AP Calc AB

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Last updated 5:35 PM on 1/12/26
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95 Terms

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Quotient ID’s

(tan x = sin x/cos x) OR (cot x = cos x/sin x)

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Reciprocal ID’s

(sec x = 1/cos x) OR (csc x = 1/sin x)

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Pythagorean ID’s

(sin²x + cos²x = 1) OR (sec²x - tan²x = 1)

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2sinxcosx = sin2x

Double Angle id #1

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cos²x-sin²x = cos2x

Double Angle id #2

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sin (-x) = - sin x

Even-odd ID (sin)

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cos (-x) = cos x

Even-odd ID (cos)

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tan(-x) = - tanx

Even-odd ID (tan)

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Cos Personality

Mean + selfish (doesn’t like sin, goes against + and -)

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Sin (A+B)

sinA cosB + cosA sinB

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Cos (A+B)

cosA cosB - sinA sinB

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Sin (A-B)

sinA cosB- cosA sinB

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Cos (A-B)

cosA cosB + sinA sinB

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Distance b/w 2 points

(x2-x1)² + (y2-y1)² (square root of)

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Midpoint Formula

(x1+x2)/2 , (y1+y2)/2

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ln (0)

undefined

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ln (1)

0

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ln (e)

1

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Law of Logarithms = ln(ab)

lna + lnb

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Law of Logarithms = ln(a/b)

lna - lnb

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Law of Logarithms = ln(an)

n*lna

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Law of Logarithms = ln(1/a)

-lna

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Average Rate of Change is also called

slope of the secant line

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Average Rate of Change Formula

f(b) - f(a) / b - a

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Squeeze Theorem

If f(x) </= g(x) </= h(x), then as x —→ a, f(x) —> L and h(x) —> L then g(x) —→ L

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lime^x (- infinity)

0

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limex (infinity)

infinity

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limlnx —> 0+

- infinity

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limlnx —> infinity

infinity

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lim1/x

0

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lim sinx/x

1

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lim1-cosx/x

0

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limarctanx (—> infinity)

pi/2

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limarctanx (—> - infinity)

- pi/2

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lim1/x (—> 0)

- infinity

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lim1/x (—> 0+)

infinity

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Definition of a vertical asymptote

x=a iff lim (—> a+) = ±infinity OR lim (—> a-)

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Definition of a horizontal asymptote

y=a iff lim (—> infinity) = a OR lim (—> - infinity) = a

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Continuity

1) f(a) exists, 2) lim (x—>a) f(x) exists, 3) lim (x—>a) f(x) = f(a)

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Intermediate Value Theorem (IVT)

1) f is cont. on the closed interval [a,b] 2) f(a) not equal to f(b) 3) k is between f(a) and f(b)

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If IVT meets requirements,

Then there exists a number c between a and b for which f(c) = k

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Definition of the derivative/limit of the difference quotient

f’(x) = lim (h—>0) f(x+h) - f(x) / h

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Definition of the derivative/alternate form

f’(x) = lim (x—>b) f(x) - f(b) / x-b 

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Tangent Line

y-f(a) = f’(a) (x-a) 

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Normal Line

The line perpendicular to the tangent line at the point of tangency

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Three Reasons for a function, f, will not be differentiable at a point x=a

1) f not cont. at x=a 2) the graph of f has a corner/cusp at x=a 3) the graph of f has a vertical tangent at x=a

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Differentiation Rules

f and g are functions of x

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Product Differentiation Rule

d/dx (f g) = f’ g + f * g’ 

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Quotient Differentiation Rule

d/dx (f/g) = f’*g - f*g’/g2

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Chain Rule:

if h(x) = f(g(x)), then h’(x) = f’(g(x)) * g’(x)

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Chain Rule Words

the derivative of the outside evaluated at the inside times the derivative of the inside

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d/dx ( sinx) =

cosx

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d/dx (cscx) =

-cscx * cotx

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d/dx (e^x) =

e^x

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d/dx (lnx) =

-1/x

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d/dx (cosx) =

-sinx

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d/dx (secx) =

secx * tanx

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d/dx (logax) =

1/xlna

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d/dx (tanx) =

sec²x

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d/dx (cotx)

-csc²x

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lim (f+-g) =

limf +- limg

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lim (c*f) =

c*limf

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lim c =

c

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lim (fg) =

limf * limg

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lim f/g = 

limf / limg for limg does not equal 0

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lim f(g(x)) =

f(limg(x))

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lim (f(x))^n =

(limf(x))^n

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lim f(g(x)) =

f(limg(x))

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Extreme Value Theorem (EVT)

1) If f is cont. on a closed interval [a,b], 2) Then f has an absolute max and an absolute min on the interval [a,b] 

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Mean Value Theorem

If: 1) f is cont. on [a,b], 2) differentiable on (a,b) Then: there exists a number c between a and b such that f’(c ) = f(b) - f(a) / b-a

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Minimum or maximum refers to

y-value

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Position, Velocity, Acceleration Application

  1. Particle at rest when v(t) = 0

  2. Speed is increasing if v and a have same sign

  3. Speed is decreasing if v and a have opposite signs

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Definition of concavity

  1. f is concave up if f’ is increasing

  2. f is concave down if f’ is decreasing

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Definition of a point of inflection (POI)

A point on the graph of f where the concavity of f changes.

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2nd derivative test for relative extrema:

Given f’(c ) = 0, then

1) If f’’(c ) < 0, then f(c ) is a max

2) If f’’(c ) > 0, then f(c ) is a min

3) If f’’(c ) = 0, then the test is inconclusive

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xndu =

xn+1/n+1 + C

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audu =

au/lna + C

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sinu du =

-cosu + C

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cscu cotu du =

-cscu + C

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<p></p>

sin-1u + C

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sin-1 u/a + C

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cosu du =

sinu + C

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secu tanu du =

secu + C

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tan-1u + C

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1/a tan-1 u/a + C

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eu du =

eu + C

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sec2 u du =

tanu + C

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csc2 u du =

-cotu + C

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1/a arc sec IuI/a + C

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arc sec IuI + C

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0

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<p></p>
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1/u du =

ln IuI + C