MTH 267 - Differential Equations Exam 1 Topics

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Module 1: Introduction to Differential Equations, Module 2: First-Order Differential Equations, Module 3: Modeling with First-Order Differential Equations

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50 Terms

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Ordinary Differential Equation (ODE)

ordinary derivatives w.r.t. 1 Independent Variable (IV)

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Partial Differential Equation (PDE)

partial derivatives w.r.t. 2 or more IVs

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Normal Form ODE

F: real-value function of n+2

y^(n): highest derivatives in terms of n+1

f:real-valued continuous function

<p>F: real-value function of n+2</p><p>y^(n): highest derivatives in terms of n+1</p><p>f:real-valued continuous function </p>
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Linear

Steps:

1) Convert given equation to the general linear formula by…

(a) dividing all terms by dx when x = IV

(b) collecting y terms (DV) on the left & x terms (IV) on the right

2) Compare to general linearity formula to verify it matches

<p>Steps:</p><p>1) Convert given equation to the general linear formula by…</p><p>(a) dividing all terms by dx when x = IV</p><p>(b) collecting y terms (DV) on the left &amp; x terms (IV) on the right</p><p>2) Compare to general linearity formula to verify it matches</p>
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Solution

“any function, defined on an interval I, with n continuous derivatives that satisfies the equation identically when substituted into it”

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Interval (I)

interval of definition, interval on which a particular solution to the ODE is defined

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Verification of Solution

substitute & determine whether each side of the equation is the same for every x in I

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Solution Curve

graph of a solution to an ODE 

1) They do NOT cross equilibrium lines & can NOT change signs

2) They either always go up or always go down (monotonic) - above or below

3) They eventually settle near equilibrium pts. - Bounded (between c1 & c2)

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Implicit Solution

“G(x,y)=0 of an ODE on I given that there exists 1 function that G(x, y(x))=0,” relating x & y w/o explicitly solving for y

Trick: rewrite y as y(x) to indicate that dy/dx will be needed

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Families of Solutions

set of relation functions with arbitrary Constant (C)

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Singular Solution

solution that’s NOT a member of the family of solution

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nth-Order Initial Value Problem (IVP)

“on some interval I containing x0 the problem of solving an nth order differential equation subject to n side conditions specified at x0

Steps:

1) Plug in 1st Initial Condition (IC)

2) Plug in 1st parameter

3) Differentiate

4) Plug in 2nd IC
5) Plug in 2nd parameter

<p>“on some interval I<em> </em>containing x<sub>0</sub> the problem of solving an nth order differential equation subject to n side conditions specified at x<sub>0</sub>”</p><p>Steps:</p><p>1) Plug in 1st Initial Condition (IC) </p><p>2) Plug in 1st parameter </p><p>3) Differentiate </p><p>4) Plug in 2nd IC <br>5) Plug in 2nd parameter</p>
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First-Order IVP

n=1

Solve: dy/dx=f(x,y)

Subject to: y(x0)=y0

Point (pt.)

<p>n=1</p><p>Solve: dy/dx=f(x,y)</p><p>Subject to: y(x<sub>0</sub>)=y<sub>0</sub></p><p>Point (pt.)</p>
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2nd-Order IVP

n=2

Solve: d²y/dx²=f(x,y,y’)

Subject to: y(x0)=y0,y’(x0)=y1

Slope

<p>n=2</p><p>Solve: d²y/dx²=f(x,y,y’)</p><p>Subject to: y(x<sub>0</sub>)=y<sub>0</sub>,y’(x<sub>0</sub>)=y<sub>1</sub></p><p>Slope</p>
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Existence & Uniqueness

“Let R be a rectangular region in the xy-plane defined by a ≤ x ≤ b, c ≤ y ≤ d that contains pt. (x0,y0). If f(x,y) & ∂f/∂y are continuous on R, then there exists some I0: (x0 - h, x0 + h), h ≥ 0, contained [a, b] & a unique function y(x)”

Note: I of definition does not have to be as wide as R & the I0 of existence & uniqueness might not be as large as I

Steps:

1) Continuous f(x,y) gives existences, so identify f(x,y)

2) Continuous ∂f/∂y gives uniqueness, so compute ∂f/∂y

3) Find where f(x,y) & ∂f/∂y are continuous

(a) No divisions by 0

(b) No even roots of negative numbers

(c) No logarithms of zero or negative numbers.

(d) No undefined expressions like 0/0 or ∞/∞

(e) No discontinuities in trigonometric functions (e.g., avoid tan(x) at x=2π+kπx ).

<p>“Let R be a rectangular region in the xy-plane defined by a ≤ x ≤ b, c ≤ y ≤ d that contains pt. (x<sub>0</sub>,y<sub>0</sub>). If f(x,y) &amp; ∂f/∂y are continuous on R, then there exists some I<sub>0</sub>: (x<sub>0 </sub>- h, x<sub>0 </sub>+ h), h ≥ 0, contained [a, b] &amp; a unique function y(x)”</p><p>Note: I of definition does not have to be as wide as R &amp; the I<sub>0</sub> of existence &amp; uniqueness might not be as large as I</p><p>Steps:</p><p>1) Continuous f(x,y) gives existences, so identify f(x,y)</p><p>2) Continuous ∂f/∂y gives uniqueness, so compute ∂f/∂y</p><p>3) Find where f(x,y) &amp; ∂f/∂y are continuous</p><p>(a) No divisions by 0</p><p>(b) No even roots of negative numbers</p><p>(c) No logarithms of zero or negative numbers.</p><p>(d) No undefined expressions like 0/0 or ∞/∞</p><p>(e) No discontinuities in trigonometric functions (e.g., avoid tan(x) at x=2π+kπx ).</p>
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Population Growth

“rate of population growth at a time is proportional to the population at that time”

P(t) = population at time (t)

k = constant of probability

P(t) = P0(t)ekt

Note: It is decay if k < 0.

<p>“rate of population growth at a time is proportional to the population at that time”</p><p>P(t) = population at time (t)</p><p>k = constant of probability</p><p>P(t) = P<sub>0</sub>(t)e<sup>kt</sup></p><p>Note: It is decay if k &lt; 0.</p>
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Radioactive Decay

“the rate dA/dt at which the nuclei of a substance decay is proportional to the amount A(t) of the substance remaining at time t”

A(t) = A0e-kt

<p>“the rate dA/dt at which the nuclei of a substance decay is proportional to the amount A(t) of the substance remaining at time t”</p><p>A(t) = A<sub>0</sub>e<sup>-kt</sup></p>
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Compound Growth

“growth of capital S when annual rate of interest r is compounded”

<p>“growth of capital S when annual rate of interest r is compounded”</p>
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Newton’s Empirical Law of Cooling/Warming

“the rate at which temperature (temp.) of a body changes is proportional to the difference between temp. of body & ambient temp.”

T(t) = Tm + (T0 -Tm)ekt

T(t) = temp. of body at time t

Tm = ambient temp.

k = constant of probability

k > 0: warming

k < 0: cooling

<p>“the rate at which temperature (temp.) of a body changes is proportional to the difference between temp. of body &amp; ambient temp.”</p><p>T(t) = T<sub>m</sub> + (T<sub>0</sub> -T<sub>m</sub>)e<sup>kt</sup></p><p>T(t) = temp. of body at time t</p><p>T<sub>m</sub> = ambient temp.</p><p>k = constant of probability</p><p>k &gt; 0: warming</p><p>k &lt; 0: cooling</p>
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Spread of Disease

“the rate dx/dt in which the disease spread is proportional to the number (#) of interactions between diseased people x(t) & unexposed people y(t)”

<p>“the rate dx/dt in which the disease spread is proportional to the number (#) of interactions between diseased people x(t) &amp; unexposed people y(t)”</p>
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1st Order Chemical Reactions

“disintegration of a radioactive substance”

X(t) = amount of substance A at any time t

k = negative constant

<p>“disintegration of a radioactive substance”</p><p>X(t) = amount of substance A at any time t</p><p>k = negative constant</p>
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2nd Order Chemical Reactions

“disintegration of a radioactive substance”

X(t) = amount of C at time t

α = amount of A

β = amount of B

α - X = amount of A not converted to C
β - X = amount of B not converted to C

<p>“disintegration of a radioactive substance”</p><p>X(t) = amount of C at time t</p><p>α = amount of A</p><p>β = amount of B </p><p>α - X = amount of A not converted to C <br>β - X = amount of B not converted to C </p>
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<p>Mixture</p>

Mixture

“the amount of salt in a mixture of 2 salt solutions of differing concentrations”

A(t) = amount of salt in tank at time t

Rin = input rate of salt

Rout = output rate of salt

R = concentration * rate

<p>“the amount of salt in a mixture of 2 salt solutions of differing concentrations”</p><p>A(t) = amount of salt in tank at time t</p><p>R<sub>in</sub> = input rate of salt</p><p>R<sub>out</sub> = output rate of salt</p><p>R = concentration * rate </p>
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<p>Draining a Tank</p>

Draining a Tank

“Torricelli’s Law states that the speed of which a fluid flows out of a hole of a container is equal to the speed of it falling freely from the height of the fluid’s surface to the level of the hole.”

Ah = area (ft3) of hole

v = √2gh = speed (ft/s) of water leaving the tank

V(t) = Awh = volume of water leaving the tank at time t

<p>“Torricelli’s Law states that the speed of which a fluid flows out of a hole of a container is equal to the speed of it falling freely from the height of the fluid’s surface to the level of the hole.”</p><p>A<sub>h</sub> = area (ft<sup>3</sup>) of hole </p><p>v = <span>√2gh = speed (ft/s) of water leaving the tank</span></p><p><span>V(t) = A<sub>w</sub>h = volume of water leaving the tank at time t</span></p>
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<p>LRC Series Circuit</p>

LRC Series Circuit

“Kirchoff’s 2nd Law states the impressed voltage E(t) in a closed loop equals the sum of the voltage drop.”

E(t) = impressed voltage

i(t) = current in closed circuit

q(t) = charge incapacitor at time t

L = inductance

R = Resistance

C = Capacitance

<p>“Kirchoff’s 2<sup>nd</sup> Law states the impressed voltage E(t) in a closed loop equals the sum of the voltage drop.”</p><p>E(t) = impressed voltage </p><p>i(t) = current in closed circuit </p><p>q(t) = charge incapacitor at time t</p><p>L = inductance</p><p>R = Resistance </p><p>C = Capacitance </p>
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<p>LR Series Circuit</p>

LR Series Circuit

E(t) = impressed voltage

i(t) = current in closed circuit

q(t) = charge incapacitor at time t

L = inductance

R = Resistance

<p>E(t) = impressed voltage</p><p>i(t) = current in closed circuit</p><p>q(t) = charge incapacitor at time t</p><p>L = inductance</p><p>R = Resistance</p>
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<p>RC Series Circuit</p>

RC Series Circuit

E(t) = impressed voltage

i(t) = dq/dt current in closed circuit

R = Resistance

C = Capacitance

<p>E(t) = impressed voltage</p><p>i(t) = dq/dt current in closed circuit</p><p>R = Resistance</p><p>C = Capacitance</p>
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<p>Falling Bodies </p>

Falling Bodies

“Newton’s 1st law states a body in motion remains in motion & a body at rest remains at rest unless acted upon by a force. Newton’s 2nd Law states Force = mass * acceleration.”

s(t) = height position of falling object (obj.)

d2s/dt2 = acceleration of falling obj.

<p>“Newton’s 1<sup>st </sup>law states a body in motion remains in motion &amp; a body at rest remains at rest unless acted upon by a force. Newton’s 2<sup>nd</sup> Law states Force = mass * acceleration.”</p><p>s(t) = height position of falling object (obj.)</p><p>d<sup>2</sup>s/dt<sup>2</sup> = acceleration of falling obj.</p>
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<p>Falling Bodies w/ Air Resistance</p>

Falling Bodies w/ Air Resistance

“when air is proportional to velocity”

mg = F1 = W

-kv = F2 = viscous damping

W = weight

m = mass

g = gravity

s(t) = distance body falls

ds/dt = v = velocity

d2s/dt2 = dv/dt = a = acceleration

<p>“when air is proportional to velocity”</p><p>mg = F<sub>1</sub> = W</p><p>-kv = F<sub>2</sub> = viscous damping </p><p>W = weight </p><p>m = mass</p><p>g = gravity </p><p>s(t) = distance body falls</p><p>ds/dt = v = velocity </p><p>d<sup>2</sup>s/dt<sup>2 </sup>= dv/dt = a = acceleration </p>
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<p>Suspended Cables</p>

Suspended Cables

“3 forces act on the cables - tension T1 (tangent to P1), tension T2 (tangent to P2), & Weight W (between P1 & P2)

T1 = cosθ

W = T2sinθ

tanθ = W/T1

<p>“3 forces act on the cables - tension T<sub>1</sub> (tangent to P<sub>1</sub>), tension T<sub>2</sub> (tangent to P<sub>2</sub>), &amp; Weight W (between P<sub>1</sub> &amp; P<sub>2</sub>)</p><p>T<sub>1 </sub>= cos<span>θ</span></p><p>W = T<sub>2</sub>sin<span>θ</span></p><p><span>tanθ = W/</span>T<sub>1</sub></p>
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Lineal Element

“the value f(x,y) that the function f assigns to the pt. represents the slope of the line segment,” dy/dx = m

Note: passing through pts. on any horizontal line must have the same slope & is parallel; slope of lineal along any vertical line vary

<p>“the value f(x,y) that the function f assigns to the pt. represents the slope of the line segment,” dy/dx = m</p><p>Note: passing through pts. on any horizontal line must have the same slope &amp; is parallel; slope of lineal along any vertical line vary</p>
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Direction Field / Slope Field

“collection of all line elements at each pt. (x, y) of a rectangular grid w/ slope f(x,y); appearance/shape of a family of solution curves of the differential equation”

“A single solution curve that passes through a direction field must follow the flow pattern of the field; it is tangent to a lineal element when it intersects a point in the grid”

Note: both definitions are true, recall whichever phrasing is the most helpful for you

<p>“collection of all line elements at each pt. (x, y) of a rectangular grid w/ slope f(x,y); appearance/shape of a family of solution curves of the differential equation”</p><p>“A single solution curve that passes through a direction field must follow the flow pattern of the field; it is tangent to a lineal element when it intersects a point in the grid”</p><p>Note: both definitions are true, recall whichever phrasing is the most helpful for you </p>
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Autonomous

an ODE in which the IV does not appear explicitly

<p>an ODE in which the IV does not appear explicitly </p>
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Phase Line Example

P(a - bP) = 0 → P = 0, a/b

Interval | Sign of f(P) | P(t) | Arrow

(-∞, 0) | minus | decreasing | down

(0, a/b) | plus | increasing | up

(a/b, ∞) | minus | decreasing | down

<p>P(a - bP) = 0 → P = 0, a/b</p><p>Interval | Sign of f(P) | P(t) | Arrow</p><p>(-∞, 0) | minus | decreasing | down</p><p>(0, a/b) | plus | increasing | up</p><p>(a/b, ∞) | minus | decreasing | down</p>
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Asymptotically stable/Attractor, Unstable/Repeller, Semi-Stable

Asymptotically stable/Attractor: when the arrowhead of both sides point towards c; lim x→∞ y(x) = c

Unstable/Repeller: when the arrowheads of both side point away c

Semi-Stable: both attracts & repels

<p>Asymptotically stable/Attractor: when the arrowhead of both sides point towards c; lim x→∞ y(x) = c</p><p>Unstable/Repeller: when the arrowheads of both side point away c</p><p>Semi-Stable: both attracts &amp; repels </p>
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Translation Property (of an autonomous DE)

“If y(x) is a solution of an autonomous DE dy/dx = f(y), then y(x) =y(x -k), k = constant, is also a solution.”

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Separable 1st Order DE

can be separated as a product of a function of x & a function of y (can be linear or nonlinear)

Steps:

1) Separate y terms on the right & x terms on the left

2) Integrate

3) If asked, solve for y

<p>can be separated as a product of a function of x &amp; a function of y (can be linear or nonlinear)</p><p>Steps:</p><p>1) Separate y terms on the right &amp; x terms on the left </p><p>2) Integrate</p><p>3) If asked, solve for y</p>
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Integral Defined Function

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Linear 1st Order DE

Follows the linear general formula: a1(x)(dy/dx) + a0(x)y = g(x)

Steps:

1) Put into standard form; (dy/dx) + P(x)y = f(x)

2) Identify P(x) & find the integrating factor: μ = eP(x)dx

3) Multiply both sides of the standard form by the integrating factor. The LHS of the resulting equation is the derivative of the product of integrating factor & y.

4) Integrate both sides of the last equation.

5) If asked, solve for y

<p>Follows the linear general formula: a<sub>1</sub>(x)(dy/dx) + a<sub>0</sub>(x)y = g(x)</p><p>Steps:</p><p>1) Put into standard form; (dy/dx) + P(x)y = f(x)</p><p>2) Identify P(x) &amp; find the integrating factor: μ = e<strong><sup>∫</sup></strong><sup>P(x)dx</sup></p><p>3)  Multiply both sides of the standard form by the integrating factor. The LHS of the resulting equation is the derivative of the product of integrating factor &amp; y. </p><p>4) Integrate both sides of the last equation.</p><p>5) If asked, solve for y</p>
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Transient Terms

We say that ce-x is a transient term, since e-x → 0 as x →

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Error Function

defined in terms of nonelementary integrals

<p>defined in terms of nonelementary integrals</p>
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Exact 1st Order DE

Differential is continuous & has continuous 1st partial derivatives in R defined by a < x < b & c < y < d on some function f(x,y)

Steps:

1) Set in Exact Equation

2) Integrate w.r.t. x / Integrate w.r.t. y

3) Partial Differentiate w.r.t. y / Partial Differentiate w.r.t. x

4) Integrate h’(y) / Integrate g’(x)

5) Final answer = C

<p>Differential is continuous &amp; has continuous 1<sup>st</sup> partial derivatives in R defined by a &lt; x &lt; b &amp; c &lt; y &lt; d on some function f(x,y) </p><p>Steps:</p><p>1) Set in Exact Equation</p><p>2) Integrate w.r.t. x / Integrate w.r.t. y</p><p>3) Partial Differentiate w.r.t. y / Partial Differentiate w.r.t. x </p><p>4) Integrate h’(y) / Integrate g’(x) </p><p>5) Final answer = C</p>
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Homogenous 1st Order DE

<p></p>
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Homogenous & Exact 1st Order DE

The Exact equation, M(x,y)dx + N(x,y) = 0, is Homogenous if the coefficient functions M(x,y) & N(x,y) are homogenous functions of the same degree (where α is equal to one another)

Substitute y = ux or x = vy

<p>The Exact equation, M(x,y)dx + N(x,y) = 0, is Homogenous if the coefficient functions M(x,y) &amp; N(x,y) are homogenous functions of the same degree (where α is equal to one another)</p><p>Substitute y = ux or x = vy</p>
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Bernoulli 1st Order DE

Can be reduced to a linear equation by means of substitution (linear & separable)

<p>Can be reduced to a linear equation by means of substitution (linear &amp; separable) </p>
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How do you determine which 1st - Order DE strategy to implement?

1) Separability → Separable

2) Linearity → Linear

3) Exactness (w/ or w/o Integrating Factor) → Exact

4) Single Nonlinearity → Bernoulli

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Euler’s Method

Linearization of the unknown solution of y’(x) = f(x, y) , y(x0) = y0

<p>Linearization of the unknown solution of y’(x) = f(x, y) , y(x<sub>0</sub>) = y<sub>0</sub></p>
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Absolute Error, Relative Error, Percentage Relative Error

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Half-Life

“time it takes for ½ of the atoms in an initial amount A0 of a radioactive substance to transmute into the atoms of another element,” measuring the stability of a radioactive substance

<p>“time it takes for ½ of the atoms in an initial amount A<sub>0</sub> of a radioactive substance to transmute into the atoms of another element,” measuring the stability of a radioactive substance</p>
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Carbon Dating

“comparing the proportionate amount of C-14 in a fossil w/ constant ratio found in the atmosphere to estimate an age”

<p>“comparing the proportionate amount of C-14 in a fossil w/ constant ratio found in the atmosphere to estimate an age”</p>