MATH - Calc Theorems

0.0(0)
studied byStudied by 6 people
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
Card Sorting

1/20

encourage image

There's no tags or description

Looks like no tags are added yet.

Study Analytics
Name
Mastery
Learn
Test
Matching
Spaced

No study sessions yet.

21 Terms

1
New cards

Intermediate Value Theorem

If f is continuous on [a,b] then there must be a value “c” on (a,) such that f(c) is between f(a) and f(b)

2
New cards

Requirement for Intermediate Value Theorem

f must be continuous on [a,b]

3
New cards

Guarantee for Intermediate Value Theorem

a c on (a,b) where f(c) is between f(a) and f(b)

4
New cards

Squeeze Theorem

If h(x)≤f(x)≤g(x) for all x in an open interval containing “c” except possibly at c itself, then if lim x→c h(x) = L = lim x→c g(x) then lim x→c f(x) = L

5
New cards

Requirement for Squeeze Theorem

h(x)≤f(x)≤g(x)

lim x→c h(x) = L = lim x→c g(x)

6
New cards

Guarantee for Squeeze Theorem

lim x→c f(x) = L

7
New cards

Extreme Value Theorem

If f is continuous on [a,b], then f must attain at least one maximum and one minimum

8
New cards

Requirement for Extreme Value Theorem

f must be continuous on [a,b]

9
New cards

Guarantee for Extreme Value Theorem

f has one max and one min

10
New cards

Fundamental Theorem of Calculus

If f is continuous on [a,b] and F(x) is an anti-derivative of f(x) then a∫b f(x)dx = F(b) - F(a)

11
New cards

Requirement for Fundamental Theorem of Calculus

f is continuous on [a,b]

F is an anti-derivative of f

12
New cards

Guarantee of for Fundamental Theorem of Calculus

a∫b f(x)dx = F(b) - F(a) or a∫b f’(x)dx = f(b)-f(a)

13
New cards

2nd Fundamental Theorem of Calculus

If f is continuous on an open interval containing “a” then d/dx a∫g(x) f(t)dt - f(g(x)) * g’(x)

14
New cards

Requirement for 2nd Fundamental Theorem of Calculus

f is continuous on an open interval containing “a”

15
New cards

Guarantee for 2nd Fundamental Theorem of Calculus

d/dx a∫g(x) f(t)dt - f(g(x)) * g’(x)

16
New cards

Average Value of a Function

If f is continuous on [a,b] then there is a value c on (a,b) such that (b-a)f(c) = a∫bf(x)dx, where f(c) is the average value of f(x) on [a,b]

17
New cards

Requirement of Average Value Function

f is continuous on [a,b]

18
New cards

Guarantee of Average Value Function

the average value of f(x) on [a,b] = 1/(b-a) a∫bf(x)dx

19
New cards

Mean Value Theorem

if if is continuous on [a,b] and differentiable on (a,b) then there is a c on (a,b) such that f’(c) = f(b) - f(a)/ (b-a)

20
New cards

Requirement for Mean Value Theorem

f is continuous on [a,b]

21
New cards

Guarantee for Mean Value Theorem

a c on (a,b) where f’(c) = f(b) - f(a) / (b-a)