AP Calculus BC Unit 10 Convergence & Divergence Tests

0.0(0)
studied byStudied by 0 people
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
Card Sorting

1/7

encourage image

There's no tags or description

Looks like no tags are added yet.

Study Analytics
Name
Mastery
Learn
Test
Matching
Spaced

No study sessions yet.

8 Terms

1
New cards

nth-Term Test

Diverges if the limit does not equal zero

<p>Diverges if the limit does not equal zero</p>
2
New cards

Geometric Series

Does an = ar^n-1, n >/= 1

If not, use a different test

If |r| < 1 then convergent

If |r| > 1 then Divergent

Example : Σ5(1/2)^n

r = 1/2 which is less than 1, so it is convergent

<p>Does an = ar^n-1, n &gt;/= 1</p><p>If not, use a different test</p><p>If |r| &lt; 1 then convergent</p><p>If |r| &gt; 1 then Divergent</p><p>Example : Σ5(1/2)^n</p><p>r = 1/2 which is less than 1, so it is convergent</p>
3
New cards

P-Series

p>1 converges

p<1 diverges

Example : an = 1/n^P

<p>p&gt;1 converges</p><p>p&lt;1 diverges</p><p>Example : an = 1/n^P</p>
4
New cards

Alternating Series

Does an = (-1)^n bn, or

an = (-1)^n+1 bn, b > 0

If yes, then is limbn = 0 and bn+1/bn < 1

Or is the nth term approaching 0 and is the term decreasing. If so, it is convergent

Example : Σ(-1)(5x)^2/(n^3)+8

Approaches 0 and is decreasing so it is convergent

<p>Does an = (-1)^n bn, or</p><p>an = (-1)^n+1 bn, b &gt; 0</p><p>If yes, then is limbn = 0 and bn+1/bn &lt; 1</p><p>Or is the nth term approaching 0 and is the term decreasing. If so, it is convergent</p><p>Example : Σ(-1)(5x)^2/(n^3)+8</p><p>Approaches 0 and is decreasing so it is convergent</p>
5
New cards

Comparison Test

Let 0 ≤ an ≤ bn, for all n.

1) If ∑bn converges, then ∑an converges.

2) If ∑an diverges, then ∑bn diverges.

<p>Let 0 ≤ an ≤ bn, for all n.</p><p>1) If ∑bn converges, then ∑an converges.</p><p>2) If ∑an diverges, then ∑bn diverges.</p>
6
New cards

Limit Comparison Test

if the limit as n approaches infinity of (given series/chosen series) is >0, the two series will converge/diverge together.

<p>if the limit as n approaches infinity of (given series/chosen series) is &gt;0, the two series will converge/diverge together.</p>
7
New cards

Integral Test

Where f(x) continuous, positive, decreasing over [1, ∞) and an=f(n), if 1∫∞f(x) convergent, Σan convergent. If 1∫∞f(x) divergent, Σan divergent.

<p>Where f(x) continuous, positive, decreasing over [1, ∞) and an=f(n), if 1∫∞f(x) convergent, Σan convergent. If 1∫∞f(x) divergent, Σan divergent.</p>
8
New cards

Ratio Test

lim as n approaches ∞ of ratio of (n+1) term/nth term > 1, series converges

<p>lim as n approaches ∞ of ratio of (n+1) term/nth term &gt; 1, series converges</p>