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Schrödinger equation
iℏ∂ψ∂t=−ℏ22m∇2ψ+Vψiℏ∂t∂ψ=−2mℏ2∇2ψ+Vψ
ψ(x,t) = wavefunction; |ψ|² = probability density of finding a particle at (x,t).
Stable solutions only exist for fixed energy eigenstates, ψₙ(x,t) → these are atomic orbitals (s, p, d, f).
Molecular orbitals
When multiple nuclei are present, atomic orbitals combine into molecular orbitals → chemical bonds.
Example: H₂ — two 1s orbitals combine into a bonding (lower energy, in-phase) and antibonding (higher energy, out-of-phase) orbital.
Filling of orbitals (left-step periodic table)
Electrons have spin up/down → max 2 electrons per orbital (Pauli exclusion).
Atoms are neutral (electrons = protons).
Orbitals fill in increasing energy order: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s...
Quantum Basis of Band Structure
In a solid, many atoms → energy levels of eigenstates blur into continuous energy bands.
Metals: a band is partially filled at all temperatures → very high conductivity (e.g., Na has a partially filled 3s band).
Semiconductors: small band gap between a full valence band and empty conduction band.
At normal temps, some valence electrons are thermally excited into the conduction band → become free (current-carrying) electrons.
This leaves holes in the valence band, which behave like mobile positive charges (a neighbouring electron hops into the hole).
Insulators: same picture as semiconductors but with a much larger band gap (negligible thermal excitation).
Energy Bands
Above 0 K, some electrons are randomly knocked loose from Si lattice bonds → electron–hole pairs.
Applying an electric field lets both electrons and holes contribute to current flow.
Doping — adding small amounts of impurity atoms changes conductivity dramatically:
Type | Impurity example | Effect |
|---|---|---|
n-type | Antimony (Sb) — 5 valence electrons | Donates an extra free electron |
p-type | Boron (B) — 3 valence electrons | Creates an extra hole (acceptor) |
Semiconductors and Doping
Joining p-type and n-type material creates a p-n junction = basic diode.
Current flows easily in one direction (forward biased) and is blocked in the other (reverse biased).
Depletion region
At the junction, free electrons from n-side diffuse over and recombine with holes → forms a region of immobile charged ions with no free carriers.
Unbiased junction: depletion region ≈ 1 µm.
Forward bias (+ to p-side, – to n-side)
Holes pushed toward junction from p-side, electrons pushed toward junction from n-side.
Depletion region shrinks; electrons and holes recombine at junction → large continuous current.
Reverse bias (– to p-side, + to n-side)
Carriers pulled away from junction → depletion region widens.
Current stops except for a tiny thermally-generated reverse current (~10⁻⁸ A) until breakdown voltage (typically –20 V to –700 V).
Diode I–V characteristic
Forward turn-on ≈ 0.5 V, significant conduction above ≈ 0.7 V (LEDs: 1.2–3.6 V).
Reverse current: tiny and roughly voltage-independent until breakdown.
Diode = two-terminal, nonlinear, passive device.
The P-N Junction (Diode)
Half-wave rectifier
Single diode; only lets through the half-cycle when source exceeds diode's ~0.6 V forward drop.
Output (V_load) is a rectified copy of the AC input's positive half-cycles only.
Full-wave bridge rectifier
4 diodes; current always passes through 2 diodes in series.
V_load(max) ≈ V_source(max) – 1.2 V (two diode drops).
V_load ≈ 0 whenever –1.2 V ≤ V_source ≤ 1.2 V (dead zone from diode drops).
Smoothing with a capacitor
A capacitor in parallel with the load smooths the ripple: charges near the peak, discharges (supplies load current) between peaks.
Ripple current relation: i=C dvdt ≈ Vload/Rload
Ripple voltage:
Vripple = δv ≈ (Vload/RloadC)δt
where δt = ripple period = 1/f (half-wave) or 1/(2f) (full-wave).
Diode Circuits — Rectifiers
3 doped regions: emitter, base (very thin, ~10 µm), collector (largest, dissipates most heat).
NPN: n-type emitter / p-type base / n-type collector.
PNP: p-type emitter / n-type base / p-type collector.
Small base current controls a much larger collector current: IC=βIB (β typically 50–200) → current amplification.
Base–emitter junction: forward biased (VBE ≈ 0.6 V typical).
Base–collector junction: reverse biased; large current still flows because base is thin and field is high.
Modes of operation (NPN)
Mode | Condition | Behaviour |
|---|---|---|
Active | V_C > V_B > V_E (base-emitter forward, base-collector reverse) | Current amplifier: I_C = βI_B |
Saturation | V_C < V_B > V_E | Switch ON — high conduction C→E |
Cut-off | V_C > V_B < V_E | Switch OFF — no conduction |
Reverse-active | V_C < V_B > V_E (rarely used) | — |
Determining the mode — procedure
Is base-emitter forward biased (V_BE > 0.6 V or I_B > 0)?
No → cut-off: I_C = I_B = I_E = 0.
Yes → active or saturation:
Compute: IC,max=VCC−VBE/RC, IB=VBB−VBE/RB
If IBβ>IC,max → saturation (I_C = I_C,max, acts as closed switch). If IBβ<IC,max → active (I_C = βI_B, acts as amplifier).
Worked examples (β=100, V_CC=10 V, V_BB=5 V, R_B=22 kΩ):
R_C = 1 kΩ → I_C,max = 9.4 mA; I_B = 200 µA; I_Bβ = 20 mA > 9.4 mA → Saturation, I_C = 9.4 mA (switch ON).
R_C = 100 Ω → I_C,max = 94 mA; I_Bβ = 20 mA < 94 mA → Active, I_C = 20 mA (amplifier).
BJT as a current source (LED driver)
Choose R_B to set I_B = I_C/β for desired LED current.
Example: I_C = 20 mA, V_CC=V_BB=5 V, β=100 → I_B = 200 µA → R_B = (5–0.6)/200µA = 22 kΩ.
To stay in active mode: RC<VCC−VLED−VBE/IC (e.g. < 190 Ω).
Emitter follower
Output taken at emitter; V_out ≈ V_in – 0.6 V (follows input, one diode drop down).
High input impedance, low output impedance → current/power gain but no voltage gain (unity-gain buffer).
Common emitter amplifier
DC collector voltage: VC=VCC−ICRC
AC input signal capacitively coupled; C chosen so C≥1/2πf(R1∥R2) (passes frequencies of interest).
AC base perturbation v_in = v_B ≈ v_E (since V_BE ≈ const), and since β is large, i_C ≈ i_E = v_E/R_E.
Output: vout=vC=−iCRC= −vinRC/RE
Voltage gain = –R_C/R_E (inverting amplifier).
Bipolar Junction Transistor (BJT)
3 terminals: gate, drain, source (+ substrate/body).
Gate = insulating oxide layer grown on p- or n-type substrate → forms a planar capacitor.
No current flows through the gate (insulated) — voltage-controlled device, unlike current-controlled BJT.
n-channel MOSFET: n-type drain/source in p-type substrate. p-channel: reverse.
Gate operation (n-channel)
V_GS = 0: no depletion, no channel.
0 < V_GS < V_th: depletion layer forms (holes pushed away, immobile negative ions) — still no conducting channel.
V_GS > V_th (threshold voltage): inversion layer forms — high concentration of electrons at the oxide/semiconductor interface → conducting channel exists.
Three modes of operation (n-channel)
Mode | Condition | Behaviour |
|---|---|---|
Cutoff | V_GS < V_th | No conduction — switch OFF |
Linear (triode) | V_GS > V_th and V_DS < V_GS – V_th | Acts like a voltage-controlled resistor |
Saturation | V_GS > V_th and V_DS > V_GS – V_th | Current flows but only weakly depends on V_DS; mainly set by V_GS. Pinch-off: inversion layer separates from drain as V_DS increases |
V_th typically 0.5 V – 5 V, device-specific.
I_D vs V_DS curves: for each V_GS – V_th, current rises linearly then flattens off (saturates) — family of curves fan out with increasing V_GS – V_th.
MOSFET as a digital switch (LED driver example)
V_th = 2 V. Gate driven digitally (0 V / 5 V).
V_GS = 0 V → cutoff (LED off).
V_GS = 5 V → saturation (LED on), MOSFET behaves as a near-zero-resistance switch.
LED current set by supply and series resistor:
RD=VCC−VLED/ID
e.g. V_CC = 5 V, I_D = 20 mA → R_D = (5 – 0.6)/0.02 = 220 Ω.
MOSFET (Metal-Oxide-Semiconductor FET)
| MOSFET | |
|---|---|---|
Control terminal | Base — current controlled | Gate — voltage controlled |
Input current | Significant (I_B) | ~Zero (insulated gate) |
Key equation | I_C = βI_B | I_D depends on V_GS – V_th |
"On" state | Saturation | Linear/Saturation depending on use |
Typical use | Analog amplification, switching | Switching (digital logic, power), amplification |
BJT vs MOSFET