Cell biology lecture 21

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Kinetics

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23 Terms

1
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what determines rate of a reaction?

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what does Maxwell Boltzmann distribution describe?

  • distribution of molecule speeds in a gas or liquid​

  • Particles in a box can collide with each other or the box​

  • If we started them all with the same speed and let them equilibrate, collisions would transfer energy between particles and we get a distribution of speed​

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Probability distribution plot

  • Most molecules have similar speed​

  • A few have very high speed​

  • A few have very low speed​

<ul><li><p class="Paragraph WhiteSpaceCollapse SCXP189342718 BCX8" style="text-align: left;"><span style="line-height: 0px;"><span>Most molecules have similar speed​</span></span></p></li><li><p class="Paragraph WhiteSpaceCollapse SCXP189342718 BCX8" style="text-align: left;"><span style="line-height: 0px;"><span>A few have very high speed​</span></span></p></li><li><p class="Paragraph WhiteSpaceCollapse SCXP189342718 BCX8" style="text-align: left;"><span style="line-height: 0px;"><span>A few have very low speed​</span></span></p></li></ul><p class="Paragraph WhiteSpaceCollapse SCXP189342718 BCX8" style="text-align: left;"><span style="line-height: 0px;"><span>​</span></span></p>
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Distriibution plot with changes in mass or temp

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MB and particle kinetic energy distribution

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Why KE does not depend on particle mass?

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What determines a rate of reaction?

Three major factors:​

1. Temperature

Higher T​

  • Average kinetic energy increases​

  • more molecules exceed activation energy​

  1. (Enzymatic) catalysis​

Enzymes lower activation energy​

 More molecules exceed activation energy​

  1. Concentration

As concentration increases​

  • Same fraction of molecules have KE greater than activation energy​

  • But more molecules in total ​

 more molecules enough KE to react

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Rate of reaction reminder

Change in conc/time

<p>Change in conc/time </p><p></p>
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Reaction orders 

  • Consider reaction:​

A + B  C + D​

  • Rate of decrease of reactants given by:​

rate = k[A]x[B]y

  • x, y are orders of reaction with respect to A, B respectively​

  • Overall order of reaction is x+y​

  • k (rate constant) is dependent on temp 

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First order reactions

  • A FIRST ORDER reaction is one in which a single atom or molecule determinesthe rate​

rate = k [A]​

  • Eg radioactive decay:​

  • In a first order reaction: if we double the amount of A, the rate doubles​

<ul><li><p class="Paragraph WhiteSpaceCollapse SCXP198914318 BCX8" style="text-align: left;"><span style="line-height: 0px;"><span>A FIRST ORDER reaction is one in which a single atom or molecule determinesthe rate​</span></span></p></li></ul><p class="Paragraph WhiteSpaceCollapse SCXP198914318 BCX8" style="text-align: center;"><span style="line-height: 0px;"><span>rate = k [A]​</span></span></p><ul><li><p class="Paragraph WhiteSpaceCollapse SCXP198914318 BCX8" style="text-align: left;"><span style="line-height: 0px;"><span>Eg radioactive decay:​</span></span></p></li></ul><ul><li><p class="Paragraph WhiteSpaceCollapse  BCX8 SCXP249869298" style="text-align: left;"><span style="line-height: 0px;"><span>In a first order reaction: if we double the amount of A, the rate doubles​</span></span></p></li></ul><p></p>
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Second order reactions

  • When two molecules collide to determine the rate, the reaction is SECOND ORDER​

  • Consider reaction:​

A+A to B​

with rate = k[A]squared​

  • This reaction is second order w.r.t. A and overall​ second order

Or

  • Bimolecular interaction:​

A + B to C​

with rate = k[A][B]​

  • This reaction is first order w.r.t. A and B and second order overall​

<ul><li><p class="Paragraph WhiteSpaceCollapse SCXP84208626 BCX8" style="text-align: left;"><span style="line-height: 0px;"><span>When two molecules collide to determine the rate, the reaction is SECOND ORDER​</span></span></p></li><li><p class="Paragraph WhiteSpaceCollapse SCXP84208626 BCX8" style="text-align: left;"><span style="line-height: 0px;"><span>Consider reaction:​</span></span></p></li></ul><p class="Paragraph WhiteSpaceCollapse SCXP84208626 BCX8" style="text-align: center;"><span style="line-height: 0px;"><span>A+A to B​</span></span></p><p class="Paragraph WhiteSpaceCollapse SCXP84208626 BCX8" style="text-align: left;"><span style="line-height: 0px;"><span>with rate = k[A]squared​</span></span></p><ul><li><p class="Paragraph WhiteSpaceCollapse SCXP84208626 BCX8" style="text-align: left;"><span style="line-height: 0px;"><span>​</span></span></p></li><li><p class="Paragraph WhiteSpaceCollapse SCXP84208626 BCX8" style="text-align: left;"><span style="line-height: 0px;"><span>This reaction is second order w.r.t. A </span><strong><span>and </span></strong><span>overall​ second order </span></span></p></li></ul><p class="Paragraph WhiteSpaceCollapse SCXP84208626 BCX8" style="text-align: left;"></p><p class="Paragraph WhiteSpaceCollapse SCXP84208626 BCX8" style="text-align: left;">Or </p><ul><li><p class="Paragraph WhiteSpaceCollapse SCXP46615837 BCX8" style="text-align: left;"><span style="line-height: 0px;"><span>Bimolecular interaction:​</span></span></p></li></ul><p class="Paragraph WhiteSpaceCollapse SCXP46615837 BCX8" style="text-align: center;"><span style="line-height: 0px;"><span>A + B to C​</span></span></p><p class="Paragraph WhiteSpaceCollapse SCXP46615837 BCX8" style="text-align: left;"><span style="line-height: 0px;"><span>with rate = k[A][B]​</span></span></p><ul><li><p class="Paragraph WhiteSpaceCollapse SCXP46615837 BCX8" style="text-align: left;"><span style="line-height: 0px;"><span>​</span></span></p></li><li><p class="Paragraph WhiteSpaceCollapse SCXP46615837 BCX8" style="text-align: left;"><span style="line-height: 0px;"><span>This reaction is first order w.r.t. A and B </span><strong><span>and </span></strong><span>second order overall​</span></span></p></li></ul><p></p>
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how do we determine the order of a reaction?

Experimentally, determined by the slowest RATE LIMITING/DETERMINING step of a reaction

<p>Experimentally, determined by the slowest RATE LIMITING/DETERMINING step of a reaction </p>
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Order of reaction and rate limiting steps

  • So to get the reaction order we need to measure the rate​

  • Because there may well be intermediate steps in a reaction​

Famous biological example:​

  • Michaelis-Menten enzyme kinetics​

  • Rate limiting intermediate step​

<ul><li><p class="Paragraph WhiteSpaceCollapse SCXP205448680 BCX8" style="text-align: left;"><span style="line-height: 0px;"><span>So to get the reaction order we need to measure the rate​</span></span></p></li><li><p class="Paragraph WhiteSpaceCollapse SCXP205448680 BCX8" style="text-align: left;"><span style="line-height: 0px;"><span>Because there may well be intermediate steps in a reaction​</span></span></p></li></ul><p class="Paragraph WhiteSpaceCollapse SCXP205448680 BCX8" style="text-align: left;"><span style="line-height: 0px;"><span>​</span></span></p><p class="Paragraph WhiteSpaceCollapse SCXP205448680 BCX8" style="text-align: left;"><span style="line-height: 0px;"><span>​</span></span></p><p class="Paragraph WhiteSpaceCollapse SCXP205448680 BCX8" style="text-align: left;"><span style="line-height: 0px;"><span>Famous biological example:​</span></span></p><ul><li><p class="Paragraph WhiteSpaceCollapse SCXP205448680 BCX8" style="text-align: left;"><span style="line-height: 0px;"><span>Michaelis-Menten enzyme kinetics​</span></span></p></li><li><p class="Paragraph WhiteSpaceCollapse SCXP205448680 BCX8" style="text-align: left;"><span style="line-height: 0px;"><span>Rate limiting intermediate step​</span></span></p></li></ul><p></p>
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Equilibrium and equilibrium constant Kc

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why is Kc useful?

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Kc process 

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Why is Kc calculated without consideration of rate limiting steps and intermediates?

This is the equilibrium constant at equilibrium, so all the rates must balance (principle of detailed balance) so only the first and last states need to be considered. 

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Kc example Q

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Equilibrium constant biological example

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How do systems at equilibrium respond to perturbation?

  • If we add more reactant A or B, the system readjusts back towards equilibrium by making more product C + D​

  • If we add more product C or D, the system readjusts back towards equilibrium by making more product A + B​

  • Example of Le Chatelier’s principle:

When a system at equilibrium is subjected to disturbance, the composition of the system adjusts to minimize the disturbance

<ul><li><p class="Paragraph WhiteSpaceCollapse SCXP253040816 BCX8" style="text-align: left;"><span style="line-height: 0px;"><span>If we add more reactant A or B, the system readjusts back towards equilibrium by making more product C + D​</span></span></p></li><li><p class="Paragraph WhiteSpaceCollapse SCXP253040816 BCX8" style="text-align: left;"><span style="line-height: 0px;"><span>If we add more product C or D, the system readjusts back towards equilibrium by making more product A + B​</span></span></p></li><li><p class="Paragraph WhiteSpaceCollapse SCXP253040816 BCX8" style="text-align: left;"><span style="line-height: 0px;"><span>Example of Le Chatelier’s principle:</span></span></p></li></ul><p class="Paragraph WhiteSpaceCollapse SCXP253040816 BCX8" style="text-align: left;"><span style="line-height: 0px;"><em><span>When a system at equilibrium is subjected to disturbance, the composition of the system adjusts to minimize the disturbance</span></em><span>​</span></span></p><p class="Paragraph WhiteSpaceCollapse SCXP10752277 BCX8" style="text-align: center;"><span style="line-height: 0px;"><span>​</span></span></p><p></p>
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Free energy and equilibrium links 

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Free energy and equilibrium example *

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