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∫ kekx dx
∫ kekx dx = kekx + c
∫ - kekx dx
∫ - kekx dx = - kekx + c
∫ x-1 dx
∫ x-1 dx = ln|x| + c
∫ cosx dx
∫ cosx dx = sinx + c
∫ sinx dx
∫ sinx dx = - cosx + c
∫ - cosx dx
∫ - cosx dx = - sinx + c
∫ - sinx dx
∫ - sinx dx = cosx + c
∫ sec2x dx
∫ sec2x dx = tanx + c
∫ - sec2x dx
∫ - sec2x dx = - tanx + c
∫ cosec2x dx
∫ cosec2x dx = - cotx + c
∫ - cosec2x dx
∫ cosec2x dx = cotx + c
∫ cosecxcotx dx
∫ cosecxcotx dx = - cosecx + c
∫ - cosecxcotx dx
∫ - cosecxcotx dx = cosecx + c
∫ secxtanx dx
∫ secxtanx dx = secx + c
∫ - secxtanx dx
∫ - secxtanx dx = - secx + c
trapezium rule;
∫ba y dx ≈ ?
∫ba y dx ≈ ½ h (y0 + 2 (y1 + y2 + … + yn-1) + yn)
h = (b - a) / n
n = number of columns (number of strips -1)
yi = f (a + ih)
what is h in the trapezium rule?
h = (b - a) / n
∫ba y dx
n = number of columns (number of strips -1)
what is n in the trapezium rule?
n = number of columns (number of strips -1)
what values can we not integrate?
sin2x
cos2x
cot2x
sinxcosx
how do we integrate values we can’t integrate?
rewrite them using trig identities
how do you integrate sin2x ?
here
∫ sin2x dx
∫ sin2x dx = ½ x - ¼ x cosx + c
how do you integrate cos2x ?
here
∫ cos2x dx
here
how do you integrate cot2x ?
here
∫ cot2x dx
here
how do you integrate sinxcosx ?
here
∫ sinxcosx dx
here
INTEGRATION BY PARTS
∫ ab dx
∫ uv’ = uv - ∫ vu’
PRODUCT RULE
y = uv
dy / dx = vu’ + uv’
QUOTIENT RULE
y = u/v
dy / dx = (vu’ - uv’) / v2
∫ tanx dx
∫ tanx dx = ln|secx| + c
∫ - tanx dx
∫ - tanx dx = - ln|secx| + c
∫ secx dx
∫ secx dx = ln|secx + tanx| + c
∫ - secx dx
∫ - secx dx = - ln|secx + tanx| + c
∫ cotx dx
∫ cotx dx = ln|sinx| + c
∫ - cotx dx
∫ - cotx dx = - ln|sinx| + c
∫ cosecx dx
∫ cosecx dx = - ln|cosecx + cotx| + c
∫ - cosecx dx
∫ - cosecx dx = ln|cosecx + cotx| + c
how do you make a trapezium rule estimate more accurate?
using more strips
using more trapezia
what does x-1 differentiate to?
- x-2
what does ln x differentiate to?
x-1
which is the tangent?
here
which is the normal?
here
what is the gradient of the tangent?
same as the curve
what is the gradient of the normal?
negative reciprocal of the curve
parts of a circle here
how do you estimate the gradient at a particular point?
find coordinates at that point by putting into equation (if you don’t have them already)
draw a tangent at that point
pick two points - one being the point you draw the tangent at (x2 , y2), and the other being some point on the tangent (x1 , y1)
(y2 - y1) / (x2 - x1)
what is NOT estimating the gradient?
by using the first derivative
how do you hypothesis about the gradient of a curve when x = p?
find first derivative for gradient function
substitute x for p
what do you use (y2 - y1) / (x2 - x1) for?
finding the gradient of a point using points on the tangent drawn from the point
what do you use √ (y2 - y1)2 + (x2 - x1)2 for?
what do you say when asked to comment about the relationship between gradients?
as the points move closer to the particular point, A, where the gradient between two points are taken from, they tend towards the gradient at A
here
how can you deduce the gradient of a tangent at a particular point without having a graph?
here 12 a 3 b
12 a 4 b
what does h / δx represent in differentiation?
a small change in the value of x
how do we denote a small change in the value of x?
h / δx
how do you differentiate ax (x + b) ?
NOT using the chain rule. expand to ax2 + abx and then go from there lolz
how do you differentiate this 12c 2 j
how do you differentiate this 12c 4
12 d 7 c
12 e 7 b
12f challenge
when is the function increasing on the interval [a, b]?
f’(x) ≥ 0, when a < x < b
when is the function decreasing on the interval [a, b]?
f’(x) ≤ 0, when a < x < b
how do you notate strictly increasing / decreasing
> / <
(without the equals to)
how do you find the values of x where a function is increasing?
differentiate term for first derivation
f’(x) ≥ 0
solve for x
‘f(x) is decreasing when x ≥ a’
how do you find the values of x where a function is decreasing?
differentiate term for first derivation
f’(x) ≤ 0
solve for x
‘f(x) is decreasing when x ≤ a’
how do you do u-sub?
always start by differentiating the substitution, u = bla bla bla
see what you can replace / cancel out by rearranging your du / dx function. you must rearrange for dx anywayz to replace the dx in the original integral function
rewrite function in terms of u, leaving some unsubstituted if they be cancelled out by another function
expand brackets for integrate-able function
integrate with respect to u (bcuz it’s du now)
indefinite:
rmbr the + c ! (if indefinite)
now sub your substitution back in !
definite:
rewrite the limits by putting them into the substitution function, giving you ‘u’ limits
do not substitute the function back in. instead, substitute your u limits into the integrated function and voila
how do you rewrite the limits of an indefinite integral in u-sub?
by putting them in the substitution function
in u-sub, what does u2 differentiate to?
2u du / dx
in u-sub, what does √x differentiate to?
1 / (2 √x )
should you ever change the limit placement, even if your new limits (in u-sub) are not placed by size?
NO ! never change it.
what can you do when your denominator is a completing the square?
split it into two separate fractions with different denominators of each factor
how do you integrate the function x-1?
1 / differential of x function x ln x