AP CALCULUS AB UNIT 4

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25 Terms

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R

all real numbers

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Z

all integers

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V

for all…

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E

an element of…

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sequence

a function whose domain is a set of non-negative numbers

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recursive

elements defined by previous elements

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explicit

elements defined by an explicit rule; not dependent on previous elements

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if the limit of A as N appr INF equals L

- limn → inf(An) = L

then sequence A converges to L

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if limit as A as N appr INF DNE
- limn → inf(An) DNE

then sequence A diverges

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absolute value sequence theorem

if: limit of |A| as N appr INF equals 0
- limn → inf(|An|) = 0
then: limit of A as N appr INF equals 0

- limn → inf(An) = 0

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f(x) = Cxn

= C fn(x) = C * n!

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limn → inf (1 + (1/n))n = ?

e

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series

sum of the terms of an infinite sequence

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Sn

partial sum

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if a sequence of partial sums (Sn) diverges

then ΣAn is a divergent series

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if a sequence of partial sums (Sn) converges

then ΣAn is a convergent series
and
Σn=1inf (An) = limn → infSn = S

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telescoping series

partial sums that collapse in on themselves (“cancel”)
often in the form Σ (c/(n + d)) - (j/(n+k))

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geometric form

Σ Arn

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divergence of geometric series

if |r| >= 1
then series diverges

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convergence of a geometric series

if |r| < 1
then series converges to a/(1 - r)

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test for series divergence (aka nth term test)

if limn → inf (An) does not equal 0
then Σn=1inf (An) diverges

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p-series

when the denominator increments but the numerator does not/remains constant

Σn = 1inf (1/np) for p > 1

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p-series convergence

when p > 1

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p-series divergence

when 0 < p <= 1

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harmonic series

a p-series in which p = 1; ALWAYS DIVERGES

Σn=1inf (1/n)