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Where is the TATA box typically located in eukaryotic genes?
A) 100-150 bp upstream of the transcription start site
B) 25-30 bp upstream of the transcription start site
C) At the transcription start site
D) Within the first exon of the gene
25-30 bp upstream of the transcription start site
Which of the following is TRUE about promoters in eukaryotic genes compared to bacterial genes?
A) Eukaryotic genes often produce polycistronic mRNAs
B) Each eukaryotic gene has its own promoter
C) Bacterial genes do not have promoters
D) Bacterial genes always have TATA boxes
Each eukaryotic gene has its own promoter
The __________ box is a key promoter element found about 25-30 base pairs upstream of the transcription start site in many eukaryotic genes and is essential for transcription initiation.
TATA
Unlike bacteria, eukaryotic cells do not typically produce __________ mRNAs; instead, each gene has its own promoter and is transcribed separately.
polycistronic
True or False: The TATA box is found in both bacterial and human genes and serves the same function in transcription initiation.
false
True or False: In eukaryotic cells, one promoter can control transcription of multiple genes like in bacterial operons.
false
What is the function of the 5’ cap added to eukaryotic mRNA?
A) Protects mRNA from degradation and is important for ribosome binding
B) Signals the start of transcription
C) Marks the mRNA for export from the nucleus only
D) Acts as a polyadenylation signal
Protects mRNA from degradation and is important for ribosome binding
Where does the ribonuclease cleave the pre-mRNA during the addition of the poly-A tail?
A) At the 5’ end of the mRNA
B) Immediately after the start codon
C) 11-30 nucleotides downstream of the AAUAAA sequence
D) At the exon-intron junction
11-30 nucleotides downstream of the AAUAAA sequence
Which enzyme adds the poly-A tail to the 3’ end of the mRNA?
A) RNA polymerase II
B) Poly-A polymerase
C) Ribonuclease
D) Spliceosome
Poly-A polymerase
Eukaryotic genes contain _________, which are removed during RNA processing, and ________, which are expressed regions coding for proteins.
introns; exons
The sequence ________ acts as a polyadenylation signal in the pre-mRNA that guides cleavage and polyadenylation.
AAUAAA
True or False: The poly-A tail is encoded directly in the DNA sequence of the gene.
false
Which cellular structure is primarily responsible for separating transcription and translation in eukaryotic cells?
A) Ribosome
B) Nuclear membrane
C) Golgi apparatus
D) Endoplasmic reticulum
Nuclear membrane
Which of the following is NOT a common point at which eukaryotic cells regulate gene expression?
A) Transcription initiation
B) mRNA transcript processing
C) mRNA translation
D) DNA replication
DNA replication
Why is mRNA export from the nucleus a critical regulatory step in eukaryotes?
A) It allows mRNA to be spliced properly
B) It controls when mRNA becomes available for translation in the cytoplasm
C) It increases mRNA stability
D) It enhances transcription initiation
It controls when mRNA becomes available for translation in the cytoplasm
What is the primary role of the promoter in gene transcription?
A) Site where ribosomes bind
B) Site where RNA polymerase binds
C) Site of mRNA splicing
D) Site where tRNA binds
Site where ribosomes bind
Which protein specifically recognizes the TATA box during transcription initiation in eukaryotes?
A) Sigma factor
B) RNA polymerase II
C) TATA-binding protein (TBP)
D) Enhancer-binding protein
TATA-binding protein (TBP)
Basal transcription factors are necessary because:
A) They enhance mRNA stability
B) They help recruit RNA polymerase to the promoter
C) They process introns from the mRNA
D) They initiate translation
They help recruit RNA polymerase to the promoter
Basal gene expression refers to a __________, __________ level of transcription that occurs even in the absence of additional regulatory signals.
low; consistent
True or False: The promoter region includes binding sites for both RNA polymerase and basal transcription factors.
true
Enhancer sequences are best described as:
A) Coding DNA sequences close to the promoter
B) DNA sequences that must be immediately upstream of the gene
C) Non-coding DNA sequences that regulate transcription and can be located far from the gene
D) RNA sequences that bind to repressors
Non-coding DNA sequences that regulate transcription and can be located far from the gene
Which of the following is TRUE about enhancer sequences?
A) They only activate transcription, never repress it
B) They function only when located upstream of the transcription start site
C) Their function depends on their DNA-protein interactions, not their position relative to the gene
D) They must be within 50 base pairs of the promoter to work
Their function depends on their DNA-protein interactions, not their position relative to the gene
Enhancers can act as __________ or __________ of transcription by interacting with proteins that influence RNA polymerase activity.
activators, repressors
Enhancer sequences are found in __________ regions of DNA and can be located either __________ or __________ the transcription start site.
non-coding, 5’, 3’
True or False: Enhancer sequences lose their function if they are moved from their original position near the gene.
false
True or False: Enhancers are part of euchromatic gene regulation because they influence the accessibility and activity of genes in loosely packed chromatin.
true
Transcription factors regulate gene expression by:
A) Binding only to promoter sequences
B) Binding only to enhancer sequences
C) Binding to both promoters and enhancers and recruiting other proteins to influence transcription
D) Binding randomly to DNA without sequence specificity
Binding to both promoters and enhancers and recruiting other proteins to influence transcription
Which feature allows transcription factors to regulate only specific genes?
A) Their ability to bind RNA polymerase directly
B) Their recognition of specific DNA sequences in enhancers or promoters
C) Their high abundance in the cell
D) Their capacity to bind to any DNA sequence
Their recognition of specific DNA sequences in enhancers or promoters
Which of the following is NOT a type of transcription factor?
A) Basal factors
B) Activators
C) Repressors
D) Ribosomes
Ribosomes
Transcription factors bind to __________ sequences to either induce or silence gene expression by recruiting other proteins that influence __________.
enhancer, transcription
The human genome encodes approximately __________ transcription factors that regulate gene expression.
2000
True or False: Transcription factors have no role in silencing gene expression.
false
True or False: Basal transcription factors are a class of transcription factors involved in general transcription initiation.
true
How do transcriptional activators enhance gene transcription?
A) By degrading RNA polymerase
B) By recruiting RNA polymerase to the promoter
C) By blocking enhancer sequences
D) By preventing DNA looping
By recruiting RNA polymerase to the promoter
What mechanism allows enhancer sequences located far from a gene’s promoter to influence transcription?
A) DNA methylation
B) RNA splicing
C) DNA looping
D) Protein degradation
DNA looping
Transcription factors bound to enhancer sequences can physically interact with the promoter through __________, which brings distant regions of DNA close together.
DNA looping
DNA looping allows enhancer-bound transcription factors to interact with the transcription machinery at the gene’s __________ site.
promoter
True or False: Enhancer sequences must be immediately adjacent to the promoter to influence transcription.
false
How do transcriptional activators enhance transcription initiation?
A) By degrading basal transcription factors
B) By directly interacting with basal transcription factors or via mediator proteins
C) By blocking RNA polymerase binding
D) By binding to the coding region of genes
By directly interacting with basal transcription factors or via mediator proteins
What is the role of mediator proteins in transcription activation?
A) To prevent RNA polymerase from binding to DNA
B) To facilitate interactions between activators and the basal transcription machinery
C) To degrade mRNA after transcription
D) To inhibit enhancer sequences
To facilitate interactions between activators and the basal transcription machinery
Transcriptional activators help stabilize the __________ at the promoter to increase the rate of transcription initiation.
transcription machinery
Cooperation between different transcription factors increases the recruitment of __________ to the promoter.
RNA polymerase
True or False: Transcriptional activators only interact directly with RNA polymerase to enhance transcription.
false
True or False: Mediator proteins act as bridges between transcriptional activators and basal transcription factors.
true
What is the purpose of the chemical crosslinking step in ChIP-Seq?
A) To break DNA into small fragments
B) To create covalent bonds between DNA and proteins, preserving their interaction
C) To sequence DNA fragments
D) To remove unbound proteins from DNA
To create covalent bonds between DNA and proteins, preserving their interaction
In ChIP-Seq, the antibody used is specific for:
A) DNA sequences near promoters
B) Any chromatin-associated protein
C) The transcription factor of interest
D) RNA polymerase only
The transcription factor of interest
Which of the following best describes why DNA is fragmented in ChIP-Seq?
A) To enable the transcription factors to bind DNA
B) To create smaller, manageable pieces for immunoprecipitation and sequencing
C) To remove unbound DNA
D) To denature proteins
To create smaller, manageable pieces for immunoprecipitation and sequencin
n ChIP-Seq, after the DNA-protein complexes are isolated using antibodies, the crosslinks are _________ to release the DNA for sequencing.
reversed
The sequencing step in ChIP-Seq helps identify the exact _________ across the genome where the transcription factor binds.
DNA binding sites (or sequences)
True or False: ChIP-Seq can only identify binding sites that are close to gene promoters, not distant enhancers.
false
True or False: The antibody in ChIP-Seq pulls down all DNA fragments from the genome, regardless of whether they are bound to the transcription factor.
false
Which of the following best explains the role of antibodies in ChIP-Seq?
A) Antibodies digest the DNA not bound to transcription factors
B) Antibodies specifically bind to transcription factors to pull down DNA-protein complexes
C) Antibodies sequence the DNA fragments
D) Antibodies fragment the chromatin into smaller pieces
Antibodies specifically bind to transcription factors to pull down DNA-protein complexes
Crosslinking in ChIP-Seq is typically performed using:
A) Formaldehyde
B) DNase
C) Protease
D) Ethanol
Formaldehyde
The DNA sequences identified by ChIP-Seq represent the _________ of transcription factors across the genome.
binding sites
True or False: ChIP-Seq results can help identify enhancer sequences that regulate gene expression from a distance
true
True or False: In ChIP-Seq, the specificity of the antibody is crucial to avoid pulling down unrelated DNA fragments.
true
What is the main advantage of using ChIP-Seq over whole-genome sequencing when studying transcription factor binding?
A) ChIP-Seq sequences the entire genome faster
B) ChIP-Seq targets only DNA bound by specific proteins, reducing data complexity
C) Whole-genome sequencing identifies binding sites more precisely
D) ChIP-Seq does not require DNA fragmentation
ChIP-Seq targets only DNA bound by specific proteins, reducing data complexity
In ChIP-Seq data analysis, what do the “peaks” represent when mapped to the genome?
A) Regions of high DNA methylation
B) Transcription factor binding sites
C) Areas of DNA mutation
D) RNA polymerase binding sites
Transcription factor binding sites
Why are many short DNA reads generated in ChIP-Seq?
A) Because the DNA is sequenced as a continuous long molecule
B) Due to fragmentation of DNA before sequencing
C) Because only RNA is sequenced
D) To remove unbound DNA
Due to fragmentation of DNA before sequencing
In ChIP-Seq, after sequencing, the short DNA reads are ________ back to the reference genome to locate transcription factor binding sites.
mapped
The regions with the highest number of aligned reads in ChIP-Seq data are called ________, indicating protein-DNA interactions.
peaks
True or False: ChIP-Seq provides data on all DNA in the genome, including regions not bound by proteins.
false
True or False: The Illumina platform is commonly used in ChIP-Seq to generate short DNA reads for high-throughput sequencing.
true
In yeast, the genes GAL1, GAL7, and GAL10 are inducible. What does “inducible” mean in this context?
A) The genes are always transcribed at a constant level
B) The genes are transcribed only when galactose is present
C) The genes are permanently turned off
D) The genes are transcribed only during cell division
The genes are transcribed only when galactose is present
Which of the following is true about GAL1, GAL7, and GAL10 genes in yeast?
A) They are transcribed from a single promoter producing polycistronic mRNA
B) They are tightly linked but have separate promoters
C) They are located on different chromosomes
D) They are constitutively expressed regardless of galactose
They are tightly linked but have separate promoters
Why might yeast tightly regulate the expression of galactose metabolism genes?
A) To conserve energy by producing enzymes only when galactose is available
B) Because galactose is toxic to yeast cells
C) Because the enzymes are needed at all times
D) To prevent glucose metabolism
To conserve energy by producing enzymes only when galactose is available
The genes GAL1, GAL7, and GAL10 in yeast are examples of _______ gene expression because they are only turned on in the presence of ________.
inducible; galactose
Although GAL1, GAL7, and GAL10 are tightly linked, each gene has its own ________ which controls transcription initiation.
promoter
What role does GAL4 play in the regulation of galactose metabolism genes in yeast?
A) It represses transcription by binding to the operator
B) It acts as a transcriptional activator by binding to upstream activating sequences (enhancers)
C) It degrades galactose molecules
D) It transports galactose into the cell
It acts as a transcriptional activator by binding to upstream activating sequences (enhancers)
How does GAL80 regulate GAL4 activity in the absence of galactose?
A) GAL80 activates GAL4 to turn on transcription
B) GAL80 binds GAL4 and inhibits its ability to activate transcription
C) GAL80 degrades GAL4 protein
D) GAL80 binds DNA and blocks RNA polymerase directly
GAL80 binds GAL4 and inhibits its ability to activate transcription
What happens to GAL80 when galactose is present in the cell?
A) GAL80 binds more tightly to GAL4 to enhance activation
B) GAL3 binds GAL80, preventing GAL80 from entering the nucleus and inhibiting GAL4
C) GAL80 is degraded immediately
D) GAL80 binds DNA and represses GAL genes
GAL3 binds GAL80, preventing GAL80 from entering the nucleus and inhibiting GAL4
The transcriptional activator ________ binds to upstream activating sequences (enhancers) near the GAL genes to stimulate transcription.
GAL4
In the absence of galactose, the protein ________ binds to GAL4 and inhibits its ability to activate transcription.
GAL80
When galactose is present, ________ binds to GAL80, preventing GAL80 from entering the nucleus and thus allowing GAL4 to activate transcription.
GAL3
What happens to GAL80 protein in the absence of galactose?
A) GAL80 is degraded rapidly
B) GAL80 enters the nucleus and binds GAL4 to repress transcription
C) GAL80 remains in the cytoplasm and cannot repress transcription
D) GAL80 binds DNA directly to activate transcription
GAL80 enters the nucleus and binds GAL4 to repress transcription
Why does GAL80’s location within the cell influence transcriptional regulation?
A) Because GAL80 can only bind DNA when in the cytoplasm
B) Because transcription occurs inside the nucleus, so GAL80 must be nuclear to repress transcription
C) Because GAL80 can only be degraded in the cytoplasm
D) Because GAL80 activates GAL4 when in the cytoplasm
Because transcription occurs inside the nucleus, so GAL80 must be nuclear to repress transcription
What causes GAL80 to be sequestered in the cytoplasm?
A) Presence of galactose, via interaction with GAL3
B) Absence of galactose
C) Phosphorylation of GAL80 by kinases
D) Degradation of GAL4
Presence of galactose, via interaction with GAL3
True or False: The chemical modification and localization of regulatory proteins like GAL80 can control gene expression
true
true or False: Transcription of GAL genes occurs in the cytoplasm, so GAL80 represses gene expression only when in the cytoplasm.
false (Transcription occurs in the nucleus, so GAL80 must be nuclear to repress it.)
Explain how GAL80 regulates transcription differently in the presence versus absence of galactose.
In the absence of galactose, GAL80 enters the nucleus and binds to GAL4, blocking recruitment of the transcription initiation complex, repressing GAL gene expression. When galactose is present, GAL3 binds GAL80, sequestering it in the cytoplasm, preventing it from repressing GAL4. This allows GAL4 to activate transcription.
What is the purpose of reverse transcription in RNA sequencing?
A) To degrade RNA before sequencing
B) To convert RNA into DNA for more stable sequencing
C) To fragment DNA into smaller pieces
D) To add adaptors to DNA fragments
To convert RNA into DNA for more stable sequencing
Adaptors attached to DNA fragments during RNA-Seq serve all EXCEPT:
A) Helping primers bind during PCR
B) Acting as unique identifiers for samples
C) Preventing DNA from entering the sequencing machine
D) Allowing hybridization to the sequencing flow cell
Preventing DNA from entering the sequencing machine
True or False: RNA sequencing only tells us whether a gene is turned on or off, but not how much it is expressed.
false
True or False: Fragmentation of cDNA is an important step to create small pieces suitable for sequencing.
true
Why is RNA sequencing important?
tells us how many copies of each gene’s mRNA are present in a cell or tissue
This shows us which genes are active and how active they are
Purpose of DNA adaptors?
For hybridization purposes
As primers for PCR
As primers for sequencing reaction
As identifiers in subsequent bioinformatic analyses (data analysis to know which fragment came from which sample)
What is the role of the flowcell in sequencing by synthesis?
A) To amplify DNA fragments by PCR
B) To hold DNA fragments in place for sequencing
C) To chemically label nucleotides
D) To fragment DNA into smaller pieces
To hold DNA fragments in place for sequencing
Adaptors on DNA fragments are designed to:
A) Help the DNA fragments bind to the flowcell
B) Break the DNA into pieces
C) Convert RNA to DNA
D) Stop PCR amplification
Help the DNA fragments bind to the flowcell
True or False: Sequencing by synthesis adds nucleotides randomly to the DNA fragment.
false (Nucleotides are added one at a time, and the sequence is determined by detecting each added base.)
True or False: PCR amplification happens after the DNA fragments are attached to the flowcell.
false (PCR amplification happens before attaching fragments to the flowcell.)
What is the primary reason we use normalization like RPM in RNA-Seq data analysis?
A) To remove sequencing errors
B) To make sure reads are from exons only
C) To account for differences in total sequencing depth
D) To identify mutations in RNA
To account for differences in total sequencing depth
Which type of gene region do RNA-Seq reads most commonly align to?
A) Introns
B) Promoters
C) Exons and UTRs
D) Telomeres
Exons and UTRs
True or False: If one RNA-seq sample has twice the total number of reads as another, it will always show twice the expression for every gene.
false (Raw counts can be misleading if not normalized; expression depends on RPM or other normalized measures.)
True or False: RPM allows fair comparisons of gene expression across samples with different total read counts.
true
In RNA-seq, if a sample has 100 reads for a gene and the total number of reads in the library is 5 million, the RPM is: ___
20 RMP (100/5)
Sample A has 250 reads for Gene B and 10 million total reads. Sample B has 500 reads for Gene B and 25 million total reads.
What is the RPM of Gene B in each sample, and which sample has higher normalized expression?
Sample A: 250/10=25 RPM
Sample B: 500/25=20 RPM
Sample A has higher normalized expression.
You have two RNA-seq samples. Sample 1 has 300 reads for gene X out of 15 million total reads. Sample 2 has 600 reads for gene X out of 30 million total reads. What can you conclude about gene X after RPM normalization?
A. It is more active in Sample 1
B. It is more active in Sample 2
C. It is equally active in both samples
D. There is insufficient data to determine
It is equally active in both samples
RPM normalization divides raw read counts for a gene by:
A. The gene's length in kilobases
B. The total number of reads in the sample (in millions)
C. The number of exons in the gene
D. The number of samples in the experiment
The total number of reads in the sample (in millions)
Which of the following is not a limitation of RPM normalization?
A. It doesn’t account for gene length
B. It fails to adjust for library size differences
C. It doesn't handle compositional biases between samples
D. It may not distinguish between biological and technical variation
It fails to adjust for library size differences
In RNA-seq, a higher number of reads mapping to a gene generally indicates higher __________ of that gene.
expression