UMD STAT 400 ( copy)

0.0(0)
Studied by 0 people
call kaiCall Kai
Locked
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/21

encourage image

There's no tags or description

Looks like no tags are added yet.

Last updated 5:39 PM on 7/7/26
Name
Mastery
Learn
Test
Matching
Spaced
Call with Kai
Chat

No analytics yet

Send a link to your students to track their progress

22 Terms

1
New cards

Sample Space

The set of all possible outcomes of an experiment, denoted by S

2
New cards

Union

All outcomes in either A, B, or both A and B. Denoted P(A ∪ B),

3
New cards

Intersection

All outcomes in both A and B. Denoted P(A ∩ B)

4
New cards

Complement

Set of all outcomes not contained in A. Denoted P(A')

5
New cards

Null

No outcomes. Denoted ¤

6
New cards

Mutually Exclusive

If P(A ∩ B) = ¤, they are said to be mutually exclusive, for they share no outcomes

7
New cards

Simple Probability Formula

Number of wanted (favorable) outcomes / Number of total outcomes

8
New cards

Empirical Probability

Ratio of number of event occurrences to the number of trials

9
New cards

Relative Frequency

Same as empirical probability

10
New cards

Axioms of Probability

1. P(A) ≥ 0

2. P(S) = 1

3. A1, A2, ... infinite disjoint events: P(A1 ∪ A2...) = Summation

11
New cards

P(A ∪ B) = ?

P(A) + P(B) - P(A ∩ B)

12
New cards

P(A ∪ B ∪ C) = ?

P(A) + P(B) + P(C) - P(A ∩ B) - P(A ∩ C) - P(B ∩ C) + P(A ∩ B ∩ C)

13
New cards

Tree Diagram

Used

14
New cards

Permutation

Ordered Subset (e.g. poker straight

15
New cards

Combination

Unordered Subset (e.g. poker three of a kind)

16
New cards

n choose k = ?

n! / k! (n - k)!

17
New cards

Conditional Probability

Probability of A given B. Denoted P(A | B)

18
New cards

P(A | B) = ?

P(A ∩ B) / P(B)

19
New cards

Multiplication Rule

P(A ∩ B) = P(A | B) * P(B)

20
New cards

Bayes' Theorem

When mutually exclusive, and P(B) = 0, P(Aj | B) = P(Aj ∩ B) / P(B)

21
New cards

Independence of Events

P(A | B) = P(A); B has no bearing on events

22
New cards

P(A ∩ B) = ?

P(A)P(B) only when both are independent