Physics 2212

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Last updated 3:44 AM on 7/21/26
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34 Terms

1
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term image

B

2
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term image

B

3
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John Travoltage -- When Jonnie rubs his foot on the carpet in his new apartment, he picks up some charges.  If he just rubs his foot on the carpet a few times and keeps his hand away from the doorknob, how will these charges behave?

The charges will mostly stay clustered near his foot.

The charges will spread out somewhat uniformly throughout his body (uniform density).

The charges will move between his finger and the doorknob, creating a spark and giving Jonnie a shock.

The charges will spread out somewhat uniformly over the surface of his body

The charges will mostly cluster at the tip of his outstretched index finger.

The charges will spread out somewhat uniformly over the surface of his body.

4
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When somebody's hair stand up after sliding on a playground, this is because

Question options:

hair experiences triboelectricity

the human is a charged conductor and hair is movable

hair is not conducting electricity

the human is an insulator and hair is in electric breakdown

the human is a charged conductor and hair is movable

5
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Consider a plastic rod that is being charged up by rubbing a wool cloth. It is then brought to an initially neutral metallic sphere, and allowed to touch the sphere for a few seconds. The rod is then separated from the sphere by a small distance. After becoming separated, the rod

Question options:

is repelled by the sphere

is attracted to the sphere

experiences no force due to the sphere

is repelled by the sphere

6
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After brushing your hair, you can use your comb to pick up pieces of paper, because

Question options:

the hair is a charged conductor and is movable and the pieces of paper too

the charged comb charges the pieces of paper through electric breakdown of air

the comb is charged by triboelectric effect and the paper is polarized and is attracted to the charged comb

both the paper and the comb are charged oppositely

the comb is charged by triboelectric effect and the paper is polarized and is attracted to the charged comb

7
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An electroscope is positively charged by touching it with a positive glass rod. The electroscope leaves spread apart and the glass rod is removed. Then a negatively charged plastic rod is brought close to the top of the electroscope, but it doesn’t touch. What happens to the leaves?

Question options:

The leaves spread further apart.

The leaves don't move

One leaf moves higher, the other lower

The leaves get closer together.

The leaves get closer together.

8
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term image

B

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What can be used to sense the electric field created by aluminum electrodes placed in water?

Question options:

electroscope

fur

LED (light-emitting diode)

plastic rod

LED (light-emitting diode)

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term image

A

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<p>Answer Choices: Surface A, Surface B, Not enough information to tell, They have the same electric field</p>

Answer Choices: Surface A, Surface B, Not enough information to tell, They have the same electric field

They have the same electric field

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<p>0, 200 N m/C, 400N m²/C, Some other Value</p><table style="min-width: 50px;"><colgroup><col style="min-width: 25px;"><col style="min-width: 25px;"></colgroup><tbody><tr><td colspan="1" rowspan="1"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>400 N m^2/C</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p></p></td></tr></tbody></table><p></p>

0, 200 N m/C, 400N m²/C, Some other Value

400 N m^2/C

0

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<table style="min-width: 50px;"><colgroup><col style="min-width: 25px;"><col style="min-width: 25px;"></colgroup><tbody><tr><td colspan="1" rowspan="1"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>Surface A</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>Surface B</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>Surface C</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>Surfaces B and C</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>All three surfaces</p></td></tr></tbody></table><p></p>

Surface A

Surface B

Surface C

Surfaces B and C

All three surfaces

Surface A

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<table style="min-width: 50px;"><colgroup><col style="min-width: 25px;"><col style="min-width: 25px;"></colgroup><tbody><tr><td colspan="1" rowspan="1"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>Surface B has more flux</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p>=</p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>Surface A has more flux</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>It's impossible to say without knowing more about the electric field</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>The fluxes are equal</p></td></tr></tbody></table><p></p>

Surface B has more flux

=

Surface A has more flux

It's impossible to say without knowing more about the electric field

The fluxes are equal

Surface A has more flux

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<table style="min-width: 50px;"><colgroup><col style="min-width: 25px;"><col style="min-width: 25px;"></colgroup><tbody><tr><td colspan="1" rowspan="1"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p><br>Flux isn't defined for an open surface.</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>400 N m^2/C</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>200 N m/C</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>0</p></td></tr></tbody></table><p></p>


Flux isn't defined for an open surface.

400 N m^2/C

200 N m/C

0

400 N m²/C

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A conductor carries a net charge of +Q.  A cavity within the conductor contains a point charge of −Q.  What is the charge on the outer surface of the conductor in electrostatic equilibrium?

Question options:

–Q

+Q

+2Q

0

0

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Consider a charge q placed on the x axis at x = 2 R and a sphere with radius R centered at the origin. What is the flux through the sphere?

Question options:

0

-2q/epsilon_0

2q/epsilon_0

-q/epsilon_0

0

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D

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<p>Question options:</p><table style="min-width: 50px;"><colgroup><col style="min-width: 25px;"><col style="min-width: 25px;"></colgroup><tbody><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>0 V</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>Undefined</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>6 V</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>3 V</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>Not enough information to tell&nbsp;</p></td></tr></tbody></table><p></p>

Question options:

0 V

Undefined

6 V

3 V

Not enough information to tell 

3V

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<p>Question options:</p><table style="min-width: 50px;"><colgroup><col style="min-width: 25px;"><col style="min-width: 25px;"></colgroup><tbody><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>1/3</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>Undefined without knowing the charge</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>9</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>3</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>1/9</p></td></tr></tbody></table><p></p>

Question options:

1/3

Undefined without knowing the charge

9

3

1/9

1/3

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The electric potential inside a parallel-plate capacitor

Question options:

decreases inversely with the square of the distance from the negative plate

decreases inversely with distance from the negative plate

increases linearly from the negative to the positive plate

is constant

decreases linearly from the negative to the positive plate

increases linearly from the negative to the positive plate

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<p>As they do,</p><p>Question options:</p><table style="min-width: 50px;"><colgroup><col style="min-width: 25px;"><col style="min-width: 25px;"></colgroup><tbody><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>A positive potential energy becomes a negative potential energy</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>A positive potential energy becomes less positive</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>A negative potential energy becomes less negative</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>A negative potential energy becomes more negative</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>A positive potential energy becomes more positive</p></td></tr></tbody></table><p></p>

As they do,

Question options:

A positive potential energy becomes a negative potential energy

A positive potential energy becomes less positive

A negative potential energy becomes less negative

A negative potential energy becomes more negative

A positive potential energy becomes more positive

A negative potential energy becomes more negative.

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<table style="min-width: 50px;"><colgroup><col style="min-width: 25px;"><col style="min-width: 25px;"></colgroup><tbody><tr><td colspan="1" rowspan="1"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>A</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>B</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>C</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>D</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>E</p></td></tr></tbody></table><p></p>

A

B

C

D

E

C

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The turning point for two point charges occurs when

Question options:

E_total = m v^2/2 + k (q1 q2)/r

E_total = m v^2/2 + k (q1 q2)/r^2

E_total = k (q1 q2)/r^2

E_total = k (q1 q2)/r

Etotal​=k(q1​q2​)/r

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<table style="min-width: 50px;"><colgroup><col style="min-width: 25px;"><col style="min-width: 25px;"></colgroup><tbody><tr><td colspan="1" rowspan="1"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p><br>vf &gt; vi</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>vf = vi</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>vf &lt; vi</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>Not enough information to compare the speeds at these points&nbsp;</p></td></tr></tbody></table><p></p>


vf > vi

vf = vi

vf < vi

Not enough information to compare the speeds at these points 

vf > vi

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<p>Afterward, the proton&nbsp;</p><p>Question options:</p><table style="min-width: 50px;"><colgroup><col style="min-width: 25px;"><col style="min-width: 25px;"></colgroup><tbody><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>remains at rest at B</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>moves toward A with an increasing speed</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>moves toward C with a steady speed</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>moves toward A with a steady speed</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>moves toward C with an increasing speed</p></td></tr></tbody></table><p></p>

Afterward, the proton 

Question options:

remains at rest at B

moves toward A with an increasing speed

moves toward C with a steady speed

moves toward A with a steady speed

moves toward C with an increasing speed

moves toward A with an increasing speed

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<table style="min-width: 50px;"><colgroup><col style="min-width: 25px;"><col style="min-width: 25px;"></colgroup><tbody><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>Vd = Ve &gt; Vc &gt; Va = Vb</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>Vb = Vc = Ve &gt; Va = Vd</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>Va = Vb = Vc = Vd = Ve</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>Va = Vb &gt; Vc &gt; Vd = Ve</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>Va = Vb = Vd = Ve &gt; Vc</p></td></tr></tbody></table><p></p>

Vd = Ve > Vc > Va = Vb

Vb = Vc = Ve > Va = Vd

Va = Vb = Vc = Vd = Ve

Va = Vb > Vc > Vd = Ve

Va = Vb = Vd = Ve > Vc

Va = Vb > Vc > Vd = Ve

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If the electric field at a certain point is zero, then the electric potential at that point

Question options:

must be zero

We cannot tell what the potential is from the given information

must be positive

must be negative

We cannot tell what the potential is from the given information.

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<p>Which of these two could represent the field of a point charge?</p><p>Question options:</p><table style="min-width: 50px;"><colgroup><col style="min-width: 25px;"><col style="min-width: 25px;"></colgroup><tbody><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>(a)</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>(b)</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>neither (a) nor (b)</p></td></tr></tbody></table><p></p>

Which of these two could represent the field of a point charge?

Question options:

(a)

(b)

neither (a) nor (b)

A

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<table style="min-width: 50px;"><colgroup><col style="min-width: 25px;"><col style="min-width: 25px;"></colgroup><tbody><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>Charge A</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>Charge B</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>They have the same potential energy</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>Both have zero potential energy</p></td></tr></tbody></table><p></p>

Charge A

Charge B

They have the same potential energy

Both have zero potential energy

Charge B

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<table style="min-width: 50px;"><colgroup><col style="min-width: 25px;"><col style="min-width: 25px;"></colgroup><tbody><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>Same charge</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>Both A and B</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>Same potential</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>Both A and C</p></td></tr><tr><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: middle; white-space: nowrap; flex-wrap: nowrap;"><p></p></td><td colspan="1" rowspan="1" style="padding: 3px; text-align: left; vertical-align: bottom; white-space: normal; flex-wrap: wrap; width: 870.9px;"><p>Same electric field</p></td></tr></tbody></table><p></p>

Same charge

Both A and B

Same potential

Both A and C

Same electric field

Same potential

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As an electron moves from higher potential to lower potential, its electrical potential energy

Question options:

increases

decreases

stays the same

increases

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