1/20
Looks like no tags are added yet.
Name | Mastery | Learn | Test | Matching | Spaced |
---|
No study sessions yet.
Intermediate Value Theorem
If f is continuous on [a,b] then there must be a value “c” on (a,) such that f(c) is between f(a) and f(b)
Requirement for Intermediate Value Theorem
f must be continuous on [a,b]
Guarantee for Intermediate Value Theorem
a c on (a,b) where f(c) is between f(a) and f(b)
Squeeze Theorem
If h(x)≤f(x)≤g(x) for all x in an open interval containing “c” except possibly at c itself, then if lim x→c h(x) = L = lim x→c g(x) then lim x→c f(x) = L
Requirement for Squeeze Theorem
h(x)≤f(x)≤g(x)
lim x→c h(x) = L = lim x→c g(x)
Guarantee for Squeeze Theorem
lim x→c f(x) = L
Extreme Value Theorem
If f is continuous on [a,b], then f must attain at least one maximum and one minimum
Requirement for Extreme Value Theorem
f must be continuous on [a,b]
Guarantee for Extreme Value Theorem
f has one max and one min
Fundamental Theorem of Calculus
If f is continuous on [a,b] and F(x) is an anti-derivative of f(x) then a∫b f(x)dx = F(b) - F(a)
Requirement for Fundamental Theorem of Calculus
f is continuous on [a,b]
F is an anti-derivative of f
Guarantee of for Fundamental Theorem of Calculus
a∫b f(x)dx = F(b) - F(a) or a∫b f’(x)dx = f(b)-f(a)
2nd Fundamental Theorem of Calculus
If f is continuous on an open interval containing “a” then d/dx a∫g(x) f(t)dt - f(g(x)) * g’(x)
Requirement for 2nd Fundamental Theorem of Calculus
f is continuous on an open interval containing “a”
Guarantee for 2nd Fundamental Theorem of Calculus
d/dx a∫g(x) f(t)dt - f(g(x)) * g’(x)
Average Value of a Function
If f is continuous on [a,b] then there is a value c on (a,b) such that (b-a)f(c) = a∫bf(x)dx, where f(c) is the average value of f(x) on [a,b]
Requirement of Average Value Function
f is continuous on [a,b]
Guarantee of Average Value Function
the average value of f(x) on [a,b] = 1/(b-a) a∫bf(x)dx
Mean Value Theorem
if if is continuous on [a,b] and differentiable on (a,b) then there is a c on (a,b) such that f’(c) = f(b) - f(a)/ (b-a)
Requirement for Mean Value Theorem
f is continuous on [a,b]
Guarantee for Mean Value Theorem
a c on (a,b) where f’(c) = f(b) - f(a) / (b-a)