Calculus Derivative Evaluation using Chain Rule

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Vocabulary flashcards covering key definitions, derivatives, and formulas from the provided calculus problem.

Last updated 7:45 PM on 9/15/26
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7 Terms

1
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Given Function yy

The algebraic composite function defined in the problem as y=(x22x9)4y = (x^2 - 2x - 9)^4.

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Inner Function uu

The substituted inner variable defined as u=x22x9u = x^2 - 2x - 9 to facilitate differentiation via the chain rule.

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Derivative dydu\frac{dy}{du}

The derivative of y=u4y = u^4 with respect to uu, calculated as 4u34u^3.

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Derivative dudx\frac{du}{dx}

The derivative of u=x22x9u = x^2 - 2x - 9 with respect to xx, calculated as 2x22x - 2.

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Chain Rule Formula

The differentiation formula expressed in the solution as dydx=dydududx\frac{dy}{dx} = \frac{dy}{du} \frac{du}{dx}.

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Derivative Function dydx\frac{dy}{dx}

The full derivative with respect to xx, expressed as 4(x22x9)3(2x2)4(x^2 - 2x - 9)^3(2x - 2).

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Evaluated Derivative at x=2x = -2

The numerical result of substituting x=2x = -2 into the derivative, resulting in 4(1)3(6)=244(-1)^3(-6) = 24.