Rate of change from graphs

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1
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<p>A student carries out an enzyme-controlled reaction. They measure how the mass of substrate mg changes over time.</p><p class="is-empty is-editor-empty has-focus"></p><p class="is-empty is-editor-empty has-focus">What should a graph of their results look like?</p>

A student carries out an enzyme-controlled reaction. They measure how the mass of substrate mg changes over time.

What should a graph of their results look like?

A

Explanation

When you draw a graph:

•The independent variable should be on the x-axis.

•The dependent variable should be on the y axis.

•The shape of the line of best fit depends on the trend shown by the data.

In this experiment:

•The independent variable is time.

•The dependent variable is the mass of the substrate.

•The trend shown by the data is linear, which means a straight line of best fit should be drawn.

2
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<p>Answer the question?</p>

Answer the question?

  1. 0.33

  2. B

To work out the units, substitute the y and x units into the same formula:

Rate of change units = change in y/change in x

Rate of change units = g dm*-3/s = g dm*-3 s*-1

<ol><li><p>0.33</p></li><li><p class="has-focus">B </p></li></ol><p class="has-focus">To work out the units, substitute the y and x units into the same formula:</p><p class="has-focus is-empty"></p><p class="has-focus is-empty"> Rate of change units =                    change in y/change in x</p><p class="is-empty has-focus">Rate of change units   = g dm*-3/s =                                                g dm*-3 s*-1</p><p class="is-empty has-focus"> </p><p class="is-empty has-focus"> </p><p class="is-empty has-focus"> </p><p class="is-empty has-focus"></p><p class="is-empty has-focus"> </p><p class="is-empty has-focus"></p><p class="is-empty has-focus">                                 </p><p class="is-empty has-focus"> </p><p class="is-empty has-focus"> </p><p class="is-empty has-focus"></p><p class="is-empty has-focus"></p><p class="is-empty has-focus"></p><p class="has-focus is-empty"> </p><p class="has-focus is-empty"></p><p class="has-focus is-empty"></p><p></p>
3
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<p>Answer the followung questions</p>

Answer the followung questions

  1. 0.03. 2. g/s or g s*-1

Explamation of q1 continued:

3.Calculate the change in y

2.2 - 1.1 = 1.1

4. Calculate the change in x

42 - 16 = 26

5. Change in y = 1.1, and change in

x = 26

Substitute these into the following formula:

Rate of change = change in x =

1.1/26 = 0.04230…

= 0.04 (2 d.p)

Q2 explamation:To work out the units, substitute the y and x units into the same formula:

Rate of change units =

change in y/ change in x

Rate of change units = g/s =

g s*-1

<ol><li><p>0.03.     2. g/s or g s*-1</p></li></ol><p class="has-focus">Explamation of q1 continued:</p><p class="has-focus">3.Calculate the change in y</p><p class="has-focus is-empty">2.2 - 1.1 = 1.1</p><p class="is-empty has-focus"></p><p class="has-focus is-empty">4. Calculate the change in x</p><p class="has-focus is-empty">42 - 16 = 26</p><p class="has-focus is-empty"></p><p class="has-focus is-empty"> 5. Change in y = 1.1, and change in </p><p class="has-focus is-empty">x = 26</p><p class="has-focus is-empty">Substitute these into the following formula: </p><p class="has-focus is-empty">Rate of change = change in x    = </p><p class="has-focus is-empty">1.1/26   = 0.04230…</p><p class="has-focus is-empty">               = 0.04 (2 d.p)</p><p></p><p class="has-focus is-empty">Q2 explamation:To work out the units, substitute the y and x units into the same formula:</p><p class="has-focus is-empty"></p><p class="has-focus is-empty"> Rate of change units = </p><p class="has-focus is-empty">change in y/ change in x</p><p class="has-focus is-empty"></p><p class="has-focus is-empty"> Rate of change units = g/s     = </p><p class="has-focus is-empty">g s*-1</p><p class="has-focus is-empty"> </p><p class="has-focus is-empty"></p><p class="has-focus is-empty"></p><p class="has-focus is-empty"></p>
4
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<p>Answer the question:</p>

Answer the question:

To predict what the concentration of the product will be at 60s, the student should extend the line of best fit. This is called extrapolation.