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energy of a hydrogen atom
energy is directly proportional to -1/quantum number squared
it is negative because it is an attractive situation
emission spectrum of hydrogen - key concepts
each line in the spectrum corresponds to an electronic transition between 2 energy levels
each level has energy E=-RH/n2
emission spectrum of hydrogen - practical
pass light through a prism to break it up into individual wavelengths
the light does not form a continuous spectrum - it forms a series of single wavelengths
for hydrogen, in visible region there are 4 lines which is given by equation:
1/wavelength = wavenumber = k(1/4-1/n2) where k is a constant and n=3, 4, 5, 6
Balmer series
experiment which allows us to map out energy levels
from 6p/5p/4p/3p to 2s where 2s is the lowest energy wavefunction
2s and 2p all have same energy for H
infinite energy is at 0 - this is a proton with an electron that doesn’t know about the proton so there are no waves
general form of equation for all lines in UV and IR regions
1/lamda = wavenumber = RH(1/m2-1/n2) where m and n are integers
explanation for 4 lines in visible region of hydrogen emission spectrum
electric discharge on H2 breaks the bond to give 2 excited state (high energy) H atoms
High energy H atoms lose energy and become low energy
As this transition takes place, excess energy is given out as a photon