OCHEM 1 Final

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Cerritos College

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20 Terms

1
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NaH, DBN, DBU

Strong Base, Weak nucleophile (E2)

2
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HO-, MeO-, EtO-

Strong Base, Strong Nucleophile (SN2, E2)

3
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I-, Br-, Cl-, RS-, HS-, RSH, H2S

Weak base, Strong nucleophile (SN1, SN2)

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H2O, MeOH, EtOH

Weak base and weak nucleophile (SN1, E1)

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SN1

  • substitution w/ strong nucleophile

  • methyl & hydride shifts

  • bad sterics

  • polar protic solvent

  • NO STEREOCHEM

  • Weak Bases: alcohols, water, nucleophiles

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SN1 - Rate

Rate = k[alkyl halide]

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SN2

  • one step

  • alpha & beta carbon pos is very important

  • Polar aprotic solvent: acetone, DMSO, DMF (no h-bond)

  • good leaving group

  • Back side attack ~ stereochem ~ chiral center inverts

  • No shifts

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SN2 Rate

Rate = k[alkyl halide][nucleophile]

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E1

  • Carbocation forms ~ rate determining step

  • Hydrogen shift ~ beta hydrogen moves to form alkene or tertiary

    • This works to form the most stable carbocation

  • Weak Base: H2O, Neutral Base,

  • Polar Protic Solvent

  • Temperature needed

  • Zaitsev product forms

  • No STEREOCHEM

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E1 Rate

Rate = k[alkyl halide]

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E2

  • strong base moves beta hydrogen to form alkene

  • No carbocation

  • STEREOCHEM - the beta hydrogen has to be anti to the leaving group

  • Strong Base:

    • Small: OH-, OEt-, OMe-

    • t-BuO-, LDA, DBU/ DBN

  • Polar Protic Solvent

  • Zaitsev and Hoffman

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E2 Rate

Rate = k[Substrate][base]

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Reaction 1 - HX Addition

Reagent - HX

Cond: Markovnikov + Methyl/ Hydride shifts + Tertiary (or closest) + 2 step + adds nucleophile

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Reaction 2 - HBr + ROOR

Reagent - HBr + ROOR

Cond: Peroxide + Antimarkovnikov + forms terminal Bromines

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Reaction 3 - Acid-catalyzed hydration

Reagent - H3O+

Cond: Markonivkov + Equilibrium + forms alcohol

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Reaction 3 - Oxymercuration-demurcuration

Reagent:

  1. Hg(OAc)2, H2O

  2. NaBH4

Cond: no need to mem. mech + can have methyl/ hydride shifts + two part rxn + markonivkov + forms alcohol

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Reaction 4 - Hydroboration-oxidation

Reagent:

  1. BH3*THF

  2. H2O2, NaOH

Cond: peroxides needed + forms alcohol + syn formed with alcohol and beta hydrogen + enantiomers

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Reaction 6 - Halogenation of Alkenes

Reagents: Cl2 or Br2

Cond: two halogens attach + triangle forms + carbocation forms + halogens end anti

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Reaction 7 - Formation of Halohydrins

Reagents: Br2 + H2O

Cond: alcohol and halogen both attach + attached groups are anti + triangle forms with one of the Halogens + alcohol breaks triangle and attaches

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Reaction 8 - Epoxides

Reagents:

  1. Peroxy Acid, RCOOOH, mCPBA

  2. H3O

Cond: oxygen triangle forms + Syn