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Molarity Solution (equation) =
(moles solute) / (L solution) or (moles of solution) / (1000 mL solution)
Dilution Equation:
Mc x Vc = Md x Vd
- where Mc and Md are the molarity of the concentrated solution, and Vc and Vd are the volumes of the two solutions.
strong acids:
Hydrochloric: (HCl)
Hydrobromic: (HBr)
Hydroiodic: (HI)
Chloric: (HClO3)
Perchloric: (HClO4)
Nitric: (HNO3)
Sulfuric: (H2SO4)
strong bases:
Group 1A metal hydroxides
Heavy group 2A metal hydroxides (Ca(OH)2 and down).
Assigning Oxidation States:
1). The oxidation state of an atom in a free, uncombined element = 0
2). The sum of oxidation numbers of all atoms must equal the total charge [neutral=0,
ion=charge]
3). In compounds, Group IA = +1(not including H), IIA = +2, B and Al = +3, F = -1
4). In compounds, H = +1
5). In compounds, O = -2
6). In their binary compounds with metals, VIIA=-1, VIA=-2, VA=-3
- Highest order rule takes precedence -
Balancing Redox Reactions:
[Note – this method leaves spectator ions out.]
1) Divide the reaction into half reactions
2) Balance all atoms in half reactions except “H” and “O”
3) Balance “O” by adding H2O
4) Balance “H” by adding H+
5) Balance each half reaction electronically by adding e-
6) Multiply each half reaction by an integer to get electrons in each half reaction to
be the same
7) Acidic solutions: Combine the two half reactions, canceling anything that is the
same on both sides of the arrow
Basic solutions: Add OH- to both sides of the reaction to balance the H+
. H+ +
OH- will yield H2O, then add the two half reactions
∆E = ?
∆E =
Efinal - Einitial
Eproducts - Ereactants
∆Esystem = ?
∆Esystem = w + q
w = ?
w = -P∆V,
-P = Pressure, typically atmosphereic pressure
∆V = Change in volume, typically volume occupied by gasses produced in a chemical reaction.
Enthlapy is…
∆H = ∆E + P∆V
… the sum of all the heat and all the work that occur during a reaction
∆H = change in enthalpy
enthalpy requires that workbe P∆V work at constant pressure.
If no work is done, then the ∆E for the reaction is equal to the ∆H.
Q = ?
Q = Csm∆T
qrxn = ?
qrxn = -Ccal∆T
∆H°rxn = ?
∆H°rxn = Σn∆H°f(products) - Σm∆H°f(reactants)