Linear Algebra Exam Three

0.0(0)
studied byStudied by 0 people
call kaiCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/22

encourage image

There's no tags or description

Looks like no tags are added yet.

Last updated 12:52 AM on 4/1/25
Name
Mastery
Learn
Test
Matching
Spaced
Call with Kai

No analytics yet

Send a link to your students to track their progress

23 Terms

1
New cards

Coordinate Systems

Suppose the set B = {b1, b2, …, bp} is a basis for a subspace H. For each x in H, x = c1b1 + c2b2 + … + cpbp, the coordinates of x relative to the basis B are the weights c1, c2, …, cp

2
New cards

Coordinate Vector

The vector in Rp [x]B =

c1
c2

cp

is called ______ of x relative to B or B-coordinate vector of x

3
New cards

Coordinate Mapping (Linear Transformation)

x |→ [x]B

4
New cards

Theorem 4.15

Let B = {b1, b2, …, bp} and C = {c1, c2, …, cp} be bases of a vector space V. Then there is a unique n x n matrix C ← B (with a P above the arrow), such that [x]C = C ← B [x]B (with a P above the arrow), the columns of C ← B (with a P above the arrow) are the C-coordinate vectors of the vectors in the basis B

C ← B (with a P above the arrow) = [[b1]C [b2]C … [bp]C ]

^Change-of-coordinates matrix from B to C

5
New cards

Applications of Eigenvectors and Eigenvalues

Web ranking system design, image compression

6
New cards

Eigen-

Adopted from the German word “eigen” for “own,” “proper,” or “characteristic” (chapter 5.2, the characteristic equation)

7
New cards

Eigenvector

An _____ of an n x n matrix A is a nonzero vector x such that Ax = λx for some scalar λ

8
New cards

Eigenvalue

A scalar λ is called a ______ of A if there is a nontrivial solution x of Ax = λx, such that x is called an eigenvector corresponding to λ

9
New cards

All the solutions of (A - λI)x = 0 is the ______ of A - λI

Null space

10
New cards

Eigenspace

Nul(A - λI) is a subspace of Rn and is called the ______ of a A corresponding to λ

11
New cards

Theorem 5.1

The eigenvalues of a triangular matrix are the entries on its main diagonal.

λ is an eigenvalue of A ←> (A - λI)x = 0 has nontrivial solution ←> A - λI is not invertible ←> det(A - λI) = 0

det(A - λI) = the product of the entries on the main diagonal since A - det(A - λI)I is also a triangular matrix

12
New cards

Theorem 5.2

If v1, …, vr are eigenvectors corresponding to distinct eigenvalues λ1, …, λr of an n x n matrix A, then {v1, …, vr} is linearly independent

← is false

13
New cards

5.2 The Characteristic Equation

Ax = λx ←> (A - λI)x = 0
Has nontrivial solution → (A - λI) is not invertible

→ det(A - λI) = 0

14
New cards

Characteristic Equation

det(A - λI) = 0

15
New cards

Characteristic Polynomial

det(A - λI)

16
New cards

A scalar λ is an _____ of an n x n matrix A if and only if, det(A - λI) = 0

eigenvalue

17
New cards

Algebraic Multiplicity

This of an eigenvalue λ is its multiplicity as a root of the characteristic equation

18
New cards

Similarity

If A and B are n x n matrix and there exists an invertible matrix P such that P-1 A P = B → A is similar to B

A = PBP-1 , let Q = P-1

→ A = Q-1 B Q

→ B is similar to A
A |→ P-1 A P is called _______ transformation

19
New cards

Theorem 5.4

If n x n matrix A and B are similar, then they have the same characteristic polynomial and hence same eigenvalues (with the same multiplicity)

20
New cards

Diagonalizable

If an n x n matrix A is similar to a diagonal matrix, then A is said to be _____
(A = P-1 D P, where D is a diagonal matrix and P is invertible)

21
New cards

Theorem 5.5: The Diagonalization Theorem

An n x n matrix A is diagonalizable if and only if A has n linearly independent eigenvectors. In fact, A = P D P-1 if and only if the columns of P are n linearly independent eigenvector of A, and D is a diagonal matrix with diagonal entries are eigenvalues of A that corresponds to the eigenvectors in P

22
New cards

Theorem 5.6

An n x n matrix with n distinct eigenvalues is diagonalizable

Proof:

Theorem 5.2 → n distinct eigenvalues are corresponding to n linearly independent eigenvectors

Theorem 5.5 → the matric is diagonalizable

23
New cards

Cases of 3 × 3 Matrix Diagonalization (with real eigenvalues)

Three cases, check notes!!

Explore top flashcards

Hinduism
Updated 1056d ago
flashcards Flashcards (20)
Civil Rights EK 3
Updated 14d ago
flashcards Flashcards (60)
Vocab Unit 1
Updated 866d ago
flashcards Flashcards (50)
Muscular System I
Updated 368d ago
flashcards Flashcards (124)
50 States
Updated 203d ago
flashcards Flashcards (50)
1017
Updated 394d ago
flashcards Flashcards (55)
Hinduism
Updated 1056d ago
flashcards Flashcards (20)
Civil Rights EK 3
Updated 14d ago
flashcards Flashcards (60)
Vocab Unit 1
Updated 866d ago
flashcards Flashcards (50)
Muscular System I
Updated 368d ago
flashcards Flashcards (124)
50 States
Updated 203d ago
flashcards Flashcards (50)
1017
Updated 394d ago
flashcards Flashcards (55)