Sequences and Series Review

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Vocabulary flashcards covering geometric series, the Fibonacci sequence formula, the golden ratio, harmonic sequences, and arithmetic sequences from the lecture notes.

Last updated 1:49 PM on 9/7/26
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12 Terms

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Finite Geometric Series Sum

The formula for calculating the sum of a finite geometric series, given as Sn=a1(rn1)r1S_n = \frac{a_1 (r^n - 1)}{r - 1}

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Infinite Geometric Series Sum

The formula for calculating the sum of an infinite geometric series, given as S=a11rS_\infty = \frac{a_1}{1 - r}

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Fibonacci Sequence Formula

An explicit formula for finding the nn-th term of the Fibonacci sequence, given as an=ϕn(1ϕ)n5a_n = \frac{\phi^n - (1 - \phi)^n}{\sqrt{5}}

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Golden Ratio (ϕ\phi)

A constant denoted by ϕ\phi, with the approximate value ϕ1.618\phi \approx 1.618

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Harmonic Sequence

A sequence of numbers whose reciprocals form an arithmetic sequence.

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Arithmetic Sequence General Term Formula

The formula for the nn-th term of an arithmetic sequence, given as an=a1+(n1)da_n = a_1 + (n - 1)d

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Finite Geometric Series Sum Example

For the series 5+15+45+1355 + 15 + 45 + 135, where a1=5a_1 = 5, r=3r = 3, and n=4n = 4: S4=5(341)31=5(811)2=200S_4 = \frac{5(3^4 - 1)}{3 - 1} = \frac{5(81 - 1)}{2} = 200

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Infinite Geometric Series Sum Example

For the infinite series 16+8+4+16 + 8 + 4 + \dots, where a1=16a_1 = 16 and r=12r = \frac{1}{2}: S=16112=160.5=32S_\infty = \frac{16}{1 - \frac{1}{2}} = \frac{16}{0.5} = 32

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Fibonacci Sequence Formula Example

To find the 2nd2\text{nd} term (n=2n = 2) using Binet's formula with ϕ1.618\phi \approx 1.618: a2=1.6182(11.618)25=2.6180.3822.236=1a_2 = \frac{1.618^2 - (1 - 1.618)^2}{\sqrt{5}} = \frac{2.618 - 0.382}{2.236} = 1

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Golden Ratio (ϕ\phi) Example

The ratio of consecutive Fibonacci terms approaches ϕ\phi; for example, 21131.615\frac{21}{13} \approx 1.615, which approximates ϕ1.618\phi \approx 1.618

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Harmonic Sequence Example

For the sequence {14,17,110,113}\{\frac{1}{4}, \frac{1}{7}, \frac{1}{10}, \frac{1}{13}\}, taking reciprocals gives the arithmetic sequence 4,7,10,134, 7, 10, 13 with common difference d=3d = 3

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Arithmetic Sequence General Term Example

For an arithmetic sequence starting at a1=7a_1 = 7 with common difference d=5d = 5, the 4th4\text{th} term is a4=7+(41)×5=22a_4 = 7 + (4 - 1) \times 5 = 22