MCAT Phys Chapt 4 Equations

Fluids

F_g=

pVg (mg)

specific gravity=

p/1.00

pressure=

Force/area

Absolute (hydraulic pressure)=

P₀+pgz

where p=density of fluid P₀= initial pressure and z= depth of object

Gauge pressure=

P-P_atm= P₀+pgz- P_atm

sea level pressure

1.013 × 10^5 Pa

Pascal’s Principle

P1=P2

F1A2=F2A1

V=

A1d1=A2d2

Work=

F1d1=PressureV=F2d2

F_buoy

=p_fluid*V_{fluiddisplaced}*g=p_fluid*V_dispersed*g

Laminer flow

smooth and orderly

tubular flow

disordered and chaotic

Flow rate=

pi*r^4*change in pressure/(8*viscosity*length of pipe)

V_{c (critical speed of turbulent fluid)}

N_RViscosity/density*diameter

Flow rate

INDEPENDENT of cross sectional area in a CLOSED SYSTEM

Linear speed

V₁A₁=V₂A₂

_{(conservation of mass)}

Bernoulli’s Equation

P₁+1/2pv₁²+pgh₁=P₂+1/2pv₂²+pgh₂

_{static pressure and dynamic pressure will be constat}

Circulatory system

closed system with non constant flow

arterial circulation moved by heart

venous circulation (3x volume) moved by skeletal musculature

Air at alveoli has

zero speed

Blood volume entering heart

equals volume exiting heart in one syclke