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Briefly explain Ohm’s law.
V across resistor = directly ≈ how much current flows thru it, scaled by Ω value.
↑ Ω for the same 𝗜 = ↑ 𝗩 needed to push it thru; ↑ 𝗜 for the same Ω = ↑ 𝗩 required.
What = a series circuit @ its core?
Components connected in ONE single path/line → same 𝗜 flows thru EVERY component, one after another.
Big picture — why does a 𝗩 divider matter?
Total 𝗩 (Vin) → “used up” piece by piece across each resistor → lets you create a SMALLER, specific 𝗩 @ any pt in circuit from one ↑ 𝗩 source.
How do you calculate a 𝗩 divider, step by step?
I = Vin/(R1 + R2) → find total 𝗜 (add resistors since 𝗜 flows thru both)
VR1 = 𝗜 × R1 → 𝗩 dropped across R1.
V2 = Vin - VR1 → what’s left over after R1’s drop = your answer.
Quick sanity check: VR2 = I × R2 → should equal V2 directly.
What’s the key difference b/w series + parallel circuits?
Series: same CURRENT flows through everything, VOLTAGE gets divided/split
Parallel: same VOLTAGE appears across everything, CURRENT gets divided/split
What = a parallel circuit, @ its core?
Components connected side-by-side, sharing SAME two connection pts ∴ same 𝗩 appears across EVERY component.
How do you calculate total Ω in parallel?
1/R = 1/R1 + 1/R2 → solve for R ∴ total R = always SMALLER than smallest individual resistor.
How do you calc 𝗜 thru each resistor?
𝗜1 = Vin/R1; 𝗜2 = Vin/R2 ∴ same Vin plugged → each, since 𝗩 shared.
What’s the difference b/w the series formula (V/R = VR1/R1 = VR2/R2) + the parallel formula (V = I1 × R1 = I2 × R2)
Series formula: V/R terms all equal I ∴ confirms CURRENT is shared/constant across the circuit
Parallel formula: I×R terms all equal V ∴ confirms VOLTAGE is shared/constant across the circuit
(Both look like "= = =" chains, but series chains current-equivalent expressions ≠ parallel chains voltage-equivalent expressions)
What = loading error?
Measuring device’s own Ω changes circuit it’s measuring ∴ measurement becomes inacc.
How to ↓ loading err for ammeters vs. voltmeters?
Ammeter → placed in SERIES → Ω adds to circuit ∴ needs ↓ Ω (~0Ω) to ↓ ∆ in circuit’s 𝗜
Voltmeter → placed in PARALLEL → Ω creates alt path, pulling 𝗜 aways ∴ needs ↑ Ω (~∞Ω) so it barely draws any 𝗜 away
? ∆ b/w capacitor + resistor.
Unlike resistor (which lets 𝗜 flow continuously thru it), a capacity STORES electrical charge on its two plates, separated by that gap.
𝗜 can’t literally flow thru the gap, but charge builds up on one side + depletes on the other, which effectively acts like 𝗜 = flowing, while the capacitor = charging
What’s a capacitor? How does it work?
Two plates, gap b/w them (no direct 𝗜 flow across) ∴ charge builds up on each side instead.
It fills up w/ e⁻’s when energized + releases them when supply stops.
How does 𝗩 rise fast → slow?
START (empty capacitor): big gap b/w battery V and capacitor's V (0V) ∴ pushes charge onto plates fast
Charge builds → capacitor's V climbs closer to battery V → gap shrinks
Smaller gap = ↓ "push" driving new charge on ∴ charging ↓ slows
Capacitor V ≈ battery V → barely any push left → charging plateaus
What’s direct 𝗜? What’s alternating 𝗜? What does each look like in a graph?
cons V over time; simple flat line
oscillating V up + down continuously over time; line = wave
Define the ff: Vpk-pk, -m, -RMS?
Vpk-pk: distance tot from very top of wave to very bottom
Vm: HALF of that pk-pk distance — measured from middle (zero line_ up to just the top peak
VRMS: the “effective” DC-equivalent 𝗩
What;’s the formula relating pk-pk, m, + RMS voltages?
/21Vpk−pk=Vm=(22)VRMS
What’s the ∆ b/w Per + Hz?
Per: how long ONE full wave cycle takes
Hz = f = 1/T — how many complete cycles happen per second
What = VRMS + why it used instead of amp?
AC 𝗩 constantly changes (sine wave) ∴ no single “the 𝗩” moment to pt to.
VRMS = “effective” steady value ∴ if replaced w DC, delivers SAME power
VRMS = Vamplitude / √2 ∴ RMS always SMALLER than peak (accounts for whole wave shape, not just top)
What is impedance (Z) + why does AC need it instead of just R?
DC: V and I are flat/constant ∴ simple R (resistance) is enough
AC: V and I are waves, constantly changing ∴ components like capacitors cause TIMING shifts, not just resistance ∴ need Z (impedance) to capture both effects
Z = Zreal + Zim × i — what does the two parts x̄?
Zreal = behaves like normal Ω (opposes 𝗜, no timing shift) = the “old” R
Zim (imaginary part) = NEW, captures the TIMING/PHASE SHIFT effect (caused by capacitors/inductors taking time to charge/react)
What does the “phase shift” on the graph actually show?
V + I waves peak @ DIFFERENT times, not aligned ∴ that offset = what Zim mathematically reps (caused by capacitors, as charging takes time, ∴ 𝗜 reacts sooner/later than 𝗩)
Pure resistor (no cap/ind) → V + I stay in-sync (Zim = 0)
Capacitor/inductor added → V + I shift out of synce (Zim ≠ 0)