Zumdahl Chemistry Chapter 4, 5, 6, 10, 18 All Needed Equations

5.0(1)
studied byStudied by 3 people
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
Card Sorting

1/44

encourage image

There's no tags or description

Looks like no tags are added yet.

Study Analytics
Name
Mastery
Learn
Test
Matching
Spaced

No study sessions yet.

45 Terms

1
New cards

Molarity Equation

M=mol/L

2
New cards

1 atm

101,325 Pa

101.325 kPa

760 mmHg

760 torr

14.7 psi

1.01 bar

3
New cards

Van Der Waals Equation

[Pobs + a(n/V)^2](V - nb) = nRT

4
New cards

Ideal Combined Gas Law

(P1V1/n2T2) = (P2V2/n2T2)

5
New cards

Boyle’s Gas Law

P1V1 = P2V2

6
New cards

Charle’s Gas Law

(V1/T1) = (V2/T2)

7
New cards

Avogadro’s Gas Law

(V1/n1) = (V2/n2)

8
New cards

Real Gas Law

Pobs + a(n/V)2(V-nb) = nRT

9
New cards

Ideal Gas Law

PV = nRT

10
New cards

Density Ideal Gas Law

d = (PM/RT)

11
New cards

Molar Mass of A Gas Equation

M = (dRT/P)

12
New cards

Mole Fraction

X1 = (n1/nTotal) = (n1/n1 + n2 + n3 + n)

13
New cards

Dalton Law of Partial Pressures

PTotal = P1 + P2 + P3 + …

14
New cards

Pressure and Volume (Boyle’s Law)

P = (nRT)(1/V)

15
New cards

Pressure and Temperature (Ideal Gas Law)

P = (nR/V)T

16
New cards

Volume and Temperature (Charles’s Law)

V = (nR/P)T

17
New cards

Volume and Number of Moles (Avogadro's Law)

V = (RT/P)n

18
New cards

STP gasses

22.4 L/mol

19
New cards

Non-STP gasses

PV = nRT

20
New cards

Density of Water

1.00 g/mL or 1000 g/L

21
New cards

Constant Pressure Calorimetry

qsoln = msoln cs,soln ΔT

22
New cards

Energy of Reaction Using Calorimetry

qrxn = -qsoln

23
New cards

Calorimetry With Multiple Substances

qsoln + qsoln =-q3

24
New cards

Isochoric (Constant Volume)

  1. ΔU = ±Q

  2. ΔV = 0

  3. W = 0

  4. Q = nCvΔT

P1/T1 = P2/T2

25
New cards

Isobaric (Constant Pressure)

  1. ΔU = ±q ±w

  2. ΔP = 0

  3. W = PΔV

    • W = nRΔT

  4. Q = nCpΔT

  5. ΔV = nCvΔT

    • V1/T1 = V2/T2

26
New cards

Isothermal (Constant Temperature)

  1. W = ±Q

    • W = nRT * ln(Vf/Vi)

  2. ΔT = 0

  3. Q = W

    • Q = nRT * ln(Pi/Pf)

  4. ΔV = 0

    • P1/V1 = P2/V2

27
New cards

Adiabatic (No Heat Flow)

  1. CV = 3/2 R

  2. W = -nCVΔT

  3. Q = 0

  4. ΔU = ±W

28
New cards

Internal Energy of System

U = ±Q ∓W

29
New cards

Cautious-Clapeyron Equation at 1 Temperature

Loge(P) = -Delta H/RT

30
New cards

Cautious-Clapeyron Equation at 1 Temperature Enthalpy Derivative

Delta H = -Lne(P)[(RT)]

31
New cards

Cautious-Clapeyron Equation at 2 Temperature

Loge(P T1/P T2) = Delta H/R (1/T2 - 1/T1)

32
New cards

Cautious-Clapeyron Equation at 1 Temperature Temperature Derivative

T = -{[Lne(P)](R)}/Delta H

33
New cards

Cautious-Clapeyron Equation at 2 Temperature 2nd Pressure Derivative

P2={e^[(Delta Hvap/R)(1/T2 - 1/T1)]}/P1

34
New cards

Cautious-Clapeyron Equation at 2 Temperature Enthalpy Derivative

P2={e^[(Delta Hvap/R)(1/T2 - 1/T1)]}/P1

35
New cards

Root Mean Squared Velocity Equation

Sqrt{[(8.314J*mol^-1*K-1)(Temperature)]/(M in kg/mol)}

36
New cards

Diffusion Equation

R1/R2 = sqrt(M2/M1)

37
New cards

Effusion Equation

R = sqrt(1/M)

38
New cards

pH Equation

pH = -log[H+]

39
New cards

pOH Equation

pOH = -log[OH-]

40
New cards

pOH Equation

pH = -log[H+]

41
New cards

pH to molar concentration

10^-pH

42
New cards

pOH to molar concentration

10^-pOH

43
New cards

Sum of pH and pOH

pH + pOH = 14

44
New cards

Cautious-Clapeyron Equation at 2 Temperature 2nd Temperature Derivative

T2 = [(1/T1) - RLoge(P T1/P T2)/Delta Hvap]^-1

45
New cards

Gas Constant (R)

8.314 J*mol^-1*K^-1

0.08206 L*atm*mol^-1*K^-1