1/296
Looks like no tags are added yet.
Name | Mastery | Learn | Test | Matching | Spaced |
---|
No study sessions yet.
Exponential minimum
dont have one
exponential maximum
is found only when decaying (.25)x and is always zero
Density =
Mass/volume
quadratic minimum
our y/k value
quadratic with no solution
when D < 0 (a negative number)
quadratic with two solutions
when D>0
linear equations can have
one solution, no solution, or infinitely many solutions.
linear: infintley many solutions
slope AND y-intrecept/b are the same
linear: no solution
slope is the same but y-inter/b is different
linear: one solution
the slopes are different, indicating that the lines intersect at exactly one point.
discriminant formula
b²-4ac
when to use vertex formula of a quadratic
in a physics like question where it is being thrown/ dropped
quadratic x value minimum
is the h value but usually isnt referred to as minimum unless the question asks so
quadratic h value
x-coordinate/value (ex. seconds) at the min/max
the vertex value A s equal to
a TIMES (x²+bx+c)
how to find the A value in vertex quadratics
find a coordinate mentioned, using the given vertex, plug in the formula and solve
porabola opens upwards
a is positive
parabola opens downwards
a is negative
ur given a vertex quad told to find a with only a
write out the vertex formula and distribute then also distribute a, with additional information ur overall just substituting
what could be the factors of p
were asked for the roots of the function p
how to find roots (ina vertex quad function)
using midpoint formula x1+x2/ 2 =h
or
solving for x when y is zero
predicted to increase by n%, n is?
(1-r) after finding the rate remember to subtract one to find %
arc length/radius
CENTRAL ANGLE = radian
arc length/circumfrence
CENTRAL ANGLE = theta /360
arc measure
is the central angle
arc length (degrees)
theta/360 × 2pie(R)
circumference of a circle
2pie(R)
sum of roots
-b/a
radian/degree conversion
r=degree(pie)/180
sin x complimentary rule
= cos(90-x)
where cos’s x + sins’s x = 90
sin x = degree, find the sides of the tri
degree → fraction → O/H
line tangent to the circle =
slope perpendicular to radius
90 degree angle
product of roots
c/a
eq of circle
(x-h)² + (y-k)² = r²
sector area
theta/360 x (pie)r²
cannot be a tri similarty
ASS
total interior angle
180(n-2)
tri similarity ratio
short/long = short/long
when presented w two tri
similairty question
if given a 45/90/45 0r 90/60/30 info or square roots in the answer choice
always the subject to be used
Coordinate Distance
/ square root (X2-X1)² + (Y2 - Y1)²
3:4:5 ratio tri
we’re dealing w a right triangle
Ex. 9:12:15
Volume of cube
S³
Bisector proof
Can never stand alone and be enough proof to find the shape
# of vertices =
Number of sides
Cylinder volume
Pie x R² x h
triangular (cylinder base) volume
1/3(pie, r²) x H
Volume of sphere
4/3(pie)R³
(POWER OF 3)
Area of trapezoid
1/2(top + bottom length) x H
Mass =
Density x Volume
Triangular prism Volume w 2 other triangles
½ Base area x height
SA of cube
6s²
SA of cylinder + of only the middle part
h x 2pieR → (middle)
Triangles are congruent
They are the exact same
Triangles are similar
Have a relationship but aren’t exactly the same
sector area
theta/360 x pieR²
(as a central angle) pie =
180
volume of right square prism
(square base, rectangle prism)
x² x h
find arc length, with one given and its degree
arc length unknown/ arc length = theta new/ theta old
corresponding angles in similarity tri
are congruent
completing the square
x² + 12x + #
how to complete the square
Bx/2 = # → #²
if the absolute eq. is originally = to a negative number
no sol.
3|x+1| + |x+1| =
4|x+1|
discrminant is used in two ways
1) linear and quadratic system
2) a quadratic alone
positive constant
b² = ± 6 → choose 6
“which pair is a solution to the eq.” W MULTIPULE CHOICE
plug into system and make a given # the variable
system of eq. problem, check 1st
only quad? only linear? or both?
leave no square roots b4 assuming
y is decreasing by 0.5
linear decline
y halves as x increases
exponential decline
a constant
non-changing #
a fixed #
“doubles everyday”
geometric seq. (multiplying)
initial(1-r^n) / (1-r)
addition sequence
initial((n-1) x D)
d is amount we are continously adding with
multiplying sequence
initial(1-r^n) / (1-r)
smallest solution
(quadratic)
out of the two possible sol. which is smaller
(2/35)/2
1/35
absolute expression
do the ENTIRE process then apply the absolute
watch out for disriminant when working w C
switching of signs due to division
how to avoid discreminant swap
ensure ur -4 has a negative c or a and not both
decreasing rate is found between
-1< r <0
5 turn into a fraction over x
5y/y → y/y x 5
squaring anything has two sol.
making ± 100 a viable answer
esp. for quadratic answers
“find the solutions”
find the roots/ solve for x(‘s)
quadratic intervals
found in the factored form (x+1), -1 is part of the interval
“sum of solutions” but for non-quadratic
add both possible answers (x+y)
“shown as a constant/base/cofficent”
look for the answer in the eq as what is asked
big fractions 1st step
as much factoring as possible
zero-product property
if the product of two numbers equal zero, one or the other must be 0
x-1= ax + b
the eq can be taken quite literal since variables match up and structure
(ax = x so a =1)
poynomial divison 1st check
are all the remainders the same?
remainder theorm
the remainder is found inserting into our eq x’s of the quadratic, c, (from x-c)
if told add a quadratic
assume ax² + bx + c
if talking abut quad. but theres no mentioning of being thrown up or being propelled
refer to a regualar quad formula
the function = 0 when x equals 0
indicates no c value
extract c from 2(x+5)(x-6)
(2×5) x -6 = C
b² > 6400
two possible solutions due to ± 80
b² < 6400
-80 < b < 80
maximum exponential w change in domain
if x>/= 1, our maximum is now 1 and is plugged into eq to find that ones specific max
edges of a cube
same as side
function tables can be
quad, exponential, linear, sequential, exponential w a linear power