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Linear Independence
if Ax=0 has ONLY the trivial solution
Linear Transformations
Ax=b
Domain
R^n (input)
Codomain
R^m (output)
Range
set of all possible b's for Ax=b
span of transformation matrix = {T.A}
One-to-ONe
For every b in R^m, there is only one x
1 input -> 1 output
Unique solution
Pivot in every COLUMN
Onto
For every b in R^m there exist at least one x
Range = codomain
Pivot in every ROW
Ax=b
Given A and x, how do you find b?
[A|B] = x
Given A and b, how do you find x?
Subspace H
-includes zero vector
-includes sum of vectors (u+v)
-includes scalars of vectors (cu)
ColA
set of all possible linear combinations of A
= span{A}
NulA
set of all solutions to Ax=0
Dimension
# of vectors in basis
Dim(ColA)
rank
Dim(NulA)
# of free variables
Rank
# of pivot columns
[A|1]
inverting an nxn matrix
x=(A^-1)b
Given A and b, find x
Diagonalizable
if A is an nxn matrix that has n linearly independent eigenvectors
Geometric Multiplicity
dim(eigenspace)
Linear Combination
sum of scaled vectors
c1v1+c2v2+...+cnvn
Transpose
an nxm matrix turned into an mxn matrix by turning the columns into rows and vice versa
Inverse
Ax=b has one solution, AB=1 and BA=1
Determinant
-row replacements do not change outcome
-scaled by same scale of the matrix
-row swaps scale outcome by -1
Eigenvalue
a number in R such that Av=(this #)v has a nontrivial solution
Eigenspace
set of all eigenvectors of A with the same eigenvalues, plus the zero vector
Orthogonal
perpendicular
x dot y = 0
Orthonormal
each pair of vectors is orthogonal and each vector is a unit vector
x bar parallel is
the orthogonal projection of x bar onto the line
two vectors are orthogonal to each other if
u * v = 0
magnitude is
the square root of each component squared
In an LU decomposition, the columns of L are
the pivotal columns in original matrix
In an LU decomposition, U is
the reduced echelon form of A
length is
the magnitude squared
a unit vector is
a vector whose length is 1
to diagonalize a 3x3 matrix,
find P and D. P is the matrix of eigenvectors, D is the coreesponding matrix with eigenvalues in diagonals
b is a linear combination of a if
there are solutions to the augmented matrix
consistent means
there are one or more solutions to the system
inconsistent means
there are no solutions to the system
a solution set with one free variable is a ____, two free variables is a ______
line, plane
the additive property of linear transformations
T(x+y)=T(x)+T(y)
the scalar property of linear transformations
T(cx)=cT(x)
linearly independent has _____ solutions
trivial
a linearly dependent system has ______ solutions
nontrivial
to find the determinant of a 3x3 matrix using diagonals
downward products - upward
to find the determinant of a 3x3 matrix using reducing
multiply the diagonals of the echelon form matrix
lambda is an eigenvalue if A-(lambda)I is a linearly _______ matrix
dependent
basis for ColA is given by
the pivotal columns
dimension for ColA
number of pivotal columns
basis for NulA is given by
soln vectors to Ax=0
dimension of NulA
number of vectors in the basis for NulA
equation for RankA
RankA+dim of NulA=n
algebraic multiplicity
the number of times it is an eigenvalue
geometric multiplicity
the number of eigenvectors for an eigenvalue
to find the Inverse of a 3x3 matrix,
set up [A I] and reduce to [I A]
how to find if a vector (u) is in the Nul space of A
if Au=0, then it is in the Nul space
how to find a vector in ColA
just a column of A
how to find a vector in NulA
a soln vector in terms of the free variable
cosine of angle between vectors v and u
(uv)/(IuIIvI)
scalar component of u in direction of v
(u*v)/IvI
implicit equation
y = mx + b, a line in a plane
parametric form
coordinates where one point is in terms of the other variables
(x,y) = (t, 1-t)
linear equation
a1x1+a2x2... = b
system of linear equations
collection of linear equations
consistent linear system
a system of equations with solutions
equivalent linear systems
2+ linear systems with the SAME solution set
m x n matrix
m rows and n columns
augmented matrix
matrix with solutions on one side
elementary row operations
scale, swap, row replacement
row equivalent
one matrix can be obtained from the other using row operations, have the same solution set
inconsistent matrix
the last column (the augmented column) is a pivot column - no solution to the linear system
Rⁿ
the set of ordered lists of n numbers
row echelon form
all zero rows at the bottom
first non zero in each row is farther right as you go down
below a leading entry its all zeroes
pivot
first nonzero number of a row
pivot column
column that contains a pivot IF matrix is in row echelon form
reduced row echelon form
row echelon + all pivots are 1 + pivot columns only contain the pivot
free variable
if the corresponding column is not a pivot column
parametric form
write matrix solution as system of linear equations, and move all free variables to the right of =
possible number of solutions to a matrix
zero, one, infinite
vector
coordinates in Rⁿ drawn as an arrow - length and direction, not location
properties of vectors
all regular addition and multiplication properties
vector addition
head to tail
vector subtraction
tail to tail
linear combination of vectors
combining vectors into one equation to produce a new vector
span
all the linear combinations of a set of vectors - "creates" the plane or the space
the set of solutions to Ax = 0
matrix equation
Ax = b
Ax = b has a solution if and only if...
b is in the span of the columns of A = b is a linear combination of v1, v2, vn
a solution always exists IF...
Ax = b has a solution for all b
the span of A is ALL of Rm
A has a pivot in every row
homogenous
set of linear equations where Ax=0
inhomogenous
Ax = b
trivial solution
x vector = 0
non trivial solution
non zero solutions - IF there is a free variable = a column with no pivot
parametric vector form
list all equations from reduced matrix including free varaiables, and move free variables to the right of = to make a vector equation
solution set of Ax = 0
creates the span
solution set is a line
one free variable
solution set is a plane
two free variables
homogenous vs nonhomogeous solutions
vector associated with free varable stays the same but an additional translation vector is added
= translation of a span
column span
span of the columns of A
all b that makes Ax = b consistent
solution set
all x so that Ax = b
b is fixed (different than column span)
linear independence
only has the trivial solution (only constant that relates the vectors is 0)
each vector is independent of the others
matrix A has a pivot in every column!!