case of the missing population variance

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Last updated 7:52 PM on 9/23/26
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20 Terms

1
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sampling distribution of s

distribution of s is skewed, in larger N, it will look more normal and vary less from σ; in smaller N, it will look less normal, vary more from σ

<p>distribution of s is skewed, in larger N, it will look more normal and vary less from σ; in smaller N, it will look less normal, vary more from σ</p>
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when we don’t know σ. why can’t you find SE of the (normal) sampling distribution of means using SE = s/√N

when sample size is small, the distribution will have fatter tail —> a larger proportion of sample means would be counted as extreme values than we expect

more likely to make Type I error (false rejection)

<p>when sample size is small, the distribution will have fatter tail —&gt; a larger proportion of sample means would be counted as extreme values than we expect</p><p>more likely to make Type I error (false rejection)</p>
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william gosset

  • worked at Guinness Brewing Company, did small-sample experiments in which he changed the ingredients in the beer recipe

  • published papers under the pseudonym “student” to avoid angering his employer

  • most famoous for discovering the t-distribution which accounts for the added uncertainty due to sampling variation in s


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how does the t-distribution account for added uncertainty due to sampling variation in s

adds an extra parameter: df, number of data points that can freely vary after accounting for estimated values

larger df: thinner tails, more similar to normal distribution

smaller df: fatter tails, less similar to normal distribution

  • fatter tails —> we need to move more SE away from the mean to include 95% of the dsitribution in the center



<p>adds an extra parameter: df, number of data points that can freely vary after accounting for estimated values</p><p>larger df: thinner tails, more similar to normal distribution</p><p>smaller df: fatter tails, less similar to normal distribution</p><ul><li><p>fatter tails —&gt; we need to move more SE away from the mean to include 95% of the dsitribution in the center</p></li></ul><p></p><p></p>
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calculate the t-statistic (one sample t-test)

t = (x̄-μ₀)/sx̄

where sx̄ = s/√N

df = N - 1

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assumptions of a t-test

  • the sampling distribution follows a normal distribution

  • the observations are independent

  • there are no outliers (influential data points not from our population, we have reason to believe they’re from a different population- not just because they stand out)

  • sampling was random


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numerical and normality checks

  • skewness and kurtosis (both = 0 in norm dist)

  • Kolmogorov-Smirnov (KS) test, Shapiro-Wilk test


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Kolmogorov-Smirnov (KS) test, Shapiro-Wilk test

hypothesis tests of whether sample distribution is significantly different from a (population) normal distribution (null hypothesis = normality)

sensitive to N, tend to always reject if N is big

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graphical normality checks

histograms/density plots

quantile-quantile (Q-Q) plots

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Q-Q plot

x-axis: theoretical quantiles of the normal distribution

y-axis: quantiles of the data

if normal, points should fall in a straight line

<p>x-axis: theoretical quantiles of the normal distribution</p><p>y-axis: quantiles of the data</p><p>if normal, points should fall in a straight line</p>
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confidence interval

interval estimate

range for which any random sample from the population will contain μ with probability 1 - α

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calculate confidence interval

x̄ ± critical value*sx̄

find the critical values: the values on the distribution such that 2.5% is in the left and right tail for α = .05

turn the critical values onto the scale of the original variable with sample mean and SE

<p>x̄ ± critical value*s<sub>x̄ </sub></p><p>find the critical values: the values on the distribution such that 2.5% is in the left and right tail for α = .05</p><p>turn the critical values onto the scale of the original variable with sample mean and SE</p>
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paired samples t-test

t-test that builds in a dependence structure:

  • variable measured at two points in time for the same N persons

  • variable measured for pairs of subjects (younger/older siblings, husband/wife pairs)

take the difference score (D) for each pair of observations


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nil hypothesis

setting a null hypothesis to a difference of zero

a way to determine test for differences in general

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paired t-test statistic

tD = (D - μ₀)/(sD/√N) with df = N - 1

N is the number of pairs

average difference divided by SE of difference scores (μ₀ often 0)

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independent groups

testing whether two independently sampled groups have the same population mean

randomized experiments where different groups get different treatments

difference in pre-existing groups

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independent samples t-test assumptions

normality of sampling distributions, independence of observations, no outliers, random sampling PLUS

homogeneity of variance: even if the populations have different means, they have the same SD around those means

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pooled variance

to get the best estimate of the shared population variance, we need to pool them

weighted average of the two sample variance

<p>to get the best estimate of the shared population variance, we need to pool them </p><p>weighted average of the two sample variance</p>
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independent samples t statistic

tx̄1-x̄2 = (x̄1 - x̄2)/(sx̄1-x̄2)

sx̄1-x̄2 = pooled standard error = sp*√(1/n1 + 1/n2)

df = n1 +n2 - 2

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Welch-Satterthwaite correction

same test statistic as before, but the SE doesn’t pool variances (sx̄1-x̄2 = √((s21/n1) + (s22/n2)) and modifies the degrees of freedom to make them smaller than (n1+n2-2)

default in R, helps if homogeneity of variance doesn’t hold