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Distance between Point P and Plane passing through point Q with normal vector N
|QP*N|/‖N‖
Distance between Line and point M given Line going through point P and v = Direction vector
‖PM x v‖/‖v‖
Projection of v on to u (PROJuV
(uv)/‖u‖^2u
Standard Unit Vector
ai+bj+ck
Component form of vector
<x, y, z>
symmetric equations of line L
(x - x0)/v0 = (y - y0)/v1 = (z - z0)/v2
Vector equation of a Line
L = Position Vector P + t(direction vector v)
angle formula
(uv)/(‖u‖‖v‖) = cos(theta)
Parametric Equations
x = x0 + tv0, y = y0 + tv1, z = z0 + tv2
What is a normal vector
The orthogonal/perpendicular cross product of two vectors on a plane.
Unit vector in the direction u given vector u
u^ = u / ‖u‖
Equation of Plane given Normal Vector N = <v0, v1, v2> and point P = <x0, y0, z0>
[v0*<x - x0>] + [v1*<y - y0)] + [v2*<z - z0>] = 0
MUST WRITE “= 0” or minus credit