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Brønsted-lowry acid
a species that donates a proton
e.g. HCl - equation = HCl → H+ + Cl-
Brønsted-lowry base
a species that accepts a proton
e.g. NH3 - equation = NH3 + H+ → NH4+
conjugate-base pairs
two species that can be interconverted by the transfer of a proton
-can have more than 1 pair in an equation
example of conjugate-base pairs: HNO2 ⇌ H+ + NO2-
HNO2 and NO2- are the conjugate base pair
-HNO2 is the acid as it donates a proton to form the conjugate base NO2-
-NO2- is the conjugate base as it accepts a proton to form the acid HNO2
monobasic acid, example: HNO3 (DO EQUATION)
an acid that can only donate 1 proton to a base
example: HNO3 - equation = HNO3 → H+ + NO3-
dibasic acid, example: H2SO4 (DO EQUATION)
an acid that can donate 2 protons to a base
example: H2SO4 - equations = H2SO4 → H+ + HSO4-
HSO4- ⇌ H+ + SO42-
equilibrium arrow used as weaker acid is produced (HSO4-)
tribasic acid, example: H3PO4 (DO EQUATION)
an acid that can donate 3 protons to a base
example: H3PO4 - equations = H3PO4 → H+ + H2PO4-
H2PO4- ⇌ H+ + HPO42-
HPO42- ⇌ H+ + PO43-
equilibrium arrow used as weaker acid is produced
reaction of metal with acid - full + ionic equation → HCl + Mg
2HCl(aq) + Mg(s) → MgCl2(aq) + H2(g)
2H+ + Mg → Mg2+ + H2
reaction of metal carbonate with acid - full + ionic equation → HCl + MgCO3
2HCl(aq) + MgCO3(s) → MgCl2(aq) + H2O(l) + CO2(g)
2H+ + MgCO3 → Mg2+ + H2O + CO2
-the carbonate is a solid so cannot dissociate into ions so remains undissolved
reaction of metal oxide with acid - full + ionic equation → HCl + MgO
2HCl(aq) + MgO(s) → MgCl2(aq) + H2O(l)
2H+ + MgO → Mg2+ + H2O
reaction of alkali with acid - full + ionic equation → HCl + NaOH
HCl + NaOH → NaCl + H2O
H+ + OH- → H2O
strong acid
completely dissociates in aqueous solution
e.g. HCl
pH scale + strong acids
-a negative logarithmic scale of conc of H+
strong acids = [H+(aq)] = [HA(aq)]
pH and H+ equations
pH = -log10[H+(aq)]
[H+(aq)] = 10-pH
weak acid
partially dissociates in aqueous solution
e.g. CH3COOH
acid dissociation constant
-for weak acids
for HA ⇌ H+ + A-
-expression: Ka = [H+] [A-] / [HA] → units = mol dm-3
Ka value
-larger Ka value means greater extent of dissociation so stronger weak acid - reverse for smaller
pKa and Ka equations
pKa = -log10Ka
Ka = 10-pKa
pKa value
-smaller pKa value means large Ka value so greater acid dissociation so stronger weak acid - reverse for larger
pH of weak acids
[H+(aq)] = √Ka x [HA(aq)]
limitations of scientific approximations
-assume that the acid is so weak that the conc at equilibrium = the same as the original conc
-but is actually [HA]equilibrium > [HA]original
-only works for weaker weak acids
water as amphoteric
-acts as an acid by donating a proton
-acts as a base by accepting a proton
deriving towards Kw
H2O ⇌ H+ + OH-
Ka = [H+][OH-] / [H2O] → Ka x [H2O] = [H+][OH-]
Kc is really small as water is a very weak acid so small amount of dissociation so [H2O] is constant
Kw equation + value
Kw = [H+][OH-] = 1 × 10-14 mol2 dm-6
for strong bases [A-] = [H+] or [OH-]
pOH and [OH-] equations
pOH = -log[OH-]
[OH-] = 10-pOH