EDEXCEL A-LEVEL PURE MATHS (6): CIRCLES

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Last updated 4:27 PM on 6/29/26
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23 Terms

1
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How can you find the midpoint of a line segment?

- You can find the midpoint of a line segment by averaging the x and y-coodinates of its endpoints.

- The midpoint of a line segment with endpoints (x₁, y₁) and (x₂, y₂) is:

((x₁ + x₂)/2, (y₁ +y₂)/2).

<p>- You can find the midpoint of a line segment by averaging the x and y-coodinates of its endpoints.</p><p>- The midpoint of a line segment with endpoints (x₁, y₁) and (x₂, y₂) is:</p><p>((x₁ + x₂)/2, (y₁ +y₂)/2).</p>
2
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What is an example of finding the midpoint of a line segment?

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What is an example of finding coordinates using the equation ((x₁ + x₂)/2, (y₁ +y₂)/2)?

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4
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What is the perpendicular bisector of a line segment?

- The perpendicular bisector of a line segment, AB, is the straight line that is perpendicular to AB and passes through the midpoint of AB.

- If the gradient of AB is m, then the gradient of the perpendicular bisector will be -1/m.

<p>- The perpendicular bisector of a line segment, AB, is the straight line that is perpendicular to AB and passes through the midpoint of AB.</p><p>- If the gradient of AB is m, then the gradient of the perpendicular bisector will be -1/m.</p>
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What is an example of finding the equation of the perpendicular bisector to a line, given two points the line passes through?

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6
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What is a circle and what is the equation of a circle?

- A circle is the set of points that equidistant from a fixed point.

- You can use Pythagoras' theorem to derive the equation of circles on a coordinate grid.

- For any point (x, y) on the circumference of a circle, you can use Pythagoras' theorem to show the relationship between x, y and the radius r.

- The equation of a circle with centre (0, 0) and radius, r, is x² + y² = r².

- When a circle has a centre (a, b) and radius r, you can use the following general form of the equation of a circle: (x - a)² + (y - b)² = r².

<p>- A circle is the set of points that equidistant from a fixed point.</p><p>- You can use Pythagoras' theorem to derive the equation of circles on a coordinate grid.</p><p>- For any point (x, y) on the circumference of a circle, you can use Pythagoras' theorem to show the relationship between x, y and the radius r.</p><p>- The equation of a circle with centre (0, 0) and radius, r, is x² + y² = r².</p><p>- When a circle has a centre (a, b) and radius r, you can use the following general form of the equation of a circle: (x - a)² + (y - b)² = r².</p>
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What is an example of finding the equation of a circle when given a centre (a, b) and a radius, r?

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What is an example of finding the equation of a circle and a point (a, b) it passes through when given a an equation in the form (x - a)² + (y - b)² = r²?

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What are more complex problems involving circle equations?

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10
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What is the other form the equation of a circle can be given in?

- You can multiply out the brackets in the equation of a circle to find it's alternate form:

1) (x - a)² + (y - b)² = r²

2) x² - 2ax + a² + y² - 2by + b² = r²

3) x² + y² - 2ax - 2by + b² + a² - r² = 0

- The equation of a circle can be given in the form: x² + y² + 2fx + 2gy + c = 0.

- This circle has centre (-f, -g).

- This circle has radius √f² + g² - c.

- If you need to find the centre and radius of a circle with an equation in expanded form, it's usually safest to complete the square for the x and y terms.

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What is an example of completing the square of the x and y terms to find the centre and radius of a circle with an equation in expanded form?

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How do you find the coordinates of intersections of a straight line and a circle?

- By using algebra.

- A straight line can intersect a circle once, by just touching a circle, or twice.

- Not all straight lines will intersect a given circle.

<p>- By using algebra.</p><p>- A straight line can intersect a circle once, by just touching a circle, or twice.</p><p>- Not all straight lines will intersect a given circle.</p>
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What is an example of finding the coordinates of intersections of a straight line and a circle?

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What is an example of proving there are no intersections of a straight line and a circle?

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15
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What are tangents and chords and what are their properties?

- A tangent to a circle is a straight line that intersects the circle at only one point.

- A tangent to a circle is perpendicular to the radius of the circle at the point of intersection.

- A chord is a line segment that joins two points on the circumference of a circle.

- The perpendicular bisector of a chord passes through the centre of a circle.

- You can use the properties of tangents and chords within circles to solve geometric problems.

<p>- A tangent to a circle is a straight line that intersects the circle at only one point.</p><p>- A tangent to a circle is perpendicular to the radius of the circle at the point of intersection.</p><p>- A chord is a line segment that joins two points on the circumference of a circle.</p><p>- The perpendicular bisector of a chord passes through the centre of a circle.</p><p>- You can use the properties of tangents and chords within circles to solve geometric problems.</p>
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What is an example of using the properties of tangents within circles to solve geometric problems?

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What are triangles and how do they form circumcircles?

- A triangle consists of three points called verticies.

- It's always possible to draw a unique circle through the three verticies of any triangle.

- This circle is called the circium circle of the triangle.

- The centre of the circle is called the circumcentre of the triangle and is the point where the perpendicular bisectors of each side intersect.

<p>- A triangle consists of three points called verticies.</p><p>- It's always possible to draw a unique circle through the three verticies of any triangle.</p><p>- This circle is called the circium circle of the triangle.</p><p>- The centre of the circle is called the circumcentre of the triangle and is the point where the perpendicular bisectors of each side intersect.</p>
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What are the rules with triangles inside circles?

- For a right-angled triangle, the hypotenuse of the triangle is a diamter of the circumcircle.

- Therefore, if angle PRQ = 90°, then R lies on the circle with diamter PQ.

- Therefore, the angle in a semicircle is always a right angle.

<p>- For a right-angled triangle, the hypotenuse of the triangle is a diamter of the circumcircle.</p><p>- Therefore, if angle PRQ = 90°, then R lies on the circle with diamter PQ.</p><p>- Therefore, the angle in a semicircle is always a right angle.</p>
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How do you find the centre of a circle given any three points on the circumference?

- Find the equations of the perpendicular bisectors of two different chords.

- Find the coordinates of the point of intersection of the perpendicular bisectors.

<p>- Find the equations of the perpendicular bisectors of two different chords.</p><p>- Find the coordinates of the point of intersection of the perpendicular bisectors.</p>
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What is an example of a question involving proof that a straight line is a diameter of a circle?

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EDEXCEL A-LEVEL PURE MATHS CHAPTER SIX: CIRCLES

(MAKE SURE YOU KNOW THE FOLLOWING)

(1-4)

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EDEXCEL A-LEVEL PURE MATHS CHAPTER SIX: CIRCLES

(MAKE SURE YOU KNOW THE FOLLOWING)

(5-7)

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EDEXCEL A-LEVEL PURE MATHS CHAPTER SIX: CIRCLES

(MAKE SURE YOU KNOW THE FOLLOWING)

(8-10)

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