x + (-1)] = 0 (x = 1), [x + (-5)] = 0 (x = 5)

  3. Convert into corrdinates (1,0), (5,0)

5
New cards

:D

:)