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Spatial Resolution
the ability to differentiate two objects (attributed to sharpness/penumbra)
spatial resolution determines
sharpness of the structural lines in a digital image
High Spatial Resolution
Edges of anatomical structures will appear sharp and easily visualized
no motion present
Digital factors & spatial resolution
matrix size
pixel size
For high spatial resolution, generally factors should be
small
Increase pixel size results in
decreased spatial resolution
increase matrix results in
increase spatial resolution
unit of resolution
lp/mm (2 pixels per mm)
When assessing recorded detail, clinical evaluation includes
trabecular pattern of bone
cortex of bone
bronchopulmonary markings of lungs
Matrix size
determined from the number of the columns and the number of rows of the image matrix
Results in increased spatial resolution
large image matrix
common plate matrix sizes
512 × 512
1024 × 1024
2048 × 2048
relationship between matrix size and pixel size
inverse
relationship between field of view (FOV) and pixel size
direct
matrix size is not
tech controlled
Sampling frequency is performed by
laser in CR equipment
frequency
number of times data is recorded on a digital plate when being read
With imaging plates: the ______ the sampling frequency = the higher spatial resolution
faster
spatial frequency
the number of details that can be fit into a given space
Modulator Transfer Function (MTF)
the ability of a system to record available spatial frequencies
best measurement of spatial resolution (for computer)
MTF
_____ have the highest MTF
Digital systems (DR)
An MTF of 1 would be
(typically, in 70% - 80% range)
a perfect imaging system
Dynamic range
the range of exposures that may be captured by a detector
dynamic range describes
number of gray shades that an imaging system can reproduce
Digital imaging has a _____ dynamic range
wide
Contrast resolution
ability to differentiate shades of gray
Exposure latitude
the range of exposures which produces quality images
Exposure latitude is the extent
which radiographs can be overexposed or underexposed and still achieve an acceptable result
Disadvantage of the wide exposure latitude that digital systems offer?
dose creep with overexposure to the patient
Quantization
takes electrical signals and turns them into digital bits of information. Occurs during ADC
ADC
analog to digital converter
Quantization is displayed as
specific brightness levels on the image
Bit Depth
total number of possible brightness levels that can be assigned to any individual pixel in the image
8 bits
256 shades of gray
computers manipulate data based on what is called
binary number system
1 byte
8 bits
Object to Image Distance (OID)
distance between patient and IR
Source to Image Distance (SID)
distance between tube and IR
Increase of
SID
Would increase spatial resolution
true
Increase of
OID
FSS
Motion
Angulation
Would increase spatial resolution
false
Distortion
the misrepresentation of the true size or shape of an object on a radiographic image
Geometric factors of distortion
Size Distortion
Shape distortion (how we make image long or short)
the two ways shape distortion affect the image
elongation
foreshortening
Angulation of these factors result in shape distortion
Image Receptor (IR)
X-ray tube
Anatomical part
Magnification is a form of size distortion primarily controlled by
OID
Increasing OID would also increase (related to distortion)
Magnification
For every 1” increase in OID, SID should increase
7-8”
Chest x-ray
72” SID (180 cm)
decreases the magnification
increases spatial resolution
PA chest is preferred over _____ because of the location of the heart within the thorax
AP chest
Performing an exam PA instead of AP can
reduce size of the anatomical part
Magnification Factor (MF)
As the x-ray beam diverges the image produced on the radiograph is always slightly larger than the original image
MF formula
SID/SOD (= image size/object size)
SOD
Source to Object Distance
SOD = SID - OID
Actual Size formula
Image Size / MF
Order of solving a MF and actual size problem
Find SOD
Calculate MF
Calculate AS
Image Size formula
Actual size x MF
How is elongation resulted?
angling the tube & image receptor
Foreshortening (f/art)
angling the part
AP Partial Flexion Elbow
Trauma or Fracture scenario
How would you minimize size distortion?
Decrease OID
Increase SID
Which of the following would produce the largest image? And why
A. 40” SID, 3” OID
B. 40” SID, 5” OID
C. 72” SID, 3” OID
D. 72” SID, 5” OID
B.
Higher OID = larger image
Lower SID = more beam divergence (think larger shadow)
A short OID would (Decreased, small / Part closer to IR = Good)
bring the object close to the image receptor and improve spatial resolution
When a large OID is used (Increased / Part further from IR = Bad)
photons will diverge and cause image blurring. Also cause magnification of the part decreasing visualization of small details
Increased Penumbra (increased blurring)
Long, Increased SID (tube farther from IR = Good)
improves spatial resolution with less divergence of beam
Short, Decreased SID (tube closer to IR = bad)
photons will diverge more and cause image blurring
Focal spot size selection directly related to
size of the filament used
Smaller focal size produces
smaller effective focal spot and a more aligned beam (Higher SR)
Larger focal spot produces
larger effective focal spot and a less aligned beam (less SR)
Penumbra
Un sharpness or blurring at the edges of an object
Penumbra (unsharpness) can be controlled by
SID
OID
SOD
FSS
A larger patient will increase OID, thus
result in magnification